blocks|key|5465551|text|当您尝试使用[UIImage+imageNamed:myImage]加载图像，但iOS不确定myImage是否真的是NSString时，通常会出现此错误，然后您会收到以下警告。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5465552|您可以使用以下命令修复此问题：|5465553|[UIImage+imageNamed:[NSString+stringWithFormat:@"%25@",+myImage]]|code-block|syntax|javascript|5465554|或者，您可以简单地检查UIImage名称的length|5465555|if+(myImage+&&+[myImage+length])+{

++++[UIImage+imageNamed:myImage];
}|5465556|entityMap^0|6|S|1A|7|1M|8|0|0|0|B|7|L|6|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]]|D|@]|E|$]]|$1|O|3|P|5|J|7|16|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|R|$]]

This error (usually) happens when you try to load an image with <code>[UIImage imageNamed:myImage]</code> but iOS is not sure if <code>myImage</code> is really a <code>NSString</code> and then you have this warning.

You can fix this using:

<pre><code>[UIImage imageNamed:[NSString stringWithFormat:@"%@", myImage]]
</code></pre>

Or you can simply check for the <code>length</code> of the name of the <code>UIImage</code>:

<pre><code>if (myImage &amp;&amp; [myImage length]) {

 [UIImage imageNamed:myImage];
}
</code></pre>

blocks|key|5465601|text|由于错误提示您提供的名称是(null)，这很可能是由调用[UIImage+imageNamed:nil]引起的。或者更具体地说，传入的变量还没有设置，所以它等于nil。虽然使用stringWithFormat:可以消除错误，但我认为它很可能不会真正执行您想要的操作。如果您提供的名称是空值，则使用stringWithFormat:将导致它查找字面名称为“(+nil+)”的图像，就像您调用[UIImage+imageNamed:@"(null)"]一样。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5465602|像这样的东西可能是更好的选择：|5465603|if+(name)+{
++++UIImage+*image+=+[UIImage+imageNamed:name];
}+else+{
++++//+Do+something+else
}|code-block|syntax|javascript|5465604|您可能希望在Xcode中的“执行其他操作”行上设置一个断点，以帮助您弄清楚为什么这段代码一开始会以nil值调用。|5465605|entityMap^0|D|6|S|O|28|3|2G|H|4Z|3|5E|U|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|15|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|P|$]]

Since the error is complaining that the name you gave is <code>(null)</code>, this is most likely caused by calling <code>[UIImage imageNamed:nil]</code>. Or more specifically, passing in a variable hasn't been set, so it's equal to <code>nil</code>. While using <code>stringWithFormat:</code> would get rid of the error, I think there's a good chance it's not actually doing what you want. If the name you supply is a <code>nil</code> value, then using stringWithFormat: would result in it looking for an image that is literally named "(null)", as if you were calling <code>[UIImage imageNamed:@"(null)"]</code>.

Something like this is probably a better option:

<pre><code>if (name) {
 UIImage *image = [UIImage imageNamed:name];
} else {
 // Do something else
}
</code></pre>

You might want to set a breakpoint in Xcode on that "Do something else" line, to help you figure out why this code is getting called with a nil value in the first place.

blocks|key|1589577|text|我刚刚修复了这个错误。只需检查[UIImage+imageNamed:(NSString*)+imageName]函数的用法即可。如果imageName为nil，则会发生错误。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1589578|entityMap^0|F|16|1V|9|25|3|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|O|8|@]|D|@]|E|$]]]|G|$]]

I have just fixed this error. Just check the usage of the <code>[UIImage imageNamed:(NSString*) imageName]</code> function. If the <code>imageName</code> is <code>nil</code>, then error occurs.

blocks|key|1936855|text|当有人试图将nil放在[UIImage+imageNamed:]中时，就会出现这个错误|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1936856|为[UIImage+imageNamed:]添加符号断点|1936857|📷|atomic|1936858|在模拟器上添加$arg3+==+nil条件，在32位iPhone上添加$r0+==+nil条件，或在64位iPhone上添加$x2+==+nil条件。|1936859|运行您的应用程序并查看调试器将在何处停止。|1936860|附注:请记住，如果图像名称为空字符串，也会发生这种情况。您可以通过将[(NSString*)$x2+length]+==+0添加到条件来检查这一点。|1936861|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/06b5a05c9489c92e93a81dbc55f92ae0.png|imageAlt^0|6|3|B|L|0|1|L|0|0|1|0|0|7|C|Z|A|1Q|A|0|0|Y|S|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|K|3|L|5|6|7|1B|8|@$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|1I|8|@]|D|@]|E|$]]|$1|O|3|P|5|6|7|1J|8|@$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1M|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X|Y|-4]]]]

This one appears when someone is trying to put <code>nil</code> in <code>[UIImage imageNamed:]</code> 

Add symbolic breakpoint for <code>[UIImage imageNamed:]</code><img src="https://i.stack.imgur.com/ATz38.png" alt="Symbolic breakpoint example"> 

Add <code>$arg3 == nil</code> condition on Simulator, <code>$r0 == nil</code> condition on 32-bit iPhone, or <code>$x2 == nil</code> on 64-bit iPhone.

