blocks|key|831046|text|将您的按钮放入一个数组中，循环遍历并禁用它们：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|831047|NSArray+*buttonsArray+=+@[yourButton1,+yourButton2];

for+(UIButton+*button+in+buttonsArray)+{
button.enabled+=+NO;
}|code-block|syntax|javascript|831048|当您想要启用它们时，只需再次循环并将enabled设置为YES|offset|length|style|CODE|831049|entityMap^0|0|0|I|7|S|3|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

Put your buttons in a array and loop through them and disable them:

<pre><code>NSArray *buttonsArray = @[yourButton1, yourButton2];

for (UIButton *button in buttonsArray) {
button.enabled = NO;
}
</code></pre>

And when you want them enabled just loop again and set <code>enabled</code> to <code>YES</code>

blocks|key|831080|text|在您的helpView(imageview)中保留一个标记，并添加以下代码|type|unstyled|depth|inlineStyleRanges|entityRanges|data|831081|for+(UIView+*view+in+self.view.subviews)+{
++++++++if+(view.tag+!=+yourViewTag)+{
++++++++++++view.userInteractionEnabled+=+NO;
++++++++}
++++}+|code-block|syntax|javascript|831082|在删除帮助屏幕之后，使用以下代码|831083|for+(UIView+*view+in+self.view.subviews)+{
++++++++++++view.userInteractionEnabled+=+YES;
++++}+|831084|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Keep a Tag to your helpView(imageview) and add the following code

<pre><code>for (UIView *view in self.view.subviews) {
 if (view.tag != yourViewTag) {
 view.userInteractionEnabled = NO;
 }
 } 
</code></pre>

And after removing the help screen use the following code

<pre><code>for (UIView *view in self.view.subviews) {
 view.userInteractionEnabled = YES;
 } 
</code></pre>

blocks|key|3147264|text|您可以尝试查看下面出现的solution..When帮助图像视图|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3147265|++++for+(UIView+*view+in+[self.view+subviews])+
++++{
++++++++if+(view+isKindOfClass:[UIButton+Class])+
++++++++{
++++++++++++view.userInteractionEnabled+=+NO;
++++++++}
+++++++else
++++++++{
++++++++++++view.userInteractionEnabled+=+YES;
++++++++}
++++}+

////After+dismissing+the+help+screen+you+can

++++for+(UIView+*view+in+[self.view+subviews])+
++++{
++++++++if+(view+isKindOfClass:[UIButton+Class])+
++++++++{
++++++++++++view.userInteractionEnabled+=+YES;
++++++++}
++++}+|code-block|syntax|javascript|3147266|/(OR)只需执行以下操作|3147267|self.view.userInteractionEnabled=YES;|3147268|希望它能帮助你..|3147269|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

you can try below solution..When help imageview is appearing

<pre><code> for (UIView *view in [self.view subviews]) 
 {
 if (view isKindOfClass:[UIButton Class]) 
 {
 view.userInteractionEnabled = NO;
 }
 else
 {
 view.userInteractionEnabled = YES;
 }
 } 

////After dismissing the help screen you can

 for (UIView *view in [self.view subviews]) 
 {
 if (view isKindOfClass:[UIButton Class]) 
 {
 view.userInteractionEnabled = YES;
 }
 } 
</code></pre>

////(OR) Simply do as below

<pre><code>self.view.userInteractionEnabled=YES;
</code></pre>

Hope it helps you..

blocks|key|1011188|text|您可以创建一个方法来禁用helpBackground下所有视图的用户交互：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1011189|-+(void)disableUserInteractionForViewsUnderView:(UIView+*)view
{
++++CGRect+area+=+view.frame;
++++for+(UIView+*underView+in+[self.view+subviews])+{
++++++++if(CGRectContainsRect(area,+underView.frame))
++++++++++++underView.userInteractionEnabled+=+NO;
++++}
}|code-block|syntax|javascript|1011190|在这之后，你在需要的地方调用它：|1011191|[self+disableUserInteractionForViewsUnderView:self.helpBackground];|1011192|编辑|offset|length|style|BOLD|1011193|我已经在github.com上创建了一个UIViewController分类要点。你可以在这里找到它：https://gist.github.com/alexcristea/0244b50e503e8bf4f25d|CODE|1011194|你可以这样使用它：|1011195|[self+enumerateViewsPlacedUnderView:self.helpBackground+usingBlock:%5E(UIView+*view)+{
++++if+([view+isKindOfClass:[UIButton+class]])+{
++++++++view.userInteractionEnabled+=+NO;
++++}
}];|1011196|entityMap|0|LINK|mutability|MUTABLE|url|https://gist.github.com/alexcristea/0244b50e503e8bf4f25d^0|0|0|0|0|0|2|0|K|G|1F|1K|0|0|0|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|17|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|18|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|19|8|@$M|1A|N|1B|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1C|8|@$M|1D|N|1E|O|S]]|9|@$M|1F|N|1G|1|1H]]|A|$]]|$1|T|3|U|5|6|7|1I|8|@]|9|@]|A|$]]|$1|V|3|W|5|D|7|1J|8|@]|9|@]|A|$E|F]]|$1|X|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|Y|$Z|$5|10|11|12|A|$13|14]]]]

You can create a method that disables user interaction for all views that are under your helpBackground:

<pre><code>- (void)disableUserInteractionForViewsUnderView:(UIView *)view
{
 CGRect area = view.frame;
 for (UIView *underView in [self.view subviews]) {
 if(CGRectContainsRect(area, underView.frame))
 underView.userInteractionEnabled = NO;
 }
}
</code></pre>

and after that you call it where you need it:

<pre><code>[self disableUserInteractionForViewsUnderView:self.helpBackground];
</code></pre>

EDIT

I've created a <code>UIViewController</code> category gist on github.com. You can find it here: <a href="https://gist.github.com/alexcristea/0244b50e503e8bf4f25d" rel="nofollow">https://gist.github.com/alexcristea/0244b50e503e8bf4f25d</a>

You can use it like this: 

<pre><code>[self enumerateViewsPlacedUnderView:self.helpBackground usingBlock:^(UIView *view) {
 if ([view isKindOfClass:[UIButton class]]) {
 view.userInteractionEnabled = NO;
 }
}];
</code></pre>

To show a help view I've put an UIImageView which behind has some UIButtons. How can I disable user interaction of these buttons? If I touch this image where buttons are behind, they responds to touch events.

CODE FOR IMAGE BACKGROUND:

<pre><code>self.helpBackground = [[UIImageView alloc] initWithFrame:CGRectMake(0, 0, 1024, 768)];
self.helpBackground.backgroundColor = [UIColor colorWithWhite:0 alpha:0.75];
self.helpBackground.hidden = YES;
[self.view addSubview:self.helpBackground];
</code></pre>

I've used self.helpBackground.userInteractionEnabled = NO; but didn't work.

Thanks.

Disable interaction for views behind background image

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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为了显示帮助视图，我放了一个后面有一些UIButtons的UIImageView。如何禁用这些按钮的用户交互？如果我触摸这张图片，按钮在后面，它们会响应触摸事件。图片背景代码：self.helpBackground = [[UIImageView alloc] initWithFrame:CGRectMake(0, 0...

问关闭背景图片背后视图的交互
EN

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问关闭背景图片背后视图的交互EN