Php路由器，从uri提取密钥
Php路由器，从uri提取密钥
提问于 2009-07-02 10:09:47
嘿，伙计们！我需要一些正则表达式等方面的帮助。我需要从url中提取虚拟关键字，应用程序中的某种路由器。下面是参数：
Rule: /books/:category/:id/:keyname
Data: /books/php/12345/this-is-a-test-keyname输出应该是这样的：
array(
'category' => 'php',
'id' => '12345',
'keyname' => 'this-is-a-test-keyname'
);所以，问题是:我如何在php中做到这一点？
P.S规则的组合可能会有所不同。因此，主键是带有“：”符号的单词。例如：
/book-:id/:category/:keyname
/book/:id_:category~:keyname附言2:这是我之前的一段代码。它是有效的，但不灵活。
function rule_process($rule, $data) {
// extract chunks
$ruleItems = explode('/',$rule);
$dataItems = explode('/',$data);
// remove empty items
array_clean(&$ruleItems);
array_clean(&$dataItems);
// rule and data supposed to have the same structure
if (count($ruleItems) == count($dataItems)) {
$result = array();
foreach($ruleItems as $ruleKey => $ruleValue) {
// check if the chunk is a key
if (preg_match('/^:[\w]{1,}$/',$ruleValue)) {
// ok, found key, adding data to result
$ruleValue = substr($ruleValue,1);
$result[$ruleValue] = $dataItems[$ruleKey];
}
}
if (count($result) > 0) return $result;
unset($result);
}
return false;
}
function array_clean($array) {
foreach($array as $key => $value) {
if (strlen($value) == 0) unset($array[$key]);
}
}事实上，这个版本的路由器对我来说已经足够了，但我只是对如何制作灵活的解决方案感兴趣。顺便说一下，一些测试：( 10000次操作中的30次)：
TEST #0 => Time:0.689285993576, Failures: 0
TEST #1 => Time:0.684408903122, Failures: 0
TEST #2 => Time:0.683394908905, Failures: 0
TEST #3 => Time:0.68522810936, Failures: 0
TEST #4 => Time:0.681587934494, Failures: 0
TEST #5 => Time:0.681943893433, Failures: 0
TEST #6 => Time:0.683794975281, Failures: 0
TEST #7 => Time:0.683885097504, Failures: 0
TEST #8 => Time:0.684013843536, Failures: 0
TEST #9 => Time:0.684071063995, Failures: 0
TEST #10 => Time:0.685361146927, Failures: 0
TEST #11 => Time:0.68728518486, Failures: 0
TEST #12 => Time:0.688632011414, Failures: 0
TEST #13 => Time:0.688556909561, Failures: 0
TEST #14 => Time:0.688539981842, Failures: 0
TEST #15 => Time:0.689876079559, Failures: 0
TEST #16 => Time:0.689854860306, Failures: 0
TEST #17 => Time:0.68727684021, Failures: 0
TEST #18 => Time:0.686210155487, Failures: 0
TEST #19 => Time:0.687953948975, Failures: 0
TEST #20 => Time:0.687957048416, Failures: 0
TEST #21 => Time:0.686664819717, Failures: 0
TEST #22 => Time:0.686244010925, Failures: 0
TEST #23 => Time:0.686643123627, Failures: 0
TEST #24 => Time:0.685017108917, Failures: 0
TEST #25 => Time:0.686363935471, Failures: 0
TEST #26 => Time:0.687278985977, Failures: 0
TEST #27 => Time:0.688650846481, Failures: 0
TEST #28 => Time:0.688835144043, Failures: 0
TEST #29 => Time:0.68886089325, Failures: 0所以，这已经足够快了。我在普通的笔记本电脑上测试。因此，可以肯定的是，这一点可以在真实的网站中使用。
还有其他的解决方案吗？
回答 5
Stack Overflow用户
发布于 2009-07-02 10:27:23
我不认为只有一个正则表达式可以做到这一点。Zend Framework的工作原理与您的示例类似。看看他们的source code吧。
Stack Overflow用户
发布于 2009-07-02 10:54:36
试试这个简单的解决方案：
$data = Array (
"/book/:id/:category/:keyname" => "/book/12345/php/this-is-a-test-keyname",
"/book-:id/:category/:keyname" => "/book-12345/php/this-is-a-test-keyname",
"/book/:id_:category~:keyname" => "/book/12345_php~this-is-a-test-keyname",
);
foreach ($data as $rule => $uri) {
$reRule = preg_replace('/:([a-z]+)/', '(?P<\1>[^/]+)', $rule);
$reRule = str_replace('/', '\/', $reRule);
preg_match('/' . $reRule .'/', $uri, $matches);
print_r($matches);
}唯一的缺点是，在这一点上您不能进行花哨的数据验证，所以您必须在其他地方进行验证。此外，如果规则与正则表达式语法冲突，它可能会变得混乱(在这里，您必须做一些繁重的转义工作)。
Stack Overflow用户
发布于 2009-09-26 19:22:00
我有另一个版本的脚本：http://blog.sosedoff.com/2009/09/20/rails-like-php-url-router/
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/1073569
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