Run your application and see where debugger will stop.

P.S. Keep in mind this also happens if image name is empty string. You can check this by adding <code>[(NSString*)$x2 length] == 0</code> to the condition.

blocks|key|5465739|text|在我的例子中，我传递的是UIImage+imageNamed:@"“，这导致我显示警告。只需将断点添加到您使用过imageNamed的所有行，并调试您发现警告的行。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5465740|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

In my case i was passing [UIImage imageNamed:@""] which caused me to show the warning. Just add breakpoints to all the lines where you have used imageNamed and the debug the line where you find the warning.

blocks|key|1936955|text|在Xcode6.4中，当对情节提要中的选项卡栏项目使用"Selected+Image“时，即使它是一个有效的图像，也会发生这种情况。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1936956|​|1936957|📷|atomic|offset|length|1936958|1936959|实际上，这似乎并没有设置所选的状态图像，因此需要在用户定义的运行时属性中定义它，并从Tab+Bar项的SelectedImage属性中删除它|1936960|1936961|1936962|1936963|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/3d721176e225b4c158c441fac2b544f1.png|imageAlt|1|https://ask.qcloudimg.com/http-save/yehe-900000/04e024f4b5465a1b91d3684efce7d3f4.png^0|0|0|0|1|0|0|0|0|0|0|1|1|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|10|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|11|8|@]|9|@$G|12|H|13|1|14]]|A|$]]|$1|I|3|C|5|6|7|15|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|16|8|@]|9|@]|A|$]]|$1|L|3|C|5|6|7|17|8|@]|9|@]|A|$]]|$1|M|3|E|5|F|7|18|8|@]|9|@$G|19|H|1A|1|1B]]|A|$]]|$1|N|3|C|5|6|7|1C|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V|W|-4]]|X|$5|R|S|T|A|$U|Y|W|-4]]]]

In Xcode 6.4, this seems to occur when using "Selected Image" for a tab bar item in the storyboard, even if it's a valid image.

<a href="https://i.stack.imgur.com/TEad3.png" rel="noreferrer"><img src="https://i.stack.imgur.com/TEad3.png" alt="enter image description here"></a>

This doesn't actually seem to set the selected state image anyway, so it needs to be defined in User Defined Runtime Attributes, and removed from the SelectedImage attribute of the Tab Bar Item

<a href="https://i.stack.imgur.com/ehXry.png" rel="noreferrer"><img src="https://i.stack.imgur.com/ehXry.png" alt="enter image description here"></a>

blocks|key|1936978|text|错误的原因是将nil值传递给"imageNamed:“方法。为了避免这种情况，您可以在尝试传递nil值时隐藏您的imageView。这种机会可能发生在重用UITableView中的imageViews中，也可能发生在scrollViews中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1936979|我通过下面的检查避免了这个警告：|1936980|UIImageView+*your_image_view;
NSString+*imageName;
if(imageName+&&+imageName.length){
+your_image_view.hidden+=+NO;
+your_image_view.image+=+[UIImage+imageNamed:imageName];
}
else+{
+your_image_view.hidden+=+YES;
}|code-block|syntax|javascript|1936981|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The Reason to the error is passing a nil value to the "imageNamed:" method. To avoid this, you can hide your imageView when you try to pass the nil value. The chances may occur in reusing the imageViews in UITableView or may be in scrollViews.

I avoided the warning with the below check :

<pre><code>UIImageView *your_image_view;
NSString *imageName;
if(imageName &amp;&amp; imageName.length){
 your_image_view.hidden = NO;
 your_image_view.image = [UIImage imageNamed:imageName];
}
else {
 your_image_view.hidden = YES;
}
</code></pre>

blocks|key|5465816|text|当我使用[[UIImage+imageNamed:normalStr]+imageWithRenderingMode:UIImageRenderingModeAlwaysOriginal]加载图像时，我得到了这个警告，然后，我更改为[UIImage+imageNamed:normalStr]，警告消失了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5465817|entityMap^0|4|2I|38|U|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

I got this warning when I load image use <code>[[UIImage imageNamed:normalStr] imageWithRenderingMode:UIImageRenderingModeAlwaysOriginal]</code>, than, I change to <code>[UIImage imageNamed:normalStr]</code>, warning was gone.

blocks|key|1937004|text|一种方法是进行类方法转换，将[UIImage+imageNamed:]替换为您自己的实现，然后在您的实现中检查镜像名称。请参阅以下内容：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1937005|How+to+swizzle+a+class+method+on+iOS?|1937006|我在我的UIImage(调试)类别中实现了这一点：|1937007|%2B+(UIImage+*)db_imageNamed:(NSString+*)imageName+{
++++if+([imageName+length]+==+0)+{
++++++++NSLog(@"breakpoint+here");
++++}
++++return+[self+db_imageNamed:imageName];++//+not+a+recursive+call+here+after+swizzling
}|code-block|syntax|javascript|1937008|您可能也想要使用[UIImage+imageNamed:inBundle:compatibleWithTraitCollection:]。|1937009|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/3267506/how-to-swizzle-a-class-method-on-ios^0|E|L|0|0|11|0|0|0|0|8|1O|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@$9|12|A|13|1|14]]|E|$]]|$1|H|3|I|5|6|7|15|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|16|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1A|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]]]

