Spring Hibernate集成错误
Spring Hibernate集成错误
提问于 2014-06-21 18:44:28
当我试图在一个独立的应用程序中集成spring和hibernate时，我收到了以下错误。
Exception in thread "main" org.springframework.dao.InvalidDataAccessApiUsageException: Write operations are not allowed in read-only mode (FlushMode.MANUAL): Turn your Session into FlushMode.COMMIT/AUTO or remove 'readOnly' marker from transaction definition.
at org.springframework.orm.hibernate4.HibernateTemplate.checkWriteOperationAllowed(HibernateTemplate.java:1135)
at org.springframework.orm.hibernate4.HibernateTemplate$12.doInHibernate(HibernateTemplate.java:620)
at org.springframework.orm.hibernate4.HibernateTemplate$12.doInHibernate(HibernateTemplate.java:617)
at org.springframework.orm.hibernate4.HibernateTemplate.doExecute(HibernateTemplate.java:340)
at org.springframework.orm.hibernate4.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:308)
at org.springframework.orm.hibernate4.HibernateTemplate.save(HibernateTemplate.java:617)
at CarDAO.insert(CarDAO.java:38)
at CarTest.main(CarTest.java:19)Bean文件：
public class Car {
int carid;
String carname;
public int getCarid() {
return carid;
}
public void setCarid(int carid) {
this.carid = carid;
}
public String getCarname() {
return carname;
}
public void setCarname(String carname) {
this.carname = carname;
}
}我的hibernate映射文件：
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="Car" table="Car">
<id name="carid" column="carid"/>
<property name="carname" column="carname"/>
</class>
</hibernate-mapping>CarDAO：
import javax.persistence.EntityManager;
import org.hibernate.FlushMode;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.context.annotation.Scope;
import org.springframework.orm.hibernate3.SessionFactoryUtils;
import org.springframework.orm.hibernate4.HibernateTemplate;
import org.springframework.transaction.annotation.Transactional;
import org.springframework.transaction.support.TransactionTemplate;
//import org.springframework.transaction.annotation.Transactional;
public class CarDAO {
HibernateTemplate template;
EntityManager entityManager;
TransactionTemplate template1;
public HibernateTemplate getTemplate() {
return template;
}
public void setTemplate(HibernateTemplate template) {
this.template = template;
}
@Transactional
@Scope("session")
public void insert(Car c){
//template.getSessionFactory().getCurrentSession().setFlushMode(org.hibernate.FlushMode.AUTO);
//entityManager.setFlushMode(javax.persistence.FlushModeType.AUTO);
// session.setFlushMode(FlushMode.AUTO);
template.save(c);
entityManager.flush();
}
}ApplicationContext.xml：
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean id="datasourceBean" class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="jdbc:mysql://localhost:3306/test"/>
<property name="username" value="root"/>
<property name="password" value="root"/>
</bean>
<bean id="sessionfactoryBean" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="datasourceBean"/>
<property name="mappingResources">
<list>
<value>Car.hbm.xml</value>
</list>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.hbm2ddl.auto">update</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="template" class="org.springframework.orm.hibernate4.HibernateTemplate">
<property name="sessionFactory" ref="sessionfactoryBean"></property>
<!-- <property name="flushModeName" value="FLUSH_COMMIT"/> -->
</bean>
<bean id="CarDAO" class="CarDAO">
<property name="template" ref="template"></property>
</bean>
</beans>我已经在网络上搜索了合适的解决方案，但无法找到it.Please帮助，谢谢事先
回答 4
Stack Overflow用户
发布于 2014-06-22 06:51:40
我已经遇到了这个错误，我使用transaction来解决它。
首先，您需要声明hibernate4事务bean。只需在您的ApplicationContext.xml中编写以下代码：
<bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionfactoryBean"/>
</bean>然后，对于DAO测试，我直接使用了@Transactional(readOnly = false)等需要写入数据库的方法(保存、更新或删除等方法)。对于生产环境，我使用AOP在我的服务层中设置事务。
一些例子:这是我使用@Transactional的一种测试方法：
@Test
@Transactional(readOnly = false)
public void UpdateUser() {
long UserId = 1;
String UserFirstName = "some.FirstName";
String UserName = "some.Name";
User userToUpdate = userDAO.getUser(UserId);
userToUpdate.setFirstName(UserFirstName);
userToUpdate.setFamilyName(UserName);
userDAO.updateUser(userToUpdate);
User userUpdated = userDAO.getUser(UserId);
Assert.assertEquals(UserFirstName, userUpdated.getFirstName());
Assert.assertEquals(UserName, userUpdated.getFamilyName());
}如果我删除@Transactional(readOnly = false)，我的测试将失败，并出现与您的错误相同的错误：
UpdateUser(project.domain.dao.hibernate.UserDAOHibernateTest): Write operation
s are not allowed in read-only mode (FlushMode.MANUAL): Turn your Session into F
lushMode.COMMIT/AUTO or remove 'readOnly' marker from transaction definition.对于现在的生产，我通过AOP的方式在服务层建立了事务，在spring xml配置中：
<aop:config>
<aop:advisor id="managerTx" advice-ref="txAdvice" pointcut="execution(* *..service.manager.*Manager.*(..))"
order="1"/>
</aop:config>
<tx:advice id="txAdvice">
<tx:attributes>
<tx:method name="*" propagation="REQUIRED" read-only="true"/>
<tx:method name="create*" propagation="REQUIRED" read-only="false" />
<tx:method name="save*" propagation="REQUIRED" read-only="false" />
<tx:method name="update*" propagation="REQUIRED" read-only="false" />
<tx:method name="delete*" propagation="REQUIRED" read-only="false" />
</tx:attributes>
</tx:advice>你可以用AOP配置很多其他的东西，关于这一点，请看spring doc。
我希望这能对你有所帮助
Stack Overflow用户
发布于 2016-02-25 16:16:14
我发现answer.But我不知道reason.The的答案是因为follows.you应该在beans.xml中加入一些代码。
<bean id="txManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
<bean id="hibernateTemplate" class="org.springframework.orm.hibernate4.HibernateTemplate">
<property name="sessionFactory" ref="sessionFactory"></property>
</bean>
<aop:config>
<aop:pointcut id="bussinessService"
expression="execution(public * com.yh.registration.service.*.*(..))" />
<aop:advisor advice-ref="txAdvice" pointcut-ref="bussinessService" />
</aop:config>
<tx:advice id="txAdvice" transaction-manager="txManager">
<tx:attributes>
<tx:method name="exists" read-only="true" />
<tx:method name="add*" propagation="REQUIRED" />
</tx:attributes>
</tx:advice>Stack Overflow用户
发布于 2017-05-25 05:04:57
<tx:annotation-driven/>
<bean id="transactionManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"></property>
</bean>页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/24340800
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