blocks|key|2470751|text|你就不能这样做吗：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2470752|int+x+=+label.Bounds.Location.X+%2B+statusStrip.Location.X;
int+y+=+label.Bounds.Location.Y+%2B+statusStrip.Location.Y;
menu.Show(this,+x,+y);|code-block|syntax|javascript|2470753|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Can't you just do something like this:

<pre><code>int x = label.Bounds.Location.X + statusStrip.Location.X;
int y = label.Bounds.Location.Y + statusStrip.Location.Y;
menu.Show(this, x, y);
</code></pre>

blocks|key|3711619|text|查看ToolStripStatusLabel的Bounds属性。像这样使用它来做你需要做的事情：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3711620|contextMenuStrip1.Show(statusStrip1,+toolStripStatusLabel2.Bounds.X,+toolStripStatusLabel2.Bounds.Y);++++++++++++|code-block|syntax|javascript|3711621|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/system.windows.forms.toolstripitem.bounds.aspx^0|N|6|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Check out the <a href="http://msdn.microsoft.com/en-us/library/system.windows.forms.toolstripitem.bounds.aspx" rel="nofollow noreferrer">Bounds</a> property of the ToolStripStatusLabel. Use it like this to do what you need to do:

<pre><code>contextMenuStrip1.Show(statusStrip1, toolStripStatusLabel2.Bounds.X, toolStripStatusLabel2.Bounds.Y); 
</code></pre>

blocks|key|3711654|text|当鼠标在ToolStripStatusLabel上单击时，需要几个步骤来确定鼠标在窗体上的正确位置。正如您所提到的，ToolStripStatusLabel没有PointToClient或PointToScreen方法，但父StatusStrip控件有。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3711655|尝试：|3711656|private+void+toolStripStatusLabel_MouseDown(object+sender,+MouseEventArgs+e)
{
++++Point+p+=+e.Location;
++++p.Offset(toolStripStatusLabel.Bounds.Location);
++++myContextMenu.Show(StatusStrip.PointToScreen(p));
}|code-block|syntax|javascript|3711657|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

There are a couple of steps involved in getting the proper location of the mouse on the form when it's clicked on a ToolStripStatusLabel. As you mention the ToolStripStatusLabel does not have PointToClient or PointToScreen methods, but the parent StatusStrip control does.

Try:

<pre><code>private void toolStripStatusLabel_MouseDown(object sender, MouseEventArgs e)
{
 Point p = e.Location;
 p.Offset(toolStripStatusLabel.Bounds.Location);
 myContextMenu.Show(StatusStrip.PointToScreen(p));
}
</code></pre>

blocks|key|558595|text|一个非常，非常晚的答案，只是因为我碰巧遇到了同样的问题，并在谷歌上搜索了这个问题。到目前为止，我发现的最好的解决方案为答案增加了一个很好的转折。这就是它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|558596|++++void+toolStripItem_MouseUp(object+sender,+MouseEventArgs+e)
++++{
++++++++if+(e.Button+==+MouseButtons.Right)
++++++++{
++++++++++++var+label+=+(ToolStripItem)sender;
++++++++++++this.contextMenuStrip1.Show(this.mainStatusStrip,+label.Bounds.X+%2B+e.X,+label.Bounds.Y+%2B+e.Y);
++++++++}+
++++}|code-block|syntax|javascript|558597|将鼠标相对于控件的坐标(e.X，e.Y)添加到边界坐标，使菜单显示在正确的位置。省略此选项将显示ToolStripItem左上角的菜单。记录在案。|558598|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

A very, very late answer, just because I happened to struggle with the same issue and googled up this question. What I found as the best solution adds one nice twist to the answers so far. Here it is:

<pre><code> void toolStripItem_MouseUp(object sender, MouseEventArgs e)
 {
 if (e.Button == MouseButtons.Right)
 {
 var label = (ToolStripItem)sender;
 this.contextMenuStrip1.Show(this.mainStatusStrip, label.Bounds.X + e.X, label.Bounds.Y + e.Y);
 } 
 }
</code></pre>

Adding the mouse coordinates relative to the control (e.X, e.Y) to the bounds coordinates makes the menu appear at exactly the right position. Omitting this shows the menu at the top left corner of the ToolStripItem. For the record.

I want to show a ContextMenuStrip at the location of a ToolStripStatusLabel in a StatusStrip. Ordinary controls have PointToScreen / PointToClient / etc, but as ToolStripStatusLabel is derived from Component it does not.

Any help would be appreciated.

Show ContextMenuStrip at location of StatusBar item

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想在StatusStrip中的ToolStripStatusLabel所在位置显示一个ContextMenuStrip。普通控件有PointToScreen / PointToClient /等，但由于ToolStripStatusLabel是从组件派生的，所以没有。任何帮助都将不胜感激。

问在StatusBar项目的位置显示ContextMenuStrip
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