blocks|key|5865144|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5865145|+${string:position:length}|blockquote|5865146|5865147|从位于$position的$string中提取子串的$length字符。|offset|length|style|CODE|5865148|stringZ=abcABC123ABCabc+#+0123456789.....基于#0的索引。echo+${stringZ:0}+#+abcABC123ABCabc+echo+${stringZ:1}+#+bcABC123ABCabc+echo+${stringZ:7}+#+23ABCabc+echo+${stringZ:7:3}+#+23A+#三个字符的子串。|5865149|5865150|--来自Mendel+Cooper的《高级Bash脚本指南》中的|5865151|然后使用循环遍历并在位置上加1，以提取每个长度为5的子串。|5865152|end=$((+${#stringZ}+-+5+))
for+i+in+$(seq+0+$end);+do
++++echo+${stringZ:$i:5}
done|code-block|syntax|javascript|5865153|entityMap^0|0|0|0|3|9|D|7|Q|7|0|0|0|0|0|0^^$0|@$1|2|3|-4|4|5|6|Y|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|Z|7|@]|8|@]|9|$]]|$1|D|3|-4|4|5|6|10|7|@]|8|@]|9|$]]|$1|E|3|F|4|5|6|11|7|@$G|12|H|13|I|J]|$G|14|H|15|I|J]|$G|16|H|17|I|J]]|8|@]|9|$]]|$1|K|3|L|4|5|6|18|7|@]|8|@]|9|$]]|$1|M|3|-4|4|5|6|19|7|@]|8|@]|9|$]]|$1|N|3|O|4|5|6|1A|7|@]|8|@]|9|$]]|$1|P|3|Q|4|5|6|1B|7|@]|8|@]|9|$]]|$1|R|3|S|4|T|6|1C|7|@]|8|@]|9|$U|V]]|$1|W|3|-4|4|5|6|1D|7|@]|8|@]|9|$]]]|X|$]]

<blockquote>
<pre><code>${string:position:length}
</code></pre>
Extracts <code>$length</code> characters of substring from <code>$string</code> at
<code>$position</code>.
<pre><code>stringZ=abcABC123ABCabc
# 0123456789.....
# 0-based indexing.

echo ${stringZ:0} # abcABC123ABCabc
echo ${stringZ:1} # bcABC123ABCabc
echo ${stringZ:7} # 23ABCabc

echo ${stringZ:7:3} # 23A
 # Three characters of substring.
</code></pre>
</blockquote>
-- from <a href="http://tldp.org/LDP/abs/html/string-manipulation.html" rel="nofollow noreferrer">Manipulating Strings</a> in the Advanced Bash-Scripting Guide by Mendel Cooper
Then use a loop to go through and add 1 to the position to extract each substring of length 5.
<pre><code>end=$(( ${#stringZ} - 5 ))
for i in $(seq 0 $end); do
 echo ${stringZ:$i:5}
done
</code></pre>

blocks|key|2336422|text|sed可以在一次操作中完成：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2336423|$+echo+"abcdefghijklmnopqr"%7Csed+-r+'s/(.{5})/\1+/g'
abcde+fghij+klmno+pqr|code-block|syntax|javascript|2336424|或|2336425|取决于您的需求：|2336426|$+echo+"abcdefghijklmnopqr"%7Csed+-r+'s/(.{5})/\1\n/g'+
abcde
fghij
klmno
pqr|2336427|更新|offset|length|style|BOLD|2336428|我认为这只是一个简单的字符串分裂问题，没有仔细阅读问题。现在，它应该提供您需要的内容：|2336429|仍然只有一次机会，但这次使用awk：|2336430|$+echo+"abcdefghijklmnopqr"%7Cawk+'{while(length($0)>=5){print+substr($0,1,5);gsub(/%5E./,"")}}'

abcde
bcdef
cdefg
defgh
efghi
fghij
ghijk
hijkl
ijklm
jklmn
klmno
lmnop
mnopq
nopqr|2336431|entityMap^0|0|0|0|0|0|0|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|13|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|15|8|@$O|16|P|17|Q|R]]|9|@]|A|$]]|$1|S|3|T|5|6|7|18|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|19|8|@]|9|@]|A|$]]|$1|W|3|X|5|D|7|1A|8|@]|9|@]|A|$E|F]]|$1|Y|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|Z|$]]

