spring-oxm:我能解组一个文件的子元素吗？
spring-oxm:我能解组一个文件的子元素吗？
提问于 2015-09-26 02:14:53
这与my prior question有关，后者通常更多地面向JAXB。但这个问题更多地与spring-oxm中的反编组程序相关。我想看看是否可以使用spring-oxm解组程序仅对XML中的特定元素进行解组。
我的XSD是：
<xs:schema version="1.3"
targetNamespace="https://www.domain.com/schema/reports/export/1.0"
xmlns:tns="https://www.domain.com/schema/reports/export/1.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
elementFormDefault="qualified">
<xs:element name="detailedreport">
<xs:complexType>
<xs:sequence>
<xs:element name="severity" minOccurs="6" maxOccurs="6" type="tns:SeverityType" />
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:complexType name="SeverityType">
<xs:sequence>
<xs:element name="category" minOccurs="0" maxOccurs="unbounded" type="tns:CategoryType"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="CategoryType">
<xs:sequence>
<xs:element name="cwe" maxOccurs="unbounded" type="tns:CweType"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="CweType">
<xs:sequence>
<xs:element name="staticflaws" type="tns:FlawListType" minOccurs="0"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="FlawListType">
<xs:sequence>
<xs:element name="flaw" minOccurs="0" maxOccurs="unbounded" type="tns:FlawType" />
</xs:sequence>
</xs:complexType>
</xs:schema>使用一些预处理，我可以找到“cwe”类型的所有节点：
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(IOUtils.toInputStream(xml));
NodeList nodeList = doc.getElementsByTagName("cwe");使用JAXBUnmarshaller，我可以设法解组我的对象：
JAXBContext jc = JAXBContext.newInstance( CweType.class );
Unmarshaller u = jc.createUnmarshaller();
u.unmarshal(new DOMSource(nodeList.item(0)), CweType.class);但是，如果我尝试使用spring-oxm unmarshaller的概念，我会得到一个错误。
Jaxb2Marshaller jaxb2Marshaller = new Jaxb2Marshaller();
jaxb2Marshaller.setClassesToBeBound(CweType.class);
jaxb2Marshaller.unmarshal(new DOMSource(nodeList.item(0)));
org.springframework.oxm.UnmarshallingFailureException: JAXB unmarshalling exception; nested exception is javax.xml.bind.UnmarshalException: unexpected element (uri:"", local:"cwe"). Expected elements are (none)
at org.springframework.oxm.jaxb.Jaxb2Marshaller.convertJaxbException(Jaxb2Marshaller.java:911)
at org.springframework.oxm.jaxb.Jaxb2Marshaller.unmarshal(Jaxb2Marshaller.java:784)
at org.springframework.oxm.jaxb.Jaxb2Marshaller.unmarshal(Jaxb2Marshaller.java:753)@M.Deinum在评论中建议尝试XPath，但我并不担心会有更好的-在解组时抛出相同的错误：
XPath xPath = XPathFactory.newInstance().newXPath();
NodeList xpnl = (NodeList)xPath.compile("//cwe").evaluate(doc, XPathConstants.NODESET);
jaxb2Marshaller.unmarshal(new DOMSource(xpnl.item(0)));我做错了什么？我创建DOMSource()的方式有问题吗？为什么我可以直接使用JAXBUnmarshaller解组，而不能使用Spring包装器？有没有什么方法可以通过spring-显式声明declaredType？
CweType.java：
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "CweType", propOrder = {
"description",
"staticflaws",
"dynamicflaws",
"manualflaws"
})
public class CweType {
@XmlElement(required = true)
protected CweType.Description description;
protected FlawListType staticflaws;
protected FlawListType dynamicflaws;
protected FlawListType manualflaws;
@XmlAttribute(name = "cweid", required = true)
@XmlSchemaType(name = "positiveInteger")
protected BigInteger cweid;
...
....回答 1
Stack Overflow用户
发布于 2016-04-25 21:42:28
public static CweType unmarshal(DOMSource node) throws JAXBException {
JAXBContext jaxbContext = JAXBContext.newInstance(CweType.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
JAXBElement<CweType> root = jaxbUnmarshaller.unmarshal(node, CweType.class);
CweType cweType= root.getValue();
LOGGER.info(cweType.toString());
return cweType;
}
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(IOUtils.toInputStream(xml));
NodeList nodeList = doc.getElementsByTagName("cwe");
CweType type = unmarshal(new DOMSource(nodeList.item(0));我希望这能对你有所帮助！
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原文链接：
https://stackoverflow.com/questions/32788288
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