blocks|key|5424757|text|查看Python+Recursive+Directory+Walker。简而言之，os.listdir()和os.walk()是您的朋友。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5424758|entityMap|0|LINK|mutability|MUTABLE|url|http://ssscripting.wordpress.com/2009/03/03/python-recursive-directory-walker/^0|2|X|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Checkout <a href="http://ssscripting.wordpress.com/2009/03/03/python-recursive-directory-walker/" rel="noreferrer">Python Recursive Directory Walker</a>. In short os.listdir() and os.walk() are your friends.

blocks|key|1895843|text|如果你想在当前目录中列出，你可以使用如下命令：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1895844|import+os

for+e+in+os.walk(os.getcwd()):
++++print+e|code-block|syntax|javascript|1895845|只需更改|1895846|os.getcwd()|1895847|添加到其他路径以在那里获得结果。|1895848|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

If You want to list in current directory, You can use something like:

<pre><code>import os

for e in os.walk(os.getcwd()):
 print e
</code></pre>

Just change the

<pre><code>os.getcwd()
</code></pre>

to other path to get results there.

blocks|key|5424770|text|import+os
import+os.path

for+dirpath,+dirnames,+filenames+in+os.walk("."):
++++for+filename+in+[f+for+f+in+filenames+if+f.endswith(".log")]:
++++++++print+os.path.join(dirpath,+filename)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|5424771|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>import os
import os.path

for dirpath, dirnames, filenames in os.walk("."):
 for filename in [f for f in filenames if f.endswith(".log")]:
 print os.path.join(dirpath, filename)
</code></pre>

blocks|key|4006337|text|您还可以将glob模块与os.walk一起使用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4006338|import+os
from+glob+import+glob

files+=+[]
start_dir+=+os.getcwd()
pattern+++=+"*.log"

for+dir,_,_+in+os.walk(start_dir):
++++files.extend(glob(os.path.join(dir,pattern)))+|code-block|syntax|javascript|4006339|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can also use the glob module along with os.walk.

<pre><code>import os
from glob import glob

files = []
start_dir = os.getcwd()
pattern = "*.log"

for dir,_,_ in os.walk(start_dir):
 files.extend(glob(os.path.join(dir,pattern))) 
</code></pre>

blocks|key|1895943|text|我有一个解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1895944|import+os
for+logfile+in+os.popen('find+.+-type+f+-name+*.log').read().split('\n')[0:-1]:
++++++print+logfile|code-block|syntax|javascript|1895945|或|1895946|import+subprocess
(out,+err)+=+subprocess.Popen(["find",+".",+"-type",+"f",+"-name",+"*.log"],+stdout=subprocess.PIPE).communicate()
for+logfile+in+out.split('\n')[0:-1]:
++print+logfile|1895947|这两个利用了find+.+-type+f+-name+*.log的优势。|offset|length|style|CODE|1895948|第一种方法更简单，但在添加-name+*.log时不能保证空格，但对于简单的find+../testdata+-type+f+(在我的OS环境中)工作得很好。|1895949|第二个使用子进程似乎更复杂，但这是空白安全的(同样，在我的OS环境中)。|1895950|这是受到Chris+Bunch的启发，在answer+https://stackoverflow.com/a/3503909/2834102|1895951|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/3503909/2834102^0|0|0|0|0|6|Q|0|D|B|12|O|0|0|R|17|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|18|8|@$M|19|N|1A|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1B|8|@$M|1C|N|1D|O|P]|$M|1E|N|1F|O|P]]|9|@]|A|$]]|$1|S|3|T|5|6|7|1G|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|1H|8|@]|9|@$M|1I|N|1J|1|1K]]|A|$]]|$1|W|3|-4|5|6|7|1L|8|@]|9|@]|A|$]]]|X|$Y|$5|Z|10|11|A|$12|13]]]]

I have a solution:

<pre><code>import os
for logfile in os.popen('find . -type f -name *.log').read().split('\n')[0:-1]:
 print logfile
</code></pre>

or

<pre><code>import subprocess
(out, err) = subprocess.Popen(["find", ".", "-type", "f", "-name", "*.log"], stdout=subprocess.PIPE).communicate()
for logfile in out.split('\n')[0:-1]:
 print logfile
</code></pre>

These two take the advantage of <code>find . -type f -name *.log</code>.

The first one is simpler but not guaranteed 
for white-space when add <code>-name *.log</code>, 
but worked fine for simply <code>find ../testdata -type f</code> 
(in my OS X environment).

The second one using subprocess seems more complicated, but this is the white-space safe one (again, in my OS X environment).

This is inspired by Chris Bunch, 
in the answer
<a href="https://stackoverflow.com/a/3503909/2834102">https://stackoverflow.com/a/3503909/2834102</a>

blocks|key|4006428|text|仅使用(嵌套)列表理解的单行解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4006429|import+os

path_list+=+[os.path.join(dirpath,filename)+for+dirpath,+_,+filenames+in+os.walk('.')+for+filename+in+filenames+if+filename.endswith('.log')]|code-block|syntax|javascript|4006430|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

A single line solution using only (nested) list comprehension:

<pre><code>import os

path_list = [os.path.join(dirpath,filename) for dirpath, _, filenames in os.walk('.') for filename in filenames if filename.endswith('.log')]
</code></pre>

blocks|key|5424896|text|使用标准库的pathlib|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5424897|from+pathlib+import+Path

working_dir+=+Path()
for+path+in+working_dir.glob("**/*.log"):
++++print(path)
++++#+OR+if+you+need+absolute+paths
++++print(path.absolute())
++++#+OR+if+you+need+only+filenames+without+extension+for+further+parsing
++++print(path.stem)|code-block|syntax|javascript|5424898|entityMap^0|6|7|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Using standard library's <code>pathlib</code>:
<pre><code>from pathlib import Path

working_dir = Path()
for path in working_dir.glob(&quot;**/*.log&quot;):
 print(path)
 # OR if you need absolute paths
 print(path.absolute())
 # OR if you need only filenames without extension for further parsing
 print(path.stem)
</code></pre>

I'm trying to get a list of all log files (.log) in directory, including all subdirectories.

How to get files in a directory, including all subdirectories

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在尝试获取目录中所有日志文件(.log)的列表，包括所有子目录。

问如何获取目录中的文件，包括所有子目录
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问如何获取目录中的文件，包括所有子目录EN