Spring - URI映射问题
Spring - URI映射问题
提问于 2015-05-25 16:11:51
我在我的应用程序上遇到了一个映射错误，任何帮助都将不胜感激！=)
错误消息:在名为'springapp‘的DispatcherServlet中找不到URI /springapp/priceincrease.htm的HTTP请求映射
你可以在下面找到一些代码：
PriceIncreaseFormController.java
@Controller
@RequestMapping(value="/priceincrease.htm")
public class PriceIncreaseFormController {
/** Logger for this class and subclasses */
protected final Log logger = LogFactory.getLog(getClass());
@Autowired
private ProductManager productManager;
@RequestMapping(method = RequestMethod.POST)
public String onSubmit(@Valid PriceIncrease priceIncrease, BindingResult result)
{
if (result.hasErrors()) {
return "priceincrease";
}
int increase = priceIncrease.getPercentage();
logger.info("Increasing prices by " + increase + "%.");
productManager.increasePrice(increase);
return "redirect:/hello.htm";
}
@RequestMapping(method = RequestMethod.GET)
protected PriceIncrease formBackingObject(HttpServletRequest request) throws ServletException {
PriceIncrease priceIncrease = new PriceIncrease();
priceIncrease.setPercentage(15);
return priceIncrease;
}
public void setProductManager(ProductManager productManager) {
this.productManager = productManager;
}
public ProductManager getProductManager() {
return productManager;
}
}app-config.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<bean id="productManager" class="com.companyname.springapp.service.SimpleProductManager">
<property name="products">
<list>
<ref bean="product1"/>
<ref bean="product2"/>
<ref bean="product3"/>
</list>
</property>
</bean>
<bean id="product1" class="com.companyname.springapp.domain.Product">
<property name="description" value="Lamp"/>
<property name="price" value="5.75"/>
</bean>
<bean id="product2" class="com.companyname.springapp.domain.Product">
<property name="description" value="Table"/>
<property name="price" value="75.25"/>
</bean>
<bean id="product3" class="com.companyname.springapp.domain.Product">
<property name="description" value="Chair"/>
<property name="price" value="22.79"/>
</bean>
<bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource">
<property name="basename" value="messages"/>
</bean>
<!-- Scans the classpath of this application for @Components to deploy as beans -->
<context:component-scan base-package="com.companyname.springapp.web" />
<!-- Configures the @Controller programming model -->
<mvc:annotation-driven/>
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property>
<property name="prefix" value="/WEB-INF/views/"></property>
<property name="suffix" value=".jsp"></property>
</bean>
</beans>web.xml
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<display-name>Springapp</display-name>
<servlet>
<servlet-name>springapp</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/app-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>springapp</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
</web-app>回答 2
Stack Overflow用户
发布于 2015-05-25 16:25:53
您忘记在应用程序上下文中添加处理程序映射：
<bean id="handlerMapping" class="org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping"/>Stack Overflow用户
发布于 2015-05-25 19:33:26
GET方法中有问题: formBackingObject。根据您的需求，它应该返回到视图或使其成为REST方法。
案例1:返回视图(JSP、HTML、XSLT...)
@RequestMapping(value="/priceincrease.htm",method = RequestMethod.GET)
protected String formBackingObject(HttpServletRequest request,Model model) throws ServletException {
PriceIncrease priceIncrease = new PriceIncrease();
priceIncrease.setPercentage(15);
model.addAttribute("priceIncrease",priceIncrease);
return "view_name";
}案例2:使用@ResponseBody的REST方法(jackson.core Jar是必需的)
@RequestMapping(value="/priceincrease.htm",method = RequestMethod.GET)
@ResponseBody
protected PriceIncrease formBackingObject(HttpServletRequest request) throws ServletException {
PriceIncrease priceIncrease = new PriceIncrease();
priceIncrease.setPercentage(15);
return priceIncrease;
}在这里，您已经为这两种情况修改了控制器的父映射(只需删除它
@Controller
public class PriceIncreaseFormController {
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/30433825
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