我在替换短语中的某些字符串时遇到了问题。我必须将"_“替换为和"< / I>”交替。到目前为止我的代码如下:
private String line; //The line to format
public TextFormatter(String lineToFormat) {
line = lineToFormat;
}
/**
* Finds the first single instance of str in line, starting at the postion start
* <p>
* @param str the string of length 1 to find. Guaranteed to be length 1.
* @param start the position to start searching. Guaranteed to be in the string line.
* <p>
* @return the index of first instance of str if string found or -1 otherwise.
*/
private int findString(String str, int start) {
String phrase = line;
int psn = phrase.indexOf(str, start);
return psn;
}
/**
* Count the number of times single instances of str appear in the line.
* <p>
* @param str the string to find. Guaranteed to be length 1.
* <p>
* @return the number of times the string appears in the line.
*/
private int countStrings(String str) {
int counter = 0;
for (int i = 0; i < line.length(); i++) {
if (line.charAt(i) == '_') {
counter++;
}
}
return counter;
}
/**
* Replaces all single instances of underscores in the line given by line with italics tags. There must be an even
* number of underscores in the line, and they will be replaced by <I>, </I>, alternating.
* <p>
* @return the line with single instances of underscores replaced with
* <I> tags or the original line if there are not an even number of underscores.
* <p>
*/
public String convertItalics() {
String toReturn = " ";
if (countStrings("_") % 2 == 0) { //makes sure there is even number of "_"
for (int i = 0; i < line.length(); i++) {
if (line.indexOf("_") + i == line.indexOf("_")) {
toReturn += line.replace("_", "<I>");
}
}
} else if (countStrings("_") % 2 != 0) {
toReturn += line.replace("_", " ");
}
return toReturn;
}我已经掌握了第一个方法,但是我在使用convertItalics()时遇到了问题。如果我运行我的代码,我会让它替换"_“,但它不会替换。
如果我有像"hello _my name is _chomez_“这样的短语,它不会替换任何"_”。任何帮助都将不胜感激。谢谢!
编辑:感谢那些留下评论的人,我的课程快结束了,所以我会在有电脑使用和有时间的时候再来看看,谢谢大家!
发布于 2014-12-13 00:40:32
我对这行做了一个注释,我建议从一行创建一个字符串数组,并在该行上循环。就像这样
String [] words = line.split(" ");然后遍历这些单词并调用您的countStrings(words[i]);
public String convertItalics() {
String toReturn = " ";
//***line below will never result in even number, since you are passing one "_", pass a whole word//***
if (countStrings("_") % 2 == 0) { //makes sure there is even number of "_"
for (int i = 0; i < line.length(); i++) {
if (line.indexOf("_") + i == line.indexOf("_")) {
toReturn += line.replace("_", "<I>");
}
}
} else if (countStrings("_") % 2 != 0) {
toReturn += line.replace("_", " ");
}
return toReturn;
}发布于 2014-12-13 00:41:39
如果你想替换Java中的字符,我建议使用" replace“方法,例如:
public class Test{
public static void main(String args[]){
String Str = new String("This is a long string");
System.out.println(Str.replace('i', 'o'));这基本上会将"i“替换为"o”。此外,如果要比较java中的字符串,则必须使用equals或equalsIgnoreCase而不是==方法,因为您要比较的是字符的数量和正确的顺序,而不是这些字符串的值。
我希望这能对你有所帮助!
发布于 2014-12-13 00:47:51
你在做屏幕报废吗?有很多方法可以做到这一点。字符串操作,stacks..etc。
这是最简单的方法之一。
String code = "hello _my name is _chomez_";
code = code.replace("_", "<li>");现在,您已经成功地将其转换为:
hello <li>my name is <li>chomez<li>现在只需要做交替的结束标记。
int n = code.indexOf("<li>", code.indexOf("<li>") + 1);
code = code.substring(0,n+1) + "/" + code.substring(n+1);现在你拥有了::
hello <li>my name is </li>chomez<li>如果你有3个以上的标签要处理,只需运行一个循环,并将所有的even position标签替换为结束标签。算法会是这样的,当有标签时,继续循环。如果这是2号,4号,6号(偶数位置标签),将其替换为</li>
https://stackoverflow.com/questions/27447972
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