sed can do it in one shot:
<pre><code>$ echo &quot;abcdefghijklmnopqr&quot;|sed -r 's/(.{5})/\1 /g'
abcde fghij klmno pqr
</code></pre>
or
depends on your needs:
<pre><code>$ echo &quot;abcdefghijklmnopqr&quot;|sed -r 's/(.{5})/\1\n/g' 
abcde
fghij
klmno
pqr
</code></pre>
update
i thought it was just simply split string problem, didn't read the question very carefully. Now it should give what you need:
still one shot, but with awk this time:
<pre><code>$ echo &quot;abcdefghijklmnopqr&quot;|awk '{while(length($0)&gt;=5){print substr($0,1,5);gsub(/^./,&quot;&quot;)}}'

abcde
bcdef
cdefg
defgh
efghi
fghij
ghijk
hijkl
ijklm
jklmn
klmno
lmnop
mnopq
nopqr
</code></pre>

blocks|key|2336489|text|fold+-w5应该可以做到这一点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2336490|$+echo+"ABCDEFGHIJKLMNOPQRSTUVWXYZ"+%7C+fold+-w5
ABCDE
FGHIJ
KLMNO
PQRST
UVWXY
Z|code-block|syntax|javascript|2336491|干杯!|2336492|entityMap^0|0|8|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

<code>fold -w5</code> should do the trick.

<pre><code>$ echo "ABCDEFGHIJKLMNOPQRSTUVWXYZ" | fold -w5
ABCDE
FGHIJ
KLMNO
PQRST
UVWXY
Z
</code></pre>

Cheers!

blocks|key|2336468|text|...or使用split命令：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2336469|$+ls

$+echo+"abcdefghijklmnopqr"+%7C+split+-b5

$+ls
xaa++xab++xac++xad

$+cat+xaa
abcde|code-block|syntax|javascript|2336470|split还可以对文件进行操作...|2336471|entityMap^0|7|5|0|0|0|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

...or use the <code>split</code> command:

<pre><code>$ ls

$ echo "abcdefghijklmnopqr" | split -b5

$ ls
xaa xab xac xad

$ cat xaa
abcde
</code></pre>

<code>split</code> also operates on files...

blocks|key|5865250|text|在bash中：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5865251|s=ABCDEFGHIJ
for+((+i=0;+i+<+${#s}-4;+i%2B%2B+));+do+
++printf+">%25d\n%25s\n"+$((i%2B1))+${s:$i:5}
done|code-block|syntax|javascript|5865252|输出|5865253|>1
ABCDE
>2
BCDEF
>3
CDEFG
>4
DEFGH
>5
EFGHI
>6
FGHIJ|5865254|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

In bash:

<pre><code>s=ABCDEFGHIJ
for (( i=0; i &lt; ${#s}-4; i++ )); do 
 printf "&gt;%d\n%s\n" $((i+1)) ${s:$i:5}
done
</code></pre>

outputs

<pre><code>&gt;1
ABCDE
&gt;2
BCDEF
&gt;3
CDEFG
&gt;4
DEFGH
&gt;5
EFGHI
&gt;6
FGHIJ
</code></pre>

blocks|key|5865170|text|str=ABCDEFGHIJKLM
splitfive(){+echo+"${1:$2:5}"+;+}
for+((+i=0+;+i+<+${#str}+;+i%2B%2B+))+;+do+splitfive+"$str"+$i+;+done|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|5865171|或者，您可能想要对结果做一些更智能的处理|unstyled|5865172|#!/usr/bin/env+bash

splitstr(){
++++printf+'%25s\n'+"${1:$2:$3}"
}

n=$1
offset=$2

declare+-a+by_fives

while+IFS=+read+-r+str+;+do
++++for+((+i=0+;+i+<+${#str}+;+i%2B%2B+))+;+do
++++++++++++by_fives=("${by_fives[@]}"+"$(splitstr+"$str"+$i+$n)")
++++done
done

echo+${by_fives[$offset]}|5865173|然后把它叫做|5865174|$+split-by+5+2+<<<"ABCDEFGHIJKLM"
CDEFG|5865175|您可以从那里对其进行调整。|5865176|编辑:+C语言的普通版本，用于性能比较：|5865177|#include+<stdio.h>

int+main(void){
++++FILE*+f;
++++int+n=0;
++++char+five[6];

++++five[5]+=+'\0';

++++f+=+fopen("inputfile",+"r");

++++if(f!=0){
++++++++++++fread(&five,+sizeof(char),+5,+f);
++++++++++++while(!feof(f)){
++++++++++++++++++++printf("%25s\n",+five);
++++++++++++++++++++fseek(f,+%2B%2Bn,+SEEK_SET);

