blocks|key|4546553|text|你的问题几乎可以用任何编程语言轻松解决……除Windows批处理外:(|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4546554|对于Windows批处理，如果文件长度超过8192字节，这几乎是不可能的，因为批处理变量限制为8192个字符。有一个复杂的方法，它使用FC+/B一次有效地读取一个字节，表示为十六进制。这将是相对容易的计数。但是，每个十六进制代码都需要转换回字符值。你不想经历所有的痛苦，除了可能的学术兴趣。|4546555|您可以使用PowerShell、VBScript或JScript轻松完成您想要的操作。|4546556|但是如果你想坚持使用批处理，那么你将需要一个非标准的实用工具来帮助你。|4546557|您可以下载一些免费的实用程序，它们会使解决方案变得微不足道。例如，Windows的sed可以很容易地解决这个问题。|4546558|该实用程序是纯脚本，可在XP及更高版本的任何Windows计算机上运行-无需下载exe。脚本中嵌入了REPL.BAT+is+available+here.完整文档。|offset|length|4546559|假设REPL.BAT在您的当前目录中，或者更好的是，在您的路径中的某个地方，那么下面的简单批处理脚本应该可以完成此任务。该脚本将要修改的文件的名称作为第一个也是唯一一个参数。文件等级库可以包含路径信息。如果文件包含空格或其他特殊字符，请确保用引号将文件括起来。|4546560|@echo+off
type+%251%7Crepl+"%5E.{240}(.*).{82}$"+"$1"%7Crepl+".{100}"+"$&\r\n"+x+>"%25~1.mod"
move+/y+"%25~1.mod"+%251+>nul|code-block|syntax|javascript|4546561|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/16735079/1012053^0|0|0|0|0|0|1E|R|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|13|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|14|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|15|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|16|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|17|8|@]|9|@$L|18|M|19|1|1A]]|A|$]]|$1|N|3|O|5|6|7|1B|8|@]|9|@]|A|$]]|$1|P|3|Q|5|R|7|1C|8|@]|9|@]|A|$S|T]]|$1|U|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]]]

Your problem is easily solved with nearly any programming language... except Windows batch :(

It is nearly impossible with Windows batch if your file is longer than 8192 bytes because batch variables are limited to 8192 characters. There is a complicated method that uses FC /B to effectively read one byte at a time, expressed as hex. It would be relatively easy to do the counting. But then each hex code would need to be converted back into the character value. You do not want to go through all that pain, except for maybe academic interest.

You could use PowerShell, VBScript, or JScript to easily do what you want.

But if you want to stick with batch, then you will need a non-standard utility to help you.

There are free utilities you could download that would make the solution trivial. For example, sed for Windows could make short work of this problem.

I have written a hybrid JScript/batch utility called REPL.BAT that performs regular expression search and replace on stdin, and writes the result to stdout. The utility is pure script that works on any Windows machine from XP onward - no exe download required. <a href="https://stackoverflow.com/a/16735079/1012053">REPL.BAT is available here.</a> Complete documentation is embedded within the script.

Assuming REPL.BAT is either in your current directory, or better yet, somewhere within your PATH, then the following simple batch script should do the trick. The script takes the name of the file to modify as the first and only argument. The file spec can include path information. Be sure to enclose the file in quotes if it contains spaces or other special characters.

<pre><code>@echo off
type %1|repl "^.{240}(.*).{82}$" "$1"|repl ".{100}" "$&amp;\r\n" x &gt;"%~1.mod"
move /y "%~1.mod" %1 &gt;nul
</code></pre>

blocks|key|4546563|text|如果可能的话，我强烈建议改用PowerShell，或者至少使用VBScript。用这些语言做你想做的事情会容易得多。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4546564|PowerShell：|4546565|$filename+=+'C:\path\to\your.txt'
(Get-Content+$filename+%7C+Out-String)+`
++++-replace+'%5E[\s\S]{240}',+''+`
++++-replace+'[\s\S]{82}$',''+`
++++-replace+'([\s\S]{100})',"`$1`r`n"+`
++%7C+Set-Content+$filename|code-block|syntax|javascript|4546566|VBScript：|4546567|filename+=+"C:\path\to\your.txt"

Set+fso+=+CreateObject("Scripting.FileSystemObject")
Set+re++=+New+RegExp
re.Global+=+True

txt+=+fso.OpenTextFile(filename).ReadAll

re.Pattern+=+"%5E[\s\S]{240}"
txt+=+re.Replace(txt,+"")
re.Pattern+=+"[\s\S]{82}$"
txt+=+re.Replace(txt,+"")
re.Pattern+=+"([\s\S]{100})"
txt+=+re.Replace(txt,+"$1"+&+vbNewLine)

fso.OpenTextFile(filename,+2).Write+txt|4546568|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I'd strongly recommend switching to PowerShell or at least VBScript if at all possible. It'd be a lot easier to do what you want with those languages.

PowerShell:

<pre><code>$filename = 'C:\path\to\your.txt'
(Get-Content $filename | Out-String) `
 -replace '^[\s\S]{240}', '' `
 -replace '[\s\S]{82}$','' `
 -replace '([\s\S]{100})',"`$1`r`n" `
 | Set-Content $filename
</code></pre>

VBScript:

<pre><code>filename = "C:\path\to\your.txt"

Set fso = CreateObject("Scripting.FileSystemObject")
Set re = New RegExp
re.Global = True

txt = fso.OpenTextFile(filename).ReadAll

re.Pattern = "^[\s\S]{240}"
txt = re.Replace(txt, "")
re.Pattern = "[\s\S]{82}$"
txt = re.Replace(txt, "")
re.Pattern = "([\s\S]{100})"
txt = re.Replace(txt, "$1" &amp; vbNewLine)

fso.OpenTextFile(filename, 2).Write txt
</code></pre>

Complete novice here so all help gratefully recieved. I am hoping to edit a text file with a batch file.

I have a text file that is all one line.
I need the first 240 characters deleted
I need the last 82 characters deleted
Finally, anything in between I need each 100 characters to be separated with a line break
Thanks
Mark

Need to edit a text file. Remove the start and then loop

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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完成新手在这里，让所有的帮助，感谢收到。我希望用批处理文件编辑一个文本文件。我有一个只有一行的文本文件。我需要删除前240个字符，我需要删除最后82个字符最后，之间的任何东西我需要每个100个字符被一个换行分隔谢谢马克

问需要编辑文本文件。删除start，然后再执行循环
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问需要编辑文本文件。删除start，然后再执行循环EN