struct STATE{
uint8 bit;
uint8 cop;
}
STATE *state_array[1024];
state_aray[0]->bit = 8;
state_aray[0].cop = 8;
state_aray[1]->bit = 0;
state_aray[1].cop = state_aray[1]->bit & 8 != state_aray[0]->bit & 8
state_aray[2]->bit = 12;
state_aray[2].cop = state_aray[1]->bit & 8 != state_aray[0]->bit & 8 && state_aray[2]->bit & 8 != state_aray[1]->bit & 8
state_aray[3]->bit = 0;
state_aray[3].cop = state_aray[1]->bit & 8 != state_aray[0]->bit & 8 && state_aray[2]->bit & 8 != state_aray[1]->bit & 8 && state_aray[3]->bit & 8 != state_aray[2]->bit & 8
state_aray[4]->bit = 8;
state_aray[4].cop = ...
state_aray[5].cop = ... ...
...
state_aray[100].cop = ... ...... ......... ....... ......... ....... ...... ....... ............... ........ ...... ............ .... ......... ...... ..有没有办法只使用state_arayi-1->cop和state_arayi-1->bit和state_arayi->bit来获取state_arayi->cop?
tks
发布于 2011-05-12 09:23:35
行不通的。与OOP的" this“或"self”概念相反,C中没有“我是这个结构的成员”的机制。这就是为什么在C中,你只是简单地隐藏你的结构实现,并提供函数来改变你偷偷设置其他值的值。
STATE *create_state(void)
{
STATE *retval;
if( (retval = malloc(sizeof(STATE))) == NULL )
return NULL;
retval->cop = -1;
retval->bit = 0;
return retval;
}
void set_state(STATE *st, int val)
{
st->bit = val;
st->cop++;
}
int has_state_changed(STATE *st)
{
return st->cop;
}https://stackoverflow.com/questions/5972297
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