++++++++++++++++++++fread(&five,+sizeof(char),+5,+f);
++++++++++++}
++++}

++++return+0;
}|5865178|请原谅我糟糕的C语言，我真的不懂这门语言。|5865179|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|X|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|Z|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$B|C]]|$1|M|3|N|5|F|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|12|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$B|C]]|$1|S|3|T|5|F|7|14|8|@]|9|@]|A|$]]|$1|U|3|-4|5|F|7|15|8|@]|9|@]|A|$]]]|V|$]]

<pre><code>str=ABCDEFGHIJKLM
splitfive(){ echo "${1:$2:5}" ; }
for (( i=0 ; i &lt; ${#str} ; i++ )) ; do splitfive "$str" $i ; done
</code></pre>

Or, perhaps you want to do something more intelligent with the results

<pre><code>#!/usr/bin/env bash

splitstr(){
 printf '%s\n' "${1:$2:$3}"
}

n=$1
offset=$2

declare -a by_fives

while IFS= read -r str ; do
 for (( i=0 ; i &lt; ${#str} ; i++ )) ; do
 by_fives=("${by_fives[@]}" "$(splitstr "$str" $i $n)")
 done
done

echo ${by_fives[$offset]}
</code></pre>

And then call it

<pre><code>$ split-by 5 2 &lt;&lt;&lt;"ABCDEFGHIJKLM"
CDEFG
</code></pre>

You can adapt it from there.

EDIT: trivial version in C, for performance comparison:

<pre><code>#include &lt;stdio.h&gt;

int main(void){
 FILE* f;
 int n=0;
 char five[6];

 five[5] = '\0';

 f = fopen("inputfile", "r");

 if(f!=0){
 fread(&amp;five, sizeof(char), 5, f);
 while(!feof(f)){
 printf("%s\n", five);
 fseek(f, ++n, SEEK_SET);

 fread(&amp;five, sizeof(char), 5, f);
 }
 }

 return 0;
}
</code></pre>

Forgive my bad C, I really don't knw the language.

blocks|key|2336445|text|sed会这样做吗？：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2336446|$+sed+'s/$.....$/\1\n/g'+<+filecontaininghugestring|code-block|syntax|javascript|2336447|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Would sed do it?:

<pre><code>$ sed 's/$.....$/\1\n/g' &lt; filecontaininghugestring
</code></pre>

blocks|key|2336476|text|sed可以做到这一点：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2336477|+sed+-nr+':a;h;s/(.{5}).*/\1/p;g;s/.//;ta;'+<<<"ABCDEFGHIJKLM"+%7C+#+split+string
+++++sed+'='+%7C+sed+'1~2s/%5E/>/'+#+add+line+numbers+and+insert+'>'|code-block|syntax|javascript|2336478|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

sed can do it:

<pre><code> sed -nr ':a;h;s/(.{5}).*/\1/p;g;s/.//;ta;' &lt;&lt;&lt;"ABCDEFGHIJKLM" | # split string
 sed '=' | sed '1~2s/^/&gt;/' # add line numbers and insert '&gt;'
</code></pre>

blocks|key|5865261|text|您可以使用cut并指定characters而不是字段，然后将输出分隔符更改为您需要的任何内容，如换行符：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|BOLD|entityRanges|data|5865262|echo+"ABCDEFGHIJKLMNOP"+%7C+cut+--output-delimiter=$'\n'+-c1-5,6-10,11-15|code-block|syntax|javascript|5865263|输出|5865264|ABCDE
FGHIJ
KLMNO|5865265|或|5865266|echo+"ABCDEFGHIJKLMNOP"+%7C+cut+--output-delimiter=$':'+-c1-5,6-10,11-15+|5865267|5865268|ABCDE:FGHIJ:KLMNO|5865269|entityMap^0|5|3|B|A|O|2|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|D]|$9|13|A|14|B|D]]|E|@]|F|$]]|$1|G|3|H|5|I|7|15|8|@]|E|@]|F|$J|K]]|$1|L|3|M|5|6|7|16|8|@]|E|@]|F|$]]|$1|N|3|O|5|I|7|17|8|@]|E|@]|F|$J|K]]|$1|P|3|Q|5|6|7|18|8|@]|E|@]|F|$]]|$1|R|3|S|5|I|7|19|8|@]|E|@]|F|$J|K]]|$1|T|3|M|5|6|7|1A|8|@]|E|@]|F|$]]|$1|U|3|V|5|I|7|1B|8|@]|E|@]|F|$J|K]]|$1|W|3|-4|5|6|7|1C|8|@]|E|@]|F|$]]]|X|$]]

