blocks|key|3145650|text|要合并您链接的内容和您的链接，请执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3145651|for+(i+=+1;+i+<+1050;+i%2B%2B)+{
++var+str+=+""+%2B+i
++var+pad+=+"0000"
++str+=+pad.substring(0,+pad.length+-+str.length)+%2B+str
++images.push('/images/'+%2B+str+%2B+'.jpg');
}|code-block|syntax|javascript|3145652|我希望这对你有帮助|3145653|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

To combine what you linked and yours:

<pre><code>for (i = 1; i &lt; 1050; i++) {
 var str = "" + i
 var pad = "0000"
 str = pad.substring(0, pad.length - str.length) + str
 images.push('/images/' + str + '.jpg');
}
</code></pre>

I hope that helps

blocks|key|1016578|text|您可以创建一个实用函数，用于将整数转换为4位字符串表示形式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1016579|function+intTo4digitsString(nb)+{
+++if(nb+>+0+&&+nb+<+10)
++++++++return+"000"%2Bnb;
+++else+if(nb+>=+10+&&+nb+<+100)
++++++++return+"00"%2Bnb;
+++else+if(nb+>=+100+&&+nb+<+1000)
++++++++return+"0"%2Bnb;
}|code-block|syntax|javascript|1016580|这个版本限制为4位数字(并且不像其他答案那样容易扩展)，但我认为它对您更具可读性:)然后您可以使用：|1016581|for+(i+=+1;+i+<+1050;+i%2B%2B)+{
++++images.push('/images/'+%2B+inTo4DigitsString(i)+%2B+'.jpg');
}|1016582|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can make a utility function which convert a integer to a 4 digits string representation:

<pre><code>function intTo4digitsString(nb) {
 if(nb &gt; 0 &amp;&amp; nb &lt; 10)
 return "000"+nb;
 else if(nb &gt;= 10 &amp;&amp; nb &lt; 100)
 return "00"+nb;
 else if(nb &gt;= 100 &amp;&amp; nb &lt; 1000)
 return "0"+nb;
}
</code></pre>

This version is limited to 4 digits (and not as easily extensible than other answers), but I think it's more readable fr you :) Then you can use:

<pre><code>for (i = 1; i &lt; 1050; i++) {
 images.push('/images/' + inTo4DigitsString(i) + '.jpg');
}
</code></pre>

blocks|key|829664|text|zeropad+=+function(+n,l+){+
++++var+ret,+d,+i;
++++ret+=+n+===+null+%7C%7C+n+===+undefined+?+''+:+n.toString();
++++//+do+we+need+to+pad+or+truncate?
++++d+=+l+-+ret.length;
++++if+(d>0)+{
++++++++for+(i=0;i<d;+i%2B%2B)+{
++++++++++++ret+=+'0'%2Bret;
++++++++}
++++}
++++return(ret);
};
images.push('/images/'%2Bzeropad(i,4)+%2B+'.jpg');|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|829665|来自我前段时间写的一个库。https://github.com/deitch/jsorm-utilities|unstyled|offset|length|829666|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/deitch/jsorm-utilities^0|0|D|15|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>zeropad = function( n,l ){ 
 var ret, d, i;
 ret = n === null || n === undefined ? '' : n.toString();
 // do we need to pad or truncate?
 d = l - ret.length;
 if (d&gt;0) {
 for (i=0;i&lt;d; i++) {
 ret = '0'+ret;
 }
 }
 return(ret);
};
images.push('/images/'+zeropad(i,4) + '.jpg');
</code></pre>

From a library I wrote a while back. <a href="https://github.com/deitch/jsorm-utilities" rel="nofollow">https://github.com/deitch/jsorm-utilities</a>

blocks|key|3145710|text|function+padNum(num,length)
{
++++return+Array((length%2B1)-num.toString().length).join("0")%2Bnum;
}

padNum(1,4);//0001
padNum(250,4);//0250|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3145711|然后在你的代码中：|unstyled|3145712|images.push('/images/'+%2B+padNum(i,4)+%2B+'.jpg');|3145713|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>function padNum(num,length)
{
 return Array((length+1)-num.toString().length).join("0")+num;
}

padNum(1,4);//0001
padNum(250,4);//0250
</code></pre>

And then in your code:

<pre><code>images.push('/images/' + padNum(i,4) + '.jpg');
</code></pre>

blocks|key|3145717|text|不如..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3145718|for+(i+=+1;+i+<+1050;+i%2B%2B)+{++++++++
++++images.push('/images/'+%2B+('0000'.substring(0,+i.toString().length)%2Bi)+%2B+'.jpg');
}|code-block|syntax|javascript|3145719|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about...