One approach is do class method swizzling to replace <code>[UIImage imageNamed:]</code> with your own implementation, then check the image name in your implementation. See the following:

<a href="https://stackoverflow.com/questions/3267506/how-to-swizzle-a-class-method-on-ios">How to swizzle a class method on iOS?</a>

I implemented this in my UIImage(Debug) category:

<pre><code>+ (UIImage *)db_imageNamed:(NSString *)imageName {
 if ([imageName length] == 0) {
 NSLog(@"breakpoint here");
 }
 return [self db_imageNamed:imageName]; // not a recursive call here after swizzling
}
</code></pre>

You might want to swizzle <code>[UIImage imageNamed:inBundle:compatibleWithTraitCollection:]</code> as well.

blocks|key|5465832|text|您提供了一些无效的图像名称，因此在将其放入之前需要进行验证。您可以使用对代码有意义的任何一种方法或类似方法来执行上述操作|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5465833|if+(iconImageName+&&+[iconImageName+length])
{

++++[UIImage+imageNamed:iconImageName];
}
else
{
+++++iconImageName.hidden+=+YES;
}|code-block|syntax|javascript|5465834|希望它能有所帮助！|5465835|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You are supplying some invalid image name, so need to validate before putting it you can do any of the above ways whichever make sense for your code or like 

<pre><code>if (iconImageName &amp;&amp; [iconImageName length])
{

 [UIImage imageNamed:iconImageName];
}
else
{
 iconImageName.hidden = YES;
}
</code></pre>

Hope it will help!!!!

blocks|key|1937027|text|也许你可以用这个来确认"imageName“不是”nil“；然后你就可以忽略这个警告了。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1937028|+if+(imageName)+{
++++self.imageView.image+=+[UIImage+imageNamed:imageName];
+}|code-block|syntax|javascript|1937029|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Maybe you can use this to confirm the "imageName" is not a "nil";Then you will leave away this warning.

<pre><code> if (imageName) {
 self.imageView.image = [UIImage imageNamed:imageName];
 }
</code></pre>

blocks|key|4047516|text|这发生在我将一个故事板分成几个之后(实际的变化发生在我度假的时候，所以我不知道它是如何完成的)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4047517|在检查了序列图像板的XML之后，我发现之前在资产目录中指向"bottomBar“的图像引用指向了imageView:fFo-1g-jzs:image。|offset|length|style|CODE|4047518|在XML文件的末尾，<resources>标记下是一个名为<image+name="imageView:fFo-1g-jzs:image">的标记，其中包含一个很大的mutableData+blob。|4047519|在重置情节提要中的图像引用并删除blob之后，错误就消失了。|4047520|entityMap^0|0|1C|Q|0|A|B|T|15|2B|B|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@$D|P|E|Q|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|R|8|@$D|S|E|T|F|G]|$D|U|E|V|F|G]|$D|W|E|X|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|Y|8|@]|9|@]|A|$]]|$1|L|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|M|$]]

This happened to me after a storyboard was split into several (the actual change happened when I was on holidays, so I don't know exactly how it was done).

After inspecting the XML of the storyboards, I found that an image reference which previously had pointed to "bottomBar" in the assets catalogue instead pointed to <code>imageView:fFo-1g-jzs:image</code>.

At the end of the XML file under the <code>&lt;resources&gt;</code> tag was tag named <code>&lt;image name="imageView:fFo-1g-jzs:image"&gt;</code> containing a big <code>mutableData</code> blob.

After resetting the image reference in the storyboard and removing the blob, the error went away.

<pre><code>TableViewApplication[1458:70b] CUICatalog: Invalid asset name supplied: (null), or invalid scale factor: 2.000000
</code></pre>

<a href="https://i.stack.imgur.com/bqOpa.png" rel="noreferrer"><img src="https://i.stack.imgur.com/bqOpa.png" alt="Screenshot added"></a>

Getting this warning while working with TableViewController. How to rectify this error and which block is affected?

Error: CUICatalog: Invalid asset name supplied: (null), or invalid scale factor : 2.000000

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

TableViewApplication[1458:70b] CUICatalog: Invalid asset name supplied: (null), or invalid scale factor: 2.000000​​在使用TableViewController时收到此警告。如何纠正此错误?哪个块会受到影响...

问错误: CUICatalog:提供的资产名称无效：(null)，或比例因子无效: 2.000000
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问错误: CUICatalog:提供的资产名称无效：(null)，或比例因子无效: 2.000000EN