blocks|key|4743244|text|http://abcoder.com/javascript/a-better-process-to-find-maximum-z-index-within-a-page/+->找到最大z索引并将%2B1赋值给它。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4743245|entityMap|0|LINK|mutability|MUTABLE|url|http://abcoder.com/javascript/a-better-process-to-find-maximum-z-index-within-a-page/^0|0|2D|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

<a href="http://abcoder.com/javascript/a-better-process-to-find-maximum-z-index-within-a-page/" rel="nofollow">http://abcoder.com/javascript/a-better-process-to-find-maximum-z-index-within-a-page/</a> -> find the max z-index and assign +1 to it.

blocks|key|2629996|text|下面是如何做的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2629997|var+elements+=+document.getElementsByTagName("*");
var+highest_index+=+0;

for+(var+i+=+0;+i+<+elements.length+-+1;+i%2B%2B)+{
++++if+(parseInt(elements[i].style.zIndex)+>+highest_index)+{
++++++++highest_index+=+parseInt(elements[i].style.zIndex;
++++}
}|code-block|syntax|javascript|2629998|highest_index现在包含页面上最高的z索引...只需将该值加1，并将其应用到您想要应用到的任何位置。您可以像这样应用它：|2629999|your_element.style.zIndex+=+highest_index+%2B+1;|2630000|下面是使用jQuery实现相同功能的另一种方法：|2630001|var+highest_index+=+0;

$("[z-index]").each(function()+{
++++if+($(this).attr("z-index")+>+highest_index)+{
+++++++++highest_index+=+$(this).attr("z-index");
++++}
});|2630002|同样，将新索引应用于元素的方法也是相同的：|2630003|$("your_element").attr("z-index",+highest_index+%2B+1);|2630004|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

Here's how to do it :

<pre><code>var elements = document.getElementsByTagName("*");
var highest_index = 0;

for (var i = 0; i &lt; elements.length - 1; i++) {
 if (parseInt(elements[i].style.zIndex) &gt; highest_index) {
 highest_index = parseInt(elements[i].style.zIndex;
 }
}
</code></pre>

highest_index now contains the highest z-index on the page... just add 1 to that value and apply it wherever you want. You can apply it like so :

<pre><code>your_element.style.zIndex = highest_index + 1;
</code></pre>

Here's another way of achieving the same thing using jQuery :

<pre><code>var highest_index = 0;

$("[z-index]").each(function() {
 if ($(this).attr("z-index") &gt; highest_index) {
 highest_index = $(this).attr("z-index");
 }
});
</code></pre>

Again, same way to apply the new index to an element :

<pre><code>$("your_element").attr("z-index", highest_index + 1);
</code></pre>

blocks|key|4743290|text|Sheavi的索引解决方案不起作用，因为z-+jQuery是一种css样式，而不是属性。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4743291|试着这样做：|4743292|raiseToHighestZindex+=+function(elem)+{
++++var+highest_index+=+0;
++++$("*").each(function()+{
++++++++var+cur_zindex=+$(this).css("z-index");
++++++++if+(cur_zindex+>+highest_index)+{
++++++++++++highest_index+=+cur_zindex;
++++++++++++$(elem).css("z-index",+cur_zindex+%2B+1);
++++++++}
++++});
++++return+highest_index;
};+|code-block|syntax|javascript|4743293|由于Javascript的异步特性，返回值可能不是您所期望的，但在任何元素上调用函数都可以很好地工作。|4743294|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Sheavi's jQuery solution doesn't work because z-index is a css style, not an attribute.

Try this instead:

<pre><code>raiseToHighestZindex = function(elem) {
 var highest_index = 0;
 $("*").each(function() {
 var cur_zindex= $(this).css("z-index");
 if (cur_zindex &gt; highest_index) {
 highest_index = cur_zindex;
 $(elem).css("z-index", cur_zindex + 1);
 }
 });
 return highest_index;
}; 
</code></pre>

Return value may not be what you expect due to Javascript's async nature, but calling the function on any element will work fine.

blocks|key|25060|text|那么堆叠上下文呢？在文档上，最高的z索引将在顶部，这是而不是总是正确的。请参阅：http://philipwalton.com/articles/what-no-one-told-you-about-z-index/如果您不考虑堆叠上下文，设置十亿可能不足以使您的元素位于最上面。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|25061|entityMap|0|LINK|mutability|MUTABLE|url|http://philipwalton.com/articles/what-no-one-told-you-about-z-index/^0|R|3|14|1W|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@$9|O|A|P|B|C]]|D|@$9|Q|A|R|1|S]]|E|$]]|$1|F|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]]]

What about stacking context? It is not always true that: On a document highest z-index will be on top. See: <a href="http://philipwalton.com/articles/what-no-one-told-you-about-z-index/" rel="nofollow">http://philipwalton.com/articles/what-no-one-told-you-about-z-index/</a>. If you do not take stacking context into account, setting a billion may not be enough to make your element on the top-most.

I would like to make an element (e.g. a <code>&lt;div&gt;</code>) be the top-most layer on the page.

My assumption is that the only way I can do this is to specify that the element has a <code>style="z-index:"</code> value that is the maximum the browser allows (int32?).

Is this correct?

Instead, would it be possible to somehow get the element's <code>z-index</code> whose is highest, and make this <code>&lt;div&gt;</code>'s <code>z-index</code> the <code>[highest element's value] + 1</code>? For example:

<pre><code>$myDiv.css("z-index", $(document.body).highestZIndex() + 1);
</code></pre>

How do modal JavaScript "windows" work?

CSS/JavaScript: Make element top-most z-index/top-most modal element

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想让一个元素(例如<div>)成为页面的最顶层。我的假设是，我能做到这一点的唯一方法是指定元素的style="z-index:"值是浏览器允许的最大值(int32?)。这是正确的吗？相反，是否有可能以某种方式获得元素的最高z-index，并将此<div>的z-index设置为[highest element's va...

问CSS/JavaScript:使元素位于最顶部的z索引/最顶部的模式元素
EN

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