<pre><code>for (i = 1; i &lt; 1050; i++) { 
 images.push('/images/' + ('0000'.substring(0, i.toString().length)+i) + '.jpg');
}
</code></pre>

blocks|key|4612995|text|我会做这样的事情|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4612996|for+(i+=+1;+i+<+1050;+i%2B%2B)
{
++++var+name+=+'0000'+%2B+i;
++++images.push('/images/'+%2B+name.substr(name.length+-+4)+%2B+'.jpg');
}|code-block|syntax|javascript|4612997|小提琴：http://jsfiddle.net/4z5Sd/|offset|length|4612998|entityMap|0|LINK|mutability|MUTABLE|url|http://jsfiddle.net/4z5Sd/^0|0|0|4|Q|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

I would do something like this

<pre><code>for (i = 1; i &lt; 1050; i++)
{
 var name = '0000' + i;
 images.push('/images/' + name.substr(name.length - 4) + '.jpg');
}
</code></pre>

fiddle: <a href="http://jsfiddle.net/4z5Sd/" rel="nofollow">http://jsfiddle.net/4z5Sd/</a>

blocks|key|3145721|text|这样如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3145722|for+(var+i+=+1;i<1050;i%2B%2B){
++++images.push("/images/"%2B(Array(5-(""%2Bi).length)).join("0")%2Bi%2B".jpg");
}+|code-block|syntax|javascript|3145723|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

What about this:

<pre><code>for (var i = 1;i&lt;1050;i++){
 images.push("/images/"+(Array(5-(""+i).length)).join("0")+i+".jpg");
} 
</code></pre>

blocks|key|3145736|text|我建议：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3145737|Number.prototype.leftPad+=+function+(len)+{
++++var+l+=+this.toString().length,
++++++++d+=+len+-+l;
++++return+new+Array(d+%2B+1).join('0')+%2B+this.toString();
};

for+(var+i+=+1,+len+=+1051;+i+<+len;+i%2B%2B)+{
++++console.log(i.leftPad(4)+%2B+'.jpg');
}|code-block|syntax|javascript|3145738|JS+Fiddle+demo。|offset|length|3145739|参考文献：|3145740|3145741|Array.|unordered-list-item|3145742|Array.join().|style|CODE|3145743|Number.toString().|3145744|3145745|entityMap|0|LINK|mutability|MUTABLE|url|http://jsfiddle.net/davidThomas/PxC5B/|1|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array|2|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/join|3|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Number/toString^0|0|0|0|E|0|0|0|0|0|5|1|0|0|C|0|C|2|0|0|H|0|H|3|0|0^^$0|@$1|2|3|4|5|6|7|1B|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1C|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1D|8|@]|9|@$I|1E|J|1F|1|1G]]|A|$]]|$1|K|3|L|5|6|7|1H|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|1J|8|@]|9|@$I|1K|J|1L|1|1M]]|A|$]]|$1|Q|3|R|5|P|7|1N|8|@$I|1O|J|1P|S|T]]|9|@$I|1Q|J|1R|1|1S]]|A|$]]|$1|U|3|V|5|P|7|1T|8|@$I|1U|J|1V|S|T]]|9|@$I|1W|J|1X|1|1Y]]|A|$]]|$1|W|3|-4|5|6|7|1Z|8|@]|9|@]|A|$]]|$1|X|3|-4|5|6|7|20|8|@]|9|@]|A|$]]]|Y|$Z|$5|10|11|12|A|$13|14]]|15|$5|10|11|12|A|$13|16]]|17|$5|10|11|12|A|$13|18]]|19|$5|10|11|12|A|$13|1A]]]]

I'd suggest:

<pre><code>Number.prototype.leftPad = function (len) {
 var l = this.toString().length,
 d = len - l;
 return new Array(d + 1).join('0') + this.toString();
};

for (var i = 1, len = 1051; i &lt; len; i++) {
 console.log(i.leftPad(4) + '.jpg');
}
</code></pre>

<a href="http://jsfiddle.net/davidThomas/PxC5B/" rel="nofollow">JS Fiddle demo</a>.

