blocks|key|585674|text|如果模式数组只包含关键字而不包含模式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|585675|str+=+"foo+went+to+bar+with+abc+and+xyz"

pats+=+["abc","xyz","foo","bar"]
pats.all?+{+%7Ce%7C+str.include?(e)+}
#+=>+true

pats+=+["abc","xyz","foo","bar",+"no"]
pats.all?+{+%7Ce%7C+str.include?(e)+}
#+=>+false|code-block|syntax|javascript|585676|如果模式数组包含模式：|585677|pats+=+[/abc/,+/xyz$/,+/%5Efoo/,+/bar/]
pats.all?+{+%7Ce%7C+str+=~+e+}
#+=>+true

pats+=+[/abc/,+/xyz$/,+/%5Efoo/,+/bar/,+/no/]
pats.all?+{+%7Ce%7C+str+=~+e+}
#+=>+false|585678|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

If the pattern array contains only keywords and no patters:

<pre><code>str = "foo went to bar with abc and xyz"

pats = ["abc","xyz","foo","bar"]
pats.all? { |e| str.include?(e) }
# =&gt; true

pats = ["abc","xyz","foo","bar", "no"]
pats.all? { |e| str.include?(e) }
# =&gt; false
</code></pre>

If the pattern array contain patterns:

<pre><code>pats = [/abc/, /xyz$/, /^foo/, /bar/]
pats.all? { |e| str =~ e }
# =&gt; true

pats = [/abc/, /xyz$/, /^foo/, /bar/, /no/]
pats.all? { |e| str =~ e }
# =&gt; false
</code></pre>

blocks|key|586009|text|我的建议如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|586010|str+=+"I+have+an+array+of+paragraphs+and+an+array+of+keywords.+I+want+to+iterate+over+the+paragraphs+array+and+return+true+for+elements+that+include+all+of+my+keywords.+The+keywords+can+be+in+any+order,+but+all+of+them+must+be+found+in+the+same+paragraph+in+order+for+it+to+be+true,+not+just+some+of+them."|code-block|syntax|javascript|586011|编辑:我最初误解了这个问题。您可以对每个段落执行以下操作：|586012|words+=+%25w(have+iterate+true)+
(words+-+str.scan(/\w%2B/)).empty?
++#=>+true

words+=+%25w(have+iterate+cat)
(words+-+str.scan(/\w%2B/)).empty?
++#=>+false|586013|当我最初阅读问题时，我认为数组中的单词必须以相同的顺序出现在每个段落中。需要说明的是，我的解决方案具有这个额外的需求。|586014|words+=+%25w(have+iterate+true)+++
r+=+/\b#{words.join('\b.*?\b')}\b/
+++#=>+/\bhave\b.*?\biterate\b.*?\btrue\b/
str+=~+r+#=>+2+(a+match)

words+=+%25w(true+have+iterate)
r+=+/\b#{words.join('\b.*?\b')}\b/
str+=~+r+#=>+nil

words+=+%25w(have+iterate+true+false)+++
r+=+/\b#{words.join('\b.*?\b')}\b/
str+=~+r+#=>+nil|586015|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I suggest the following:

<pre><code>str = "I have an array of paragraphs and an array of keywords. I want to iterate over the paragraphs array and return true for elements that include all of my keywords. The keywords can be in any order, but all of them must be found in the same paragraph in order for it to be true, not just some of them."
</code></pre>

Edit: I initially misunderstood the question. You can just do the following for each paragraph: 

<pre><code>words = %w(have iterate true) 
(words - str.scan(/\w+/)).empty?
 #=&gt; true

words = %w(have iterate cat)
(words - str.scan(/\w+/)).empty?
 #=&gt; false
</code></pre>

When I initially read the question I thought the words in the array must appear in each paragraph in the same order. For the record, my solution with that additional requirement follows. 

<pre><code>words = %w(have iterate true) 
r = /\b#{words.join('\b.*?\b')}\b/
 #=&gt; /\bhave\b.*?\biterate\b.*?\btrue\b/
str =~ r #=&gt; 2 (a match)

words = %w(true have iterate)
r = /\b#{words.join('\b.*?\b')}\b/
str =~ r #=&gt; nil

words = %w(have iterate true false) 
r = /\b#{words.join('\b.*?\b')}\b/
str =~ r #=&gt; nil
</code></pre>

blocks|key|716081|text|我从来没有使用过Ruby，但我可以给你这里使用的逻辑。希望能有所帮助|type|unstyled|depth|inlineStyleRanges|entityRanges|data|716082|array_words
array_paragraphs
number_words+=+array_words
count+=0

foreach+para+(array_paragraph)
{
++++foreach+word+(array_word)
++++{
++++++++if+(para+=~+m/word/gi)
++++++++{
++++++++++++count%2B%2B
++++++++}
++++}
++++if+(count+==+number_words)
++++{
++++++++print+all+words+present+in+the+paragraph
++++}
++++count+=+0
}|code-block|syntax|javascript|716083|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I have never used Ruby but I can give you the logic to use here. Hope it helps

<pre><code>array_words
array_paragraphs
number_words = array_words
count =0

foreach para (array_paragraph)
{
 foreach word (array_word)
 {
 if (para =~ m/word/gi)
 {
 count++
 }
 }
 if (count == number_words)
 {
 print all words present in the paragraph
 }
 count = 0
}
</code></pre>

I have an array of paragraphs and an array of keywords. I want to iterate over the paragraphs array and return <code>true</code> for elements that include all of my keywords. The keywords can be in any order, but all of them must be found in the same paragraph in order for it to be <code>true</code>, not just some of them.

Is there a way I can do this using one <code>Regexp.union</code> or one regex, without <code>=~ regex1 &amp;&amp; =~ regex2 &amp;&amp; =~ regex3 &amp;&amp; =~ regex4</code> etc?

Check if string matches multiple substrings/regexes

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一组段落和一组关键字。我希望遍历段落数组，并为包含我所有关键字的元素返回true。关键字可以是任何顺序，但必须在同一段落中找到所有关键字，才能使其为true，而不仅仅是其中的一部分。有没有一种方法可以在没有=~ regex1 && =~ regex2 && =~ regex3 && =~ regex4的情况下使用一...

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