我知道Flask有int、float和path转换器,但我们正在开发的应用程序的URL中有更复杂的模式。
有没有办法可以像Django那样使用正则表达式?
发布于 2011-05-04 00:52:46
尽管Armin用一个公认的答案比我先了一步,但我认为我应该展示一个简短的示例,说明我如何在Flask中实现正则表达式匹配器,以防有人想知道如何实现它。
from flask import Flask
from werkzeug.routing import BaseConverter
app = Flask(__name__)
class RegexConverter(BaseConverter):
def __init__(self, url_map, *items):
super(RegexConverter, self).__init__(url_map)
self.regex = items[0]
app.url_map.converters['regex'] = RegexConverter
@app.route('/<regex("[abcABC0-9]{4,6}"):uid>-<slug>/')
def example(uid, slug):
return "uid: %s, slug: %s" % (uid, slug)
if __name__ == '__main__':
app.run(debug=True, host='0.0.0.0', port=5000)
此URL应返回200:http://localhost:5000/abc0-foo/
此URL应返回404:http://localhost:5000/abcd-foo/
发布于 2011-05-03 21:33:18
您可以挂接与任意表达式匹配的自定义转换器:Custom Converter
from random import randrange
from werkzeug.routing import Rule, Map, BaseConverter, ValidationError
class BooleanConverter(BaseConverter):
def __init__(self, url_map, randomify=False):
super(BooleanConverter, self).__init__(url_map)
self.randomify = randomify
self.regex = '(?:yes|no|maybe)'
def to_python(self, value):
if value == 'maybe':
if self.randomify:
return not randrange(2)
raise ValidationError()
return value == 'yes'
def to_url(self, value):
return value and 'yes' or 'no'
url_map = Map([
Rule('/vote/<bool:werkzeug_rocks>', endpoint='vote'),
Rule('/vote/<bool(randomify=True):foo>', endpoint='foo')
], converters={'bool': BooleanConverter})
发布于 2013-06-05 07:52:55
您还可以编写一个catch all类型的路由,并在该方法中执行复杂的路由:
from flask import Flask
app = Flask(__name__)
@app.route('/', methods=['GET', 'POST'], defaults={'path': ''})
@app.route('/<path:path>', methods=['GET', 'POST'])
def catch_all(path):
return 'You want path: %s' % path
if __name__ == '__main__':
app.run()
这将匹配任何请求。更多细节请看这里:Catch-All URL。
https://stackoverflow.com/questions/5870188
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