References:

<ul>
<li><a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array" rel="nofollow">Array</a>.</li>
<li><a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/join" rel="nofollow"><code>Array.join()</code></a>.</li>
<li><a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Number/toString" rel="nofollow"><code>Number.toString()</code></a>.</li>
</ul>

blocks|key|829722|text|谢谢，mattsjo。必须将'pad‘添加到数组中才能完全工作。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|829723|for+(i+=+1;+i+<+1050;+i%2B%2B)+{
++var+str+=+""+%2B+i
++var+pad+=+"0000"
++var+padd+=+pad.substring(0,+pad.length+-+str.length)+%2B+str
++images.push('/images/'+%2B+padd+%2B+'.jpg');
}|code-block|syntax|javascript|829724|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Thanks mattsjo. Had to add 'pad' to array for it to work fully.

<pre><code>for (i = 1; i &lt; 1050; i++) {
 var str = "" + i
 var pad = "0000"
 var padd = pad.substring(0, pad.length - str.length) + str
 images.push('/images/' + padd + '.jpg');
}
</code></pre>

blocks|key|4613044|text|function+pad(val,+len)+{
++++return+("000000000000000000"+%2B+val).substr(len+*+-1);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4613045|用法：|unstyled|4613046|console.log(pad(1,+4)+%2B+".jpg");
>+0001.jpg|4613047|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>function pad(val, len) {
 return ("000000000000000000" + val).substr(len * -1);
}
</code></pre>

Usage:

<pre><code>console.log(pad(1, 4) + ".jpg");
&gt; 0001.jpg
</code></pre>

blocks|key|1010464|text|如果您需要一个通用的字符串格式化函数，那么sprintf库可能适合您。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1010465|var+i,+images+=+[];

for+(i+=+1;+i+<=+1050;+i%2B%2B)+{
++++images.push(sprintf('/images/%2504d.jpg',+i));
}|code-block|syntax|javascript|1010466|JSFiddle|1010467|entityMap|0|LINK|mutability|MUTABLE|url|http://www.diveintojavascript.com/projects/javascript-sprintf|1|http://jsfiddle.net/UvjzP/^0|L|7|L|7|0|0|0|0|8|1|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@]|D|@$9|14|A|15|1|16]]|E|$]]|$1|M|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]|U|$5|P|Q|R|E|$S|V]]]]

If you want a general purpose string formatting function then the <a href="http://www.diveintojavascript.com/projects/javascript-sprintf" rel="nofollow"><code>sprintf</code></a> library might work for you.

<pre><code>var i, images = [];

for (i = 1; i &lt;= 1050; i++) {
 images.push(sprintf('/images/%04d.jpg', i));
}
</code></pre>

<a href="http://jsfiddle.net/UvjzP/" rel="nofollow">JSFiddle</a>

I have an array in javascript. It specifies URLs for images 1-1050. My images must be named 0001.jpg, 0002.jpg ect... However my script is calling up 1.jpg, 2.jpg... 
I am very new to JS and am struggling to incorporate an answer from <a href="https://stackoverflow.com/questions/5366849/convert-1-to-0001-in-javascript">here</a> with my script.

<pre><code>for (i = 0001; i &lt; 1050; i++) {
 images.push('/images/' + i + '.jpg');
}
</code></pre>

Converting 1 to 0001 in javascript array

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我在javascript中有一个数组。它指定图像1-1050的URL。我的图片必须命名为0001.jpg，0002.jpg等...但是我的脚本调用的是1.jpg，2.jpg...我对JS非常陌生，正在努力将来自的答案与我的脚本结合起来。for (i = 0001; i < 1050; i++) { images.pus...

问在javascript数组中将1转换为0001
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问在javascript数组中将1转换为0001EN