blocks|key|3021627|text|在jq的手册中找到了解决方案(使用#ifthenelse和#Objects)+--+http://stedolan.github.io/jq/manual|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3021628|jq+-r+'{name1:+.[].item1,+name2:+.[].array[].item2}+%7C+/
if+.item2+==+"bbb"+then+.name1+elif+.item2+!=+"bbb"+then+empty+else+empty+end'|code-block|syntax|javascript|3021629|entityMap|0|LINK|mutability|MUTABLE|url|http://stedolan.github.io/jq/manual^0|16|Z|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

found the solution on jq's manual (with #ifthenelse and #Objects) - <a href="http://stedolan.github.io/jq/manual" rel="nofollow">http://stedolan.github.io/jq/manual</a>

<pre><code>jq -r '{name1: .[].item1, name2: .[].array[].item2} | /
if .item2 == "bbb" then .name1 elif .item2 != "bbb" then empty else empty end'
</code></pre>

blocks|key|3021678|text|多亏了递归运算符..的魔力，才有了一个更简单的解决方案|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3021679|jq+-r+'.[]+%7C+select(..+%7C+.item2?+==+"bbb").item1'|3021680|基本上，对于原始数组中的每个(.[])对象，只选择(select)那些递归(..)名为.item2等于"bbb"的键，然后选择所述对象的.item1属性。|3021681|entityMap^0|8|2|0|0|1D|0|F|3|Q|6|12|2|17|6|1F|5|1W|6|0^^$0|@$1|2|3|4|5|6|7|L|8|@$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|K|$]]

An easier solution is available thanks to the magic powers of the recurse operator, <code>..</code>:

<code>jq -r '.[] | select(.. | .item2? == "bbb").item1'</code>

Basically what this does is, for each (<code>.[]</code>) object in the original array, pick (<code>select</code>) only those in which any of the keys recursively (<code>..</code>) named <code>.item2</code> equals <code>"bbb"</code>, and then select the <code>.item1</code> property of said object.

blocks|key|706161|text|如果你发现..的魔力。对于您的目的来说，功能太强大了，以下内容可能会有用。它限制搜索"item2“键。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|706162|def+some(condition):+reduce+.[]+as+$x
+(false;+if+.+then+.+else+$x%7Ccondition+end);

.[]
%7C+to_entries
%7C+select(+some(+.value+%7C+(type+==+"array")+and+some(.item2+==+"bbb"))+)
%7C+from_entries
%7C+.item1|code-block|syntax|javascript|706163|如果您的jq有任何/1，则使用它而不是某些/1。|706164|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you find the magic of .. too powerful for your purposes, the following may be useful. It restricts the search for the "item2" key.

<pre><code>def some(condition): reduce .[] as $x
 (false; if . then . else $x|condition end);

.[]
| to_entries
| select( some( .value | (type == "array") and some(.item2 == "bbb")) )
| from_entries
| .item1
</code></pre>

If your jq has any/1, then use it instead of some/1.

blocks|key|947890|text|这是一个使用tostream和getpath的解决方案|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|947891|foreach+(tostream%7Cselect(length==2))+as+[$p,$v]+(.;.;
++if+$p[-1]+==+"item2"+and+$v+==+"bbb"+then+getpath($p[:-3]).item1+else+empty+end
)|code-block|syntax|javascript|947892|编辑:我现在意识到表单foreach+E+as+$X+(.;+.;+R)的过滤器几乎总是可以被重写为E+as+$X+%7C+R，所以上面的内容实际上是|CODE|947893|++(tostream+%7C+select(length==2))+as+[$p,$v]
%7C+if+$p[-1]+==+"item2"+and+$v+==+"bbb"+then+getpath($p[:-3]).item1+else+empty+end|947894|entityMap^0|6|8|F|7|0|0|B|P|1E|B|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|W|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|X|8|@$9|Y|A|Z|B|M]|$9|10|A|11|B|M]]|D|@]|E|$]]|$1|N|3|O|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|P|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|Q|$]]

Here is a solution which uses tostream and getpath

<pre><code>foreach (tostream|select(length==2)) as [$p,$v] (.;.;
 if $p[-1] == "item2" and $v == "bbb" then getpath($p[:-3]).item1 else empty end
)
</code></pre>

EDIT: I now realize a filter of the form <code>foreach E as $X (.; .; R)</code> can almost always be rewritten as <code>E as $X | R</code> so the above is really just

<pre><code> (tostream | select(length==2)) as [$p,$v]
| if $p[-1] == "item2" and $v == "bbb" then getpath($p[:-3]).item1 else empty end
</code></pre>

I've already asked a similar question here - <a href="https://stackoverflow.com/questions/31533719/parse-json-and-choose-items-keys-upon-condition">Parse json and choose items\keys upon condition</a>, but this time it's slightly different.

This is the Example:

<pre><code>[
 {
 "item1": "value123",
 "array0": [
 {
 "item2": "aaa"
 }
 ]
 },
 {
 "item1": "value456",
 "array1": [
 {
 "item2": "bbb"
 }
 ]
 },
 {
 "item1": "value789",
 "array2": [
 {
 "item2": "ccc"
 }
 ]
 }
]
</code></pre>

I'd like to get the value of "item1", only when "item2" has a specific value.

Let's say if item2 equals "bbb", then all I want to get back is "value456".

I've tried to solve it with jq like it worked for me in the issue mentioned above, but to no avail, as I can't extract values from a "higher" level than the one i'm searching in with jq's select and map.

Parse json and extract items in array upon condition of nested values

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我已经在这里问了一个类似的问题- ，但这次略有不同。示例如下：[  {    "item1": "value123",    "array0": [      {        "item2": "aaa"      }    ]  },  {    "item1": "value456",    "array1": ...

问根据嵌套值的条件解析json并提取数组中的项
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问根据嵌套值的条件解析json并提取数组中的项EN