问题:当我输入一个ID并按下按钮时,它不会加载ID的网页...
"a url“是我试图创建的网站页面,(隐藏的原因有很多)
它应该是工作的,它加载第一个站点,但当我尝试调用I时,WebView没有改变……谁能帮帮我?-Thanks,JG1
我的代码:
@Override
protected void onCreate(Bundle savedInstanceState) {
requestWindowFeature(Window.FEATURE_NO_TITLE);
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
wv.setWebViewClient(new OurViewClient());
wv.getSettings().setJavaScriptEnabled(true);
try {
String url = "a url";
wv.loadUrl(url);
} catch (Exception e) {
e.printStackTrace();
}
String lid = "0";
//Clicking button changes to the color
}
final EditText idbox = (EditText) findViewById(R.id.editText1);
final Button idbutton = (Button) findViewById(R.id.idbtn);
final WebView wv = (WebView) findViewById(R.id.webView1);
public void onClick(View v) {
idbutton.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
String lid = idbox.getText().toString();
if (lid == "1") {
wv.setWebViewClient(new OurViewClient());
try {
String urla = "a url";
wv.loadUrl(urla);
} catch (Exception e) {
e.printStackTrace();
}
}
if (lid == "2") {
wv.setWebViewClient(new OurViewClient());
try {
String urlb = "a url";
wv.loadUrl(urlb);
} catch (Exception e) {
e.printStackTrace();
}
}
if (lid == "3") {
wv.setWebViewClient(new OurViewClient());
try {
String urlc = "a url";
wv.loadUrl(urlc);
} catch (Exception e) {
e.printStackTrace();
}
}
}
});
}发布于 2014-03-09 00:59:08
我猜,您已经被称为相同的URL值,如(“url")。如果是,请尝试在web视图中加载不同的URL。
如果没有,请在代码中进行以下更改,
String lid = idbox.getText().toString();//检查lid is null or not
if(lid.equalsIgnoreCase("1")) {//用于呈现网页的任务}
https://stackoverflow.com/questions/22271693
复制相似问题