You could use <code>cut</code> and specify characters instead of fields, and then change output delimiter to whatever you need, like new line:
<pre><code>echo &quot;ABCDEFGHIJKLMNOP&quot; | cut --output-delimiter=$'\n' -c1-5,6-10,11-15
</code></pre>
output
<pre><code>ABCDE
FGHIJ
KLMNO
</code></pre>
or
<pre><code>echo &quot;ABCDEFGHIJKLMNOP&quot; | cut --output-delimiter=$':' -c1-5,6-10,11-15 
</code></pre>
output
<pre><code>ABCDE:FGHIJ:KLMNO
</code></pre>

blocks|key|2336534|text|多亏了你们，我才能找到一种快速完成此任务的方法！这是我的解决方案，结合了这里的一些想法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2336535|str="ABCDEFGHIJKLMNOP"+++
splitfive(){
++++echo+$1+%7C+cut+-c+$2-+%7C+sed+-r+'s/(.{5})/\1\n/g'
}++
for+((+i=0;+i+<=+5;+i%2B%2B+));+do
++++splitfive+"$str"+$i
done+%7C+grep+-v+"%5E$"|code-block|syntax|javascript|2336536|2336537|上述答案最初是添加到问题本身中的。以下是相关评论。|2336538|2336539|你的splitfive可以更有效率。不需要通过管道来剪切，在bash中你可以说cut+-c+"$2"-+<<<"$1"+%7C+sed等，这样会稍微好一点。--+sorpigal+Sep+28+'11+at+11:48您的sed表达式还可以改进为sed+'s/...../&\n/g'，其执行速度大约快一倍。--+sorpigal+Sep+28+'11+at+11:56|blockquote|offset|length|style|CODE|2336540|2336541|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/users/180736/sorpigal|1^0|0|0|0|0|0|2|9|13|Q|3D|J|27|8|0|4B|8|1|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|13|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|14|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|15|8|@]|9|@]|A|$]]|$1|K|3|L|5|M|7|16|8|@$N|17|O|18|P|Q]|$N|19|O|1A|P|Q]|$N|1B|O|1C|P|Q]]|9|@$N|1D|O|1E|1|1F]|$N|1G|O|1H|1|1I]]|A|$]]|$1|R|3|-4|5|6|7|1J|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]|10|$5|V|W|X|A|$Y|Z]]]]

thanks to you guys I was able to find a way to do this fast! This is my solution combining a few ideas from here:
<pre><code>str=&quot;ABCDEFGHIJKLMNOP&quot; 
splitfive(){
 echo $1 | cut -c $2- | sed -r 's/(.{5})/\1\n/g'
} 
for (( i=0; i &lt;= 5; i++ )); do
 splitfive &quot;$str&quot; $i
done | grep -v &quot;^$&quot;
</code></pre>
<hr />
[The above answer was initially added to the question itself. Here are the relevant comments.]
<blockquote>
Your <code>splitfive</code> could be more efficient. There's no need to pipe to cut, in bash you could say <code>cut -c &quot;$2&quot;- &lt;&lt;&lt;&quot;$1&quot; | sed</code> etc and it will be slightly better. -- <a href="https://stackoverflow.com/users/180736/sorpigal">sorpigal</a> Sep 28 '11 at 11:48
</blockquote>
<blockquote>
Your sed expression could also be improved to <code>sed 's/...../&amp;\n/g'</code> which executes about twice as fast. -- <a href="https://stackoverflow.com/users/180736/sorpigal">sorpigal</a> Sep 28 '11 at 11:56
</blockquote>

I have a huge string like
<pre class="lang-none prettyprint-override"><code>ABCDEFGHIJKLM...
</code></pre>
and I would like to split it into substrings of length 5 in this way:
<pre class="lang-none prettyprint-override"><code>&gt;1
ABCDE
&gt;2
BCDEF
&gt;3
CDEFG
[...]
</code></pre>

Split large string into substrings

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一根很大的线，比如ABCDEFGHIJKLM...我想用这种方式把它分成长度为5的子串：>1ABCDE>2BCDEF>3CDEFG[...]

问将大字符串拆分成子字符串
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问将大字符串拆分成子字符串
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