#include<iostream>
#include<thread>
using namespace std ;
void dowork(size_t s , size_t e, size_t *se )
{
for(size_t i = s ; i < e; i++)
se += i ;
}
int main(void)
{
int numthreads = std::thread::hardware_concurrency() ;
size_t start = 0 ;
size_t end = 12;
size_t chunk = (end - start + (numthreads - 1))/numthreads ;
cout<< chunk ;
std::thread t[numthreads] ;
size_t sum = 0 ;
for(int i = 0 ; i < numthreads ; i++ )
{
size_t s = start + i * chunk ;
size_t e = s + chunk ;
t[i] = std::thread(dowork, s, e, &sum) ;
}
for(int i = 0 ; i < numthreads ; i++)
t[i].join() ;
cout<<sum ;
}
我一直收到浮点异常。我尝试过数据类型Auto,size_t,double,float。我们的目标是展示循环的线程。简单的程序将0与12相加,并在内核之间分配工作。
发布于 2015-08-18 05:54:32
尝试更改:
size_t chunk = (end - start + (numthreads - 1))/numthreads ;
t0:
size_t chunk = (numthreads>0 ? (end - start + (numthreads - 1))/numthreads) : end - start)
https://stackoverflow.com/questions/32059980
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