startForeground的错误通知(调用Recorder API 29)
startForeground的错误通知(调用Recorder API 29)
提问于 2020-01-20 23:01:31
我正在做一个通话记录器program.But，ACTION_NEW_OUTGOING_CALL权限从API29中删除，它给出这样的错误。我的目标，删除这个权限使用的代码，我该怎么做?我不想输入我们的输出信息。请帮帮我！
我的代码：
public void onReceive(Context context, Intent intent) {
String action = intent.getAction();
if (!action.equals(TelephonyManager.ACTION_PHONE_STATE_CHANGED) &&
!action.equals(Intent.ACTION_NEW_OUTGOING_CALL)) {
return;
}
String phoneNumber = intent.getStringExtra(Intent.EXTRA_PHONE_NUMBER);
String extraState = intent.getStringExtra(TelephonyManager.EXTRA_STATE);
Log.d(Constants.TAG, "PhoneReceiver phone number: " + phoneNumber);
if (!FileHelper.isStorageWritable(context))
return;
if (Intent.ACTION_NEW_OUTGOING_CALL.equals(intent.getAction())) {
App.isOutComming = true;
}
if (extraState != null) {
dispatchExtra(context, intent, phoneNumber, extraState);
} else if (phoneNumber != null) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
context.startForegroundService(new Intent(context, RecordService.class)
.putExtra("commandType", Constants.STATE_INCOMING_NUMBER)
.putExtra("phoneNumber", phoneNumber));
} else {
context.startService(new Intent(context, RecordService.class)
.putExtra("commandType", Constants.STATE_INCOMING_NUMBER)
.putExtra("phoneNumber", phoneNumber));
}
} else {
Log.d(Constants.TAG, "phone number x:x " + null);
}
}但是当我打开这个应用程序时，我看到了这个错误：
android.app.RemoteServiceException: Bad notification for startForeground: java.lang.RuntimeException: invalid channel for service notification: Notification(channel=null pri=0 contentView=null vibrate=null sound=null defaults=0x0 flags=0x40 color=0x00000000 number=0 vis=PRIVATE semFlags=0x0 semPriority=0 semMissedCount=0)回答 1
Stack Overflow用户
回答已采纳
发布于 2020-01-20 23:04:49
你应该为android.O创建通知通道
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
val importance = android.app.NotificationManager.IMPORTANCE_LOW
val mChannel = NotificationChannel(CHANNEL_ID, CHANNEL_NAME, importance)
mChannel.description = CHANNEL_DESCRIPTION
mChannel.enableLights(true)
mChannel.lightColor = Color.RED
mChannel.enableVibration(true)
val mNotificationManager =
context.getSystemService(Context.NOTIFICATION_SERVICE) as android.app.NotificationManager
mNotificationManager.createNotificationChannel(mChannel)
}在创建通知时，您应该给它提供通道id。
NotificationCompat.Builder(context, CHANNEL_ID)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/59825937
复制相关文章
相似问题
腾讯云开发者
