blocks|key|2143896|text|scanf需要格式(您的"%25d")和变量的内存地址，该变量应该将所读取的值放入其中。height和weight是int，而不是int的内存地址(这是int+*类型所说的:指向int内存地址的指针)。您应该使用运算符&将内存地址传递给scanf。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2143897|你的代码应该是：|2143898|printf("What+is+your+height+in+inches?\n");
scanf("%25d",+&height);

printf("What+is+your+weight+in+pounds?\n");
scanf("%25d",+&weight);|code-block|syntax|javascript|2143899|更新：正如顺磁翻译器指出的那样，引用不是正确的term.So，我将其更改为内存地址。|BOLD|2143900|entityMap^0|0|5|C|4|16|6|1D|6|1K|3|1R|3|22|5|2F|3|2Z|1|38|5|0|0|0|0|2|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1C|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1D|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1E|8|@$9|1F|A|1G|B|O]]|D|@]|E|$]]|$1|P|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|Q|$]]

<code>scanf</code> requires the format (your <code>"%d"</code>) and also a memory address of the variable where it should put the value that was read. <code>height</code> and <code>weight</code> are <code>int</code>, not the memory address of an <code>int</code> (this is what <code>int *</code> type 'says': a pointer to a memory address of an <code>int</code>). You should use the operator <code>&amp;</code> to pass the memory address to <code>scanf</code>.

Your code should be:

<pre><code>printf("What is your height in inches?\n");
scanf("%d", &amp;height);

printf("What is your weight in pounds?\n");
scanf("%d", &amp;weight);
</code></pre>

Update: As The Paramagnetic Croissant pointed out, reference is not the correct term.So I changed it to memory address.

blocks|key|5672966|text|scanf从标准输入中读取字符，根据这里的整数格式说明符"%25d"解释它们，并将它们存储在相应的参数中。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5672967|要存储它们，您必须指定&variable_name，它将指定应该存储输入的地址位置。|5672968|您的scanf语句应为：|5672969|//For+storing+value+of+height
scanf("+%25d",+&height);
//For+storing+value+of+weight
scanf("+%25d",+&weight);|code-block|syntax|javascript|5672970|entityMap^0|0|5|S|4|0|B|E|0|2|5|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|11|8|@]|D|@]|E|$M|N]]|$1|O|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|P|$]]

<code>scanf</code> reads characters from the standard input, interprets them according to the format specifiers here <code>"%d"</code> for integers and stores them in corresponding arguments.

To store them you must specify <code>&amp;variable_name</code>, it will specify the address location where the input should be stored.

Your <code>scanf</code> statement should be:

<pre><code>//For storing value of height
scanf(" %d", &amp;height);
//For storing value of weight
scanf(" %d", &amp;weight);
</code></pre>

blocks|key|2144010|text|考虑到其他用户已经说过的话，尝试这样做；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2144011|int+height;++++++++++++++++++<----+declaring+your+variables
int+weight;
float+bmi;+++++++++++++++++++<----+bmi+is+a+float+because+it+has+decimal+values

printf("What+is+your+height+in+inches?\n");
scanf("%25d",+&height);+++++++++++<-----+don't+forget+to+have+'&'+before+variable+you+are+storing+the+value+in

printf("What+is+your+weight+in+pounds?\n");
scanf("%25d",+&weight);


bmi+=+(weight+/+pow(height,+2))+*+703;++++<----+the+math+for+calculating+BMI
printf("The+BMI+is+%25f\n",+bmi);|code-block|syntax|javascript|2144012|(为此，您需要包含math.h库。)|2144013|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

taking into account what the other users have said, try something like this;

<pre><code>int height; &lt;---- declaring your variables
int weight;
float bmi; &lt;---- bmi is a float because it has decimal values

printf("What is your height in inches?\n");
scanf("%d", &amp;height); &lt;----- don't forget to have '&amp;' before variable you are storing the value in

printf("What is your weight in pounds?\n");
scanf("%d", &amp;weight);


bmi = (weight / pow(height, 2)) * 703; &lt;---- the math for calculating BMI
printf("The BMI is %f\n", bmi);
</code></pre>

(for this you will need to include the math.h library.)

blocks|key|4255270|text|正如其他人所说，这是因为当你有一个基元(如int)的值被scanf读取时，你必须将内存地址传递给那个基元值。然而，只是添加一些还没有提到的东西，字符串就不是这样了。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4255271|示例1.使用原始值|4255272|#include+<stdio.h>

int+main()
{
++++int+primitiveInteger;+//+integer+(i.e.+no+decimals+allowed)
++++scanf("%25i",+&primitiveInteger);+//+notice+the+address+of+operator+getting+the+address+of+the+primitiveInteger+variable+by+prepending+the+variable+name+with+the+&+(address+of)+operator.
++++printf("Your+integer+is+%25i",+primitiveInteger);+simply+printing+it+out+here+to+the+stdout+stream+(most+likely+your+terminal.)
}|code-block|syntax|javascript|4255273|示例2.不使用原始值|4255274|#include+<stdio.h>

int+main()
{
++++char+*nonPrimitiveString;+//+initialize+a+string+variable+which+is+NOT+a+primitive+in+C
++++scanf("%25s",+nonPrimitiveString);+//+notice+there+is+no+address+of+operator+here
++++printf("%25s\n",+nonPrimitiveString);+//+prints+string
}|4255275|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Like others have said, it's because when you have a value that is a primitive (like an int) that is being read with scanf you have to pass the memory address to that primitive value. However, just to add something that has not been mentioned yet, the same is not true for strings.
<h3>Example 1. Using with a primitive value</h3>
<pre><code>#include &lt;stdio.h&gt;

int main()
{
 int primitiveInteger; // integer (i.e. no decimals allowed)
 scanf(&quot;%i&quot;, &amp;primitiveInteger); // notice the address of operator getting the address of the primitiveInteger variable by prepending the variable name with the &amp; (address of) operator.
 printf(&quot;Your integer is %i&quot;, primitiveInteger); simply printing it out here to the stdout stream (most likely your terminal.)
}
</code></pre>
<h3>Example 2. Not using a primitive value</h3>
<pre><code>#include &lt;stdio.h&gt;

int main()
{
 char *nonPrimitiveString; // initialize a string variable which is NOT a primitive in C
 scanf(&quot;%s&quot;, nonPrimitiveString); // notice there is no address of operator here
 printf(&quot;%s\n&quot;, nonPrimitiveString); // prints string
}
</code></pre>

Creating a code that prints out Body Mass Index 

<pre><code>printf("What is your height in inches?\n");
scanf("%d", height);

printf("What is your weight in pounds?\n");
scanf("%d", weight);
</code></pre>

I have height and weight as initialized as <code>int height</code>, <code>int weight</code>, but the program is not letting me run it because it says the format is type <code>int*</code> on both <code>scanf</code> lines. What am I doing wrong to get this program to run?

Format specifies type "int*" but argument has type "int"

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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创建一个打印身体质量指数的代码printf("What is your height in inches?\n");scanf("%d", height);printf("What is your weight in pounds?\n");scanf("%d", weight);我有初始化为int height，in...

问Format指定类型"int*“，但参数的类型为"int”
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问Format指定类型"int*“，但参数的类型为"int”EN