如何在C++中找出一个字符串是否以另一个字符串结尾?
发布于 2009-05-17 08:34:05
只需使用std::string::compare比较最后n个字符
#include <iostream>
bool hasEnding (std::string const &fullString, std::string const &ending) {
if (fullString.length() >= ending.length()) {
return (0 == fullString.compare (fullString.length() - ending.length(), ending.length(), ending));
} else {
return false;
}
}
int main () {
std::string test1 = "binary";
std::string test2 = "unary";
std::string test3 = "tertiary";
std::string test4 = "ry";
std::string ending = "nary";
std::cout << hasEnding (test1, ending) << std::endl;
std::cout << hasEnding (test2, ending) << std::endl;
std::cout << hasEnding (test3, ending) << std::endl;
std::cout << hasEnding (test4, ending) << std::endl;
return 0;
}发布于 2010-01-15 23:59:35
使用此函数:
inline bool ends_with(std::string const & value, std::string const & ending)
{
if (ending.size() > value.size()) return false;
return std::equal(ending.rbegin(), ending.rend(), value.rbegin());
}发布于 2011-06-13 05:36:04
使用boost::algorithm::ends_with (例如参见http://www.boost.org/doc/libs/1_34_0/doc/html/boost/algorithm/ends_with.html ):
#include <boost/algorithm/string/predicate.hpp>
// works with const char*
assert(boost::algorithm::ends_with("mystring", "ing"));
// also works with std::string
std::string haystack("mystring");
std::string needle("ing");
assert(boost::algorithm::ends_with(haystack, needle));
std::string haystack2("ng");
assert(! boost::algorithm::ends_with(haystack2, needle));https://stackoverflow.com/questions/874134
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