blocks|key|507683|text|在程序中将var1和var2初始化为零。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|507684|+if+(((var1%2Bvar2)+>=+0)+&&+((var1%2Bvar2)+<=+3000))+{+//+check+if+the+value+is+with+in+the+limits+

+++++++if(var1+>=+2900+&&+var1+<=2999)+//+check+if+reached+maximum+capacity

+++++++++++System.out.println("This+box+has+reached+its+maximum+capacity");

+++++++++++var1+=+var1+%2B+var2;+//+add+the+values+based+on+first+if+condition
+++++++++++}
+++++++++++else{
++++++++++++++++//+to+do+if+condition+fails
+++++++++++}|code-block|syntax|javascript|507685|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

initialize var1 and var2 to zero in your program.

<pre><code> if (((var1+var2) &gt;= 0) &amp;&amp; ((var1+var2) &lt;= 3000)) { // check if the value is with in the limits 

 if(var1 &gt;= 2900 &amp;&amp; var1 &lt;=2999) // check if reached maximum capacity

 System.out.println("This box has reached its maximum capacity");

 var1 = var1 + var2; // add the values based on first if condition
 }
 else{
 // to do if condition fails
 }
</code></pre>

blocks|key|507704|text|我会给你几个不同的选择，因为你的问题有点模糊。一种选择是用你的“给定数量”替换3000。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|507705|{
+++int+amtGiven+=+//however+you+obtained+this+value
+++if+(((var1%2Bvar2)+>=+0)+&&+((var1%2Bvar2)+<+amtGiven))+{+
++++++++++++++var1+=+var1+%2B+var2;

+++}
+++else{
++++++++System.out.println("This+box+has+reached+its+maximum+capacity");
+++}


}+|code-block|syntax|javascript|507706|同样，如果您想要将此内容添加到现有边界中：|507707|{
+++int+amtGiven+=+//however+you+obtained+this+value
+++if+(((var1%2Bvar2)+>=+amtGiven)+&&+((var1%2Bvar2)+<+amtGiven%2B3000))+{+
++++++++++++++var1+=+var1+%2B+var2;

+++}
+++else{
++++++++System.out.println("This+box+has+reached+its+maximum+capacity");
+++}


}|507708|返回到您的原始代码来解决您关于接近的问题，您应该探索条件分支的更多选项。在这种情况下，嵌套的if子句：|507709|{

+++if+(((var1%2Bvar2)+>=+0)+&&+((var1%2Bvar2)+<+3000))+{+

+++++++if(var1%2Bvar2+>=+2900){
++++++++++++System.out.println("This+box+is+getting+close+to+its+maximum+capacity")
+++++++}

++++++++++++++var1+=+var1+%2B+var2;

+++}
+++else{
++++++++System.out.println("This+box+has+reached+its+maximum+capacity");
+++}


}|507710|您还应该考虑is+var1%2Bvar2+<0的另一种情况，因为盒子还没有达到它的最大容量，因此对于您的程序来说是一个特例。|507711|编辑：|507712|根据你的评论，我认为你想要这样的东西：|507713|{
+++//this+assumes+maximumcapacity+was+defined+in+the+constructor.
+++if+(((var1%2Bvar2)+>=+0)+&&+((var1%2Bvar2)+<+maximumcapacity))+{+
++++++++++++++var1+=+var1+%2B+var2;

+++++++++//this+is+where+you+could+add+a+bit+for+getting+close+to+max+capacity,+see+above+example


+++}+
+++else{
++++++++System.out.println("This+box+has+reached+its+maximum+capacity");
+++}


}+|507714|如果你有更多的问题，欢迎编码和评论！|507715|entityMap^0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|14|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|16|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|17|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|18|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|W|3|X|5|6|7|1A|8|@]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|Z|$]]

I will present you with a couple different options since your question is sort of vague. One option is to replace 3000 with your "amount given"

<pre><code>{
 int amtGiven = //however you obtained this value
 if (((var1+var2) &gt;= 0) &amp;&amp; ((var1+var2) &lt; amtGiven)) { 
 var1 = var1 + var2;

 }
 else{
 System.out.println("This box has reached its maximum capacity");
 }


} 
</code></pre>

Similarly if you want to add this to existing bounds:

<pre><code>{
 int amtGiven = //however you obtained this value
 if (((var1+var2) &gt;= amtGiven) &amp;&amp; ((var1+var2) &lt; amtGiven+3000)) { 
 var1 = var1 + var2;

 }
 else{
 System.out.println("This box has reached its maximum capacity");
 }


}
</code></pre>

Jumping back to your original code to address your question about getting close, you should explore more options with conditional branching. In this case nested if clauses:

<pre><code>{

 if (((var1+var2) &gt;= 0) &amp;&amp; ((var1+var2) &lt; 3000)) { 

 if(var1+var2 &gt;= 2900){
 System.out.println("This box is getting close to its maximum capacity")
 }

 var1 = var1 + var2;

 }
 else{
 System.out.println("This box has reached its maximum capacity");
 }


}
</code></pre>

You should also consider an alternate case for is var1+var2 &lt; 0 as the box would not have reached its maximum capacity and thus is a special case for your program.

EDIT:

based on your comment, I think you want something to this effect:

<pre><code>{
 //this assumes maximumcapacity was defined in the constructor.
 if (((var1+var2) &gt;= 0) &amp;&amp; ((var1+var2) &lt; maximumcapacity)) { 
 var1 = var1 + var2;

 //this is where you could add a bit for getting close to max capacity, see above example


 } 
 else{
 System.out.println("This box has reached its maximum capacity");
 }


} 
</code></pre>

Happy coding and comment if you have more questions!

blocks|key|4483495|text|+++int+amt+=+var1+%2B+var2;+
+++if+(amt+>=+0+&&+amt+<+3000)+{++var1+%2B=+amt;++}
+++if(var1+>=+2900+&&+<=+2999)+{++System.out.println("near+cap.");+}
+++else+if(var1+>=+3000){+System.out.println("reached+max+cap.");+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4483496|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code> int amt = var1 + var2; 
 if (amt &gt;= 0 &amp;&amp; amt &lt; 3000) { var1 += amt; }
 if(var1 &gt;= 2900 &amp;&amp; &lt;= 2999) { System.out.println("near cap."); }
 else if(var1 &gt;= 3000){ System.out.println("reached max cap."); }
</code></pre>

Sorry that the question is vague, I wasn't quite sure how to best word it. I have the following code so far and it works, but I wanted it to still add the amount inputted by the user. For example if the initial amount given was 4000, I still want it to add the 3000 before telling the user that it has reached maximum capacity. 

<pre><code>{
 if (((var1+var2) &gt;= 0) &amp;&amp; ((var1+var2) &lt; 3000)) { 
 var1 = var1 + var2;

 }
 else{
 System.out.println("This box has reached its maximum capacity");
 }


} 
</code></pre>

In addition, how may I add a message telling the user that the box is nearly full, at say 2900-2999, but have it not be displayed when the box has reached its limit?

Thank you.

Java : How may I add to the counter up until the limit

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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很抱歉这个问题很含糊，我不太确定怎么说才好。到目前为止，我有以下代码，它可以工作，但我希望它仍然添加用户输入的数量。例如，如果给定的初始值是4000，我仍然希望它在告诉用户它已达到最大容量之前添加3000。{ if (((var1+var2) >= 0) && ((var1+var2) < 3000)) {...

问Java :我怎样才能将计数器加到最大值
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问Java :我怎样才能将计数器加到最大值EN