我想在一个参数中传递多个值。SQL Server 2005
发布于 2012-05-12 04:14:04
您可以创建一个函数:
ALTER FUNCTION [dbo].[CSVStringsToTable_fn] ( @array VARCHAR(8000) )
RETURNS @Table TABLE ( value VARCHAR(100) )
AS
BEGIN
DECLARE @separator_position INTEGER,
@array_value VARCHAR(8000)
SET @array = @array + ','
WHILE PATINDEX('%,%', @array) <> 0
BEGIN
SELECT @separator_position = PATINDEX('%,%', @array)
SELECT @array_value = LEFT(@array, @separator_position - 1)
INSERT @Table
VALUES ( @array_value )
SELECT @array = STUFF(@array, 1, @separator_position, '')
END
RETURN
END并从中选择:
DECLARE @LocationList VARCHAR(1000)
SET @LocationList = '1,32'
SELECT Locations
FROM table
WHERE LocationID IN ( SELECT CAST(value AS INT)
FROM dbo.CSVStringsToTable_fn(@LocationList) )或
SELECT Locations
FROM table loc
INNER JOIN dbo.CSVStringsToTable_fn(@LocationList) list
ON CAST(list.value AS INT) = loc.LocationID当您尝试将多值列表从SSRS发送到PROC时,这非常有用。
CSV编辑:显示您可能需要强制转换-但是要小心控制在列表中发送的内容
发布于 2012-05-12 04:59:52
您可以让存储过程接受一个xml类型的输入变量,然后解压元素并获取它们。例如:
DECLARE @XMLData xml
DECLARE
@Code varchar(10),
@Description varchar(10)
SET @XMLData =
'
<SomeCollection>
<SomeItem>
<Code>ABCD1234</Code>
<Description>Widget</Description>
</SomeItem>
</SomeCollection>
'
SELECT
@Code = SomeItems.SomeItem.value('Code[1]', 'varchar(10)'),
@Description = SomeItems.SomeItem.value('Description[1]', 'varchar(100)')
FROM @XMLDATA.nodes('//SomeItem') SomeItems (SomeItem)
SELECT @Code AS Code, @Description AS Description结果:
Code Description
========== ===========
ABCD1234 Widget发布于 2015-07-10 20:50:48
有多种方法可以实现这一点,具体方法如下:
(表值参数)参数,并将它们作为传递
https://stackoverflow.com/questions/10493545
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