blocks|key|5773132|text|这样如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5773133|DateTime+date+=+DateTime.Today;
int+daysInYear+=+DateTime.IsLeapYear(date.Year)+?+366+:+365;
int+daysLeftInYear+=+daysInYear+-+date.DayOfYear;+//+Result+is+in+range+0-365.|code-block|syntax|javascript|5773134|请注意，只评估一次DateTime.Now很重要，否则，如果它在一年结束时评估一次，在另一年开始时评估一次，可能会出现不一致的情况。|offset|length|style|CODE|5773135|entityMap^0|0|0|9|C|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

How about:

<pre><code>DateTime date = DateTime.Today;
int daysInYear = DateTime.IsLeapYear(date.Year) ? 366 : 365;
int daysLeftInYear = daysInYear - date.DayOfYear; // Result is in range 0-365.
</code></pre>

Note that it's important to only evaluate <code>DateTime.Now</code> once, otherwise you could get an inconsistency if it evaluates once at the end of one year and once at the start of another.

blocks|key|2444966|text|DateTime+now+=+DateTime.Now;
DateTime+end+=+new+DateTime(now.Year+%2B+1,+1,+1);
int+daysLeftInYear+=+(int)(end+-+now).TotalDays;|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2444967|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>DateTime now = DateTime.Now;
DateTime end = new DateTime(now.Year + 1, 1, 1);
int daysLeftInYear = (int)(end - now).TotalDays;
</code></pre>

blocks|key|5773099|text|在我脑海中，你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5773100|Date+someDate+=+DateTime.Now;
Date+nextYear+=+new+DateTime(someDate.Year+%2B+1,+1,+1);
int+daysLeft+=+(nextYear+-+someDate).Days;|code-block|syntax|javascript|5773101|没有测试，因为我在家里，但我很确定逻辑。:)|5773102|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Off the top of my head, you could do this:

<pre><code>Date someDate = DateTime.Now;
Date nextYear = new DateTime(someDate.Year + 1, 1, 1);
int daysLeft = (nextYear - someDate).Days;
</code></pre>

Not tested because I'm at home, but I'm pretty sure on the logic. :)

blocks|key|3659162|text|这样如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3659163|++++public+int+DaysLeftInYear()
++++{
++++++++DateTime+today+=+DateTime.Now;
++++++++int+daysInYear+=+365;
++++++++if+(DateTime.IsLeapYear(today.Year))
++++++++{
++++++++++++daysInYear%2B%2B;
++++++++}

++++++++return+daysInYear+-+today.DayOfYear;
++++}|code-block|syntax|javascript|3659164|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about this:

<pre><code> public int DaysLeftInYear()
 {
 DateTime today = DateTime.Now;
 int daysInYear = 365;
 if (DateTime.IsLeapYear(today.Year))
 {
 daysInYear++;
 }

 return daysInYear - today.DayOfYear;
 }
</code></pre>

blocks|key|3659166|text|就像这样..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3659167|DateTime+EOY+=+new+DateTime(DateTime.Now.Year,+12,+31);
int+DaysLeft+=+EOY.Subtract(DateTime.Now).Days;|code-block|syntax|javascript|3659168|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

something like this...

<pre><code>DateTime EOY = new DateTime(DateTime.Now.Year, 12, 31);
int DaysLeft = EOY.Subtract(DateTime.Now).Days;
</code></pre>

blocks|key|2451221|text|假设您有更重要的日期(endDate)，并且您想知道有多少天重要，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2451222|int+days+=+endDate.Subtract(startDate).Days;|code-block|syntax|javascript|2451223|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Assuming that you have bigger date (endDate) and you want to know how many days big ,

<pre><code>int days = endDate.Subtract(startDate).Days;
</code></pre>

blocks|key|5773203|text|根据投票最多的答案，一条直线：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5773204|DateTime.IsLeapYear(DateTime.Today.Year)+?+366+-+DateTime.Today.DayOfYear+:+365+-+DateTime.Today.DayOfYear|code-block|syntax|javascript|5773205|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

One liner, based on top voted answer:

<pre><code>DateTime.IsLeapYear(DateTime.Today.Year) ? 366 - DateTime.Today.DayOfYear : 365 - DateTime.Today.DayOfYear
</code></pre>

blocks|key|540521|text|已经有很多有效的答案，但还没有看到这个简单的答案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|540522|DateTime+today+=+DateTime.Now;
int+daysleft+=+new+DateTime(today.Year,12,31).DayOfYear+-+today.DayOfYear;|code-block|syntax|javascript|540523|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Already a lot of answers that work, but haven't seen this simple one yet

<pre><code>DateTime today = DateTime.Now;
int daysleft = new DateTime(today.Year,12,31).DayOfYear - today.DayOfYear;
</code></pre>

I'm trying to get the number of days left in a year from <code>Datetime.Now</code>. 

Having a little trouble, I tried using a <code>datediff</code> without much success.

I don't suppose one of you experts could perhaps show me how this would be achieved in C#?

I'd like a code to return an integer value for the days remaining.

C# - How many days left in year from Datetime.Now

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我正在尝试从Datetime.Now获取一年中剩余的天数。遇到一点小麻烦，我试着使用datediff，但没有太多成功。我不认为你们中的任何一个专家可以向我展示如何在C#中实现这一点？我想要一个代码来返回剩余天数的整数值。

问C# -一年中离Datetime.Now还剩多少天
EN

回答 8

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问C# -一年中离Datetime.Now还剩多少天EN

回答 8

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问C# -一年中离Datetime.Now还剩多少天
EN