用于构建多层树的JSON
用于构建多层树的JSON
提问于 2015-04-27 21:18:40
我想像这样形成JSON：
{
"Schedule": [
{
"id": "A",
"name": "Summary",
"ischild": "1",
"level1": [
{
"id": "A.1",
"name": "A.1",
"ischild": "1",
"level2": [
{
"id": "A.1.a",
"name": "Income Statement",
"ischild": "0"
},
{
"id": "A.1.b",
"name": "Balance Sheet",
"ischild": "0"
},
{
"id": "A.1.c",
"name": "A.1.c",
"ischild": "1",
"level3": [
{
"id": "A.1.c.1",
"name": "General RWA",
"ischild": "0"
},
{
"id": "A.1.c.2",
"name": "Standardized RWA",
"ischild": "0"
},
{
"id": "A.1.c.3",
"name": "Advanced RWA",
"ischild": "0"
}
]
}
]
}
]
}
]
}但我的代码给出了以下输出：
{
"Schedule": [
{
"name": "Summary",
"ischild": "1",
"id": "A",
"N_LEVEL": "1"
},
{
"name": "A.1",
"ischild": "1",
"id": "A.1",
"N_LEVEL": "2"
},
{
"name": "Income Statement",
"ischild": "0",
"id": "A.1.a",
"N_LEVEL": "3"
},
{
"name": "Balance Sheet",
"ischild": "0",
"id": "A.1.b",
"N_LEVEL": "3"
},
{
"name": "A.1.c",
"ischild": "1",
"id": "A.1.c",
"N_LEVEL": "3"
},
{
"name": "General RWA",
"ischild": "0",
"id": "A.1.c.1",
"N_LEVEL": "4"
},
{
"name": "Standardized RWA",
"ischild": "0",
"id": "A.1.c.2",
"N_LEVEL": "4"
},
{
"name": "Advanced RWA",
"ischild": "0",
"id": "A.1.c.3",
"N_LEVEL": "4"
}
]
}下面是我的代码：
public static String getJSONFromResultSet(ResultSet rs,String keyName)
{
System.out.println(" in getJSONFromResultSet method");
Map json = new HashMap();
List list = new ArrayList();
if(rs!=null)
{
try
{
ResultSetMetaData metaData = rs.getMetaData();
while(rs.next())
{
Map<String,Object> columnMap = new HashMap<String, Object>();
for(int columnIndex=1;columnIndex<=metaData.getColumnCount();columnIndex++)
{
if(rs.getString(metaData.getColumnName(columnIndex))!=null)
columnMap.put(metaData.getColumnLabel(columnIndex),rs.getString(metaData.getColumnName(columnIndex)));
else
columnMap.put(metaData.getColumnLabel(columnIndex), "");
}
list.add(columnMap);
}
}
catch (SQLException e)
{
e.printStackTrace();
}
json.put(keyName, list);
}
return JSONValue.toJSONString(json);回答 1
Stack Overflow用户
发布于 2015-04-27 21:59:22
我认为你的目标结构可以更好，如果它的名称不会在每个级别上改变。级别编号是值，而不是密钥。ischild也没有任何意义，我认为这是isNotALeaf，这是可以解决的，所以把它也去掉，所以我们有：
{
"id": "A",
"name": "Summary",
"level": "1",
"children": [
{
"id": "A.1",
"name": "A.1",
"level": "2",
"children": [
{
"id": "A.1.a",
"name": "Income Statement",
"level": "3"
},
{
"id": "A.1.b",
"name": "Balance Sheet",
"level": "3"
}
]
}
}然后根据在GSon中使用的类生成一个自引用类：
package com.example;
import java.util.ArrayList;
import java.util.List;
import javax.annotation.Generated;
import com.google.gson.annotations.Expose;
@Generated("org.jsonschema2pojo")
public class Child {
@Expose
private String id;
@Expose
private String name;
@Expose
private String level;
@Expose
private List<Child> children = new ArrayList<Child>();
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getLevel() {
return level;
}
public void setLevel(String level) {
this.level = level;
}
public List<Child_> getChildren() {
return children;
}
public void setChildren(List<Child> children) {
this.children = children;
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/29896975
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