我做了这个MIPS问题,提示用户输入至少4个数字并按升序打印。我想知道是否有人可以看一看,告诉我你对它的看法?如果我也想让它以降序打印,我该如何开始呢?在我有真正的程序要做之前,这个程序只是为了好玩!
.data
array: .space 100
input: .asciiz "Enter at least 4 integers: Enter the number 1000 to exit \n"
output: .asciiz "The array in ascending order: \n"
commas: .asciiz ","
.text
.globl main
main:
la $a1, array   #loads a pointer to array into $a1
li $a2,9        #loads 9 into $a2
li $t0,0    
li $t1,1000     
loops:
la $a0, input   #loads input text into $a
li $v0, 4       #loads 4 into $v0 (prints string) 
syscall         
li $v0, 5       #loads 5 into $v0 (read interger)
syscall         
beq $v0,$t1,swap
addi $t0,$t0,4   #add 4 to $t0, save to $t0
sw $v0, ($a1)    #stores input into array
addi $a1, $a1,4  #add 4 to $a1, save to $a1
j loops
swap:
la $t4, array    #loads array to $t4
la $t1, array    #loads array to $t1
addi $t1,$t1,4   #add 4 to $t1, save to $t1 
la $t8,array     #loads array to $t8
add $t8,$t0,$t8  #add $t8 to $t0, save to $t8
la $t9,array
add $t9,$t0,$t9  #add $t9 to $t0, save to $t9
addi $t9,$t9,-4  #subtracts 4 from $t9, save to $t9
loop:
lw $t2,($t4)     #load input into $t2
lw $t3,($t1)     #load input into $t3
blt $t2,$t3,loop1 #if $t2 < $t3, go to loops
sw $t3,($t4)     #store $t3 in $t4
sw $t2,($t1)     #store $t2 in $t1
loop1:
addi $t1,$t1,4    #add 4 to $t1, save to $t1
blt $t1,$t8,loop  #if $t1<$t8, go to loop
addi $t4,$t4,4    #add 4 to $t4, save to $t4
move $t1,$t4
addi $t1,$t1,4    #add 4 to $t1, save to $t1
blt $t4,$t9,loop  #if $t4<$t9, to go loop
print:
la $a1,array      #loads array to $a1
la $a0, output    #loads output to $a0
li $v0, 4         #loads 4 into #v0
syscall
loop2:
blez $t0, done   #if $t0<=0, go to done
li $v0, 1        #loads 1 into $v0
lw $a0, 0($a1)   #load an inout into $a0
syscall
la $a0, commas    #loads commas into $a0
li $v0, 4        #loads 4 into $v0
syscall
addi $a1, $a1, 4  #add 4 to $a1, save to $a1
addi $t0, $t0, -4 #subtracts 4 from #t0, save to $t0
j loop2
done:
j done发布于 2014-04-16 19:46:27
方法一:
只需对数组进行降序排序。这应该是推荐的版本。
像大多数常见的排序一样,排序基于比较和交换方案。在代码中,它发生在label、loop和loop1中。因此,您只需更改第44行的比较部分:
blt $t2,$t3,loop1 #if $t2 < $t3, go to loops至:
bgt $t2,$t3,loop1 #if $t2 > $t3, go to loops然后结果看起来应该是下降的。
方法2.:
仍然对数组进行升序排序,同时反向打印数组。
打印部分位于label loop2,您需要像替换第68行一样对其进行更改:
lw $a0, 0($a1)   #load an inout into $a0通过以下方式:
add $t1, $a1, $t0
addi $t1, $t1, -4
lw $a0, 0($t1)   #load an inout into $a0还有注释第73行:
addi $a1, $a1, 4  #add 4 to $a1, save to $a1https://stackoverflow.com/questions/23107912
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