blocks|key|839828|text|虽然我不明白为什么要以这种方式合并数组，但这里有一种按顺序合并数组的方法。因此，array1的第一个子级将与array2的第一个子级合并，依此类推。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|839829|<?php

$array1+=+[
++++[
++++++++'rank'+=>+579,
++++++++'id'+=>+1
++++],
++++[
++++++++'rank'+=>+251,
++++++++'id'+=>+2
++++]
];

$array2+=+[
++++[
++++++++'size'+=>+'S',
++++++++'rank'+=>+251
++++],
++++[
++++++++'size'+=>+'L',
++++++++'rank'+=>+579
++++]
];


foreach+($array1+as+$key+=>+&$data)+{
++++if+(isset($array2[$key]))+{
++++++++$data+=+array_merge($data,+$array2[$key]);++++
++++}
}

var_dump($array1);|code-block|syntax|javascript|839830|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

While I do not understand why you want to merge the arrays this way, here's a way to merge the arrays by their sequences. so the first child of array1 will be merged with the first child of array2 etc.

<pre><code>&lt;?php

$array1 = [
 [
 'rank' =&gt; 579,
 'id' =&gt; 1
 ],
 [
 'rank' =&gt; 251,
 'id' =&gt; 2
 ]
];

$array2 = [
 [
 'size' =&gt; 'S',
 'rank' =&gt; 251
 ],
 [
 'size' =&gt; 'L',
 'rank' =&gt; 579
 ]
];


foreach ($array1 as $key =&gt; &amp;$data) {
 if (isset($array2[$key])) {
 $data = array_merge($data, $array2[$key]); 
 }
}

var_dump($array1);
</code></pre>

blocks|key|3155843|text|未经测试，但这应该是可行的，或者至少让你更接近。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3155844|for+($array1+as+$key1+=>+$value1)+{
++++for+($array2+as+$key2+=>+$value2)+{
++++++++if+($value1['rank']+==+$value2['rank'])+{
++++++++++++$result[$key1]+=+[$value2['size'],+$value1['rank'],+$value1['id']];
++++++++};
++++};
};|code-block|syntax|javascript|3155845|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Untested, but this should work, or at least get you close.

<pre><code>for ($array1 as $key1 =&gt; $value1) {
 for ($array2 as $key2 =&gt; $value2) {
 if ($value1['rank'] == $value2['rank']) {
 $result[$key1] = [$value2['size'], $value1['rank'], $value1['id']];
 };
 };
};
</code></pre>

blocks|key|839848|text|foreach($arr1+as+$key1+=>+$data1){
++++foreach($arr2+as+$key2+=>+$data2){
++++++++if($data1['rank']==$data2['rank']){
++++++++++++$result[]+=+array_merge($data1,+$data2);
++++++++}
++++}
}
print_r($result);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|839849|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>foreach($arr1 as $key1 =&gt; $data1){
 foreach($arr2 as $key2 =&gt; $data2){
 if($data1['rank']==$data2['rank']){
 $result[] = array_merge($data1, $data2);
 }
 }
}
print_r($result);
</code></pre>

blocks|key|839851|text|//save+keys+of+ranks+in+the+1st+array
$keys+=+array();+
foreach($arr1+as+$k+=>+$v)
+++$keys[$v['rank']]+=+$k;

$res+=+array();
//+Walk+through+the+2nd+array+and+make+result
foreach($arr2+as+$k+=>+$v)+
+if+(isset($keys[$v['rank']]))+
++++$res[]+=+array_merge($arr1[$keys[$v['rank']]],+$v);

print_r($res);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|839852|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>//save keys of ranks in the 1st array
$keys = array(); 
foreach($arr1 as $k =&gt; $v)
 $keys[$v['rank']] = $k;

$res = array();
// Walk through the 2nd array and make result
foreach($arr2 as $k =&gt; $v) 
 if (isset($keys[$v['rank']])) 
 $res[] = array_merge($arr1[$keys[$v['rank']]], $v);

print_r($res);
</code></pre>

blocks|key|839892|text|看看你提供的数组，我假设你想使用键等级作为连接点(这似乎不是一个好主意，问题是它们是否唯一)如果它们是唯一的，那么一个很小的方法可以帮助根据它们的等级来获取元素，其余的只是组装结果：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|839893|<?php

$arr1+=+[
++++[
++++++++'rank'+=>+579,
++++++++'id'+=>+1
++++],
++++[
++++++++'rank'+=>+251,
++++++++'id'+=>+2
++++],
];

$arr2+=+[
++++[
++++++++'size'+=>+'S',
++++++++'rank'+=>+251
++++],
++++[
++++++++'size'+=>+'L',
++++++++'rank'+=>+579
++++],
];

function+getItemByRank($array,+$rank)
{
++++foreach+($array+as+$item){
++++++++if+($item['rank']+===+$rank)+{
++++++++++++return+$item;
++++++++}
++++}
}


$result+=+[];
foreach+($arr1+as+$k+=>+$item)+{

++++$match+=+getItemByRank($arr2,+$item['rank']);

++++if+(isset($match))+{
++++++++$result[$k]+=+$item;
++++++++$result[$k]['size']+=+$match['size'];
++++}
}

print_r($result);|code-block|syntax|javascript|839894|输出：|839895|Array
(
++++[0]+=>+Array
++++++++(
++++++++++++[rank]+=>+579
++++++++++++[id]+=>+1
++++++++++++[size]+=>+L
++++++++)

++++[1]+=>+Array
++++++++(
++++++++++++[rank]+=>+251
++++++++++++[id]+=>+2
++++++++++++[size]+=>+S
++++++++)

)|839896|entityMap^0|H|2|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

Looking at your provided arrays, I'm assuming you want to use the key rank as the joining point (which doesn't seems such a good idea, and question will be if their unique or not) if they are unique then a tiny method can help to fetch element based on their rank and the rest is just assembling the result :

<pre><code>&lt;?php

$arr1 = [
 [
 'rank' =&gt; 579,
 'id' =&gt; 1
 ],
 [
 'rank' =&gt; 251,
 'id' =&gt; 2
 ],
];

$arr2 = [
 [
 'size' =&gt; 'S',
 'rank' =&gt; 251
 ],
 [
 'size' =&gt; 'L',
 'rank' =&gt; 579
 ],
];

function getItemByRank($array, $rank)
{
 foreach ($array as $item){
 if ($item['rank'] === $rank) {
 return $item;
 }
 }
}


$result = [];
foreach ($arr1 as $k =&gt; $item) {

 $match = getItemByRank($arr2, $item['rank']);

 if (isset($match)) {
 $result[$k] = $item;
 $result[$k]['size'] = $match['size'];
 }
}

print_r($result);
</code></pre>

output:

<pre><code>Array
(
 [0] =&gt; Array
 (
 [rank] =&gt; 579
 [id] =&gt; 1
 [size] =&gt; L
 )

 [1] =&gt; Array
 (
 [rank] =&gt; 251
 [id] =&gt; 2
 [size] =&gt; S
 )

)
</code></pre>

I have tried to merge two different arrays into a single array. Can any one help me please?

i have array like this

<pre><code>[0] (Array)#2
 [rank] "579"
 [id] "1"
[1] (Array)#4
 [rank] "251"
 [id] "2"

[0] (Array)#2
 [size] "S"
 [rank] "251"
[1] (Array)#15
 [size] "L"
 [rank] "579"
</code></pre>

i need like this

<pre><code>[0] (Array)#2
 [size] "S"
 [rank] "251"
 [id] "1"
[1] (Array)#15
 [size] "L"
 [rank] "579"
 [id] "1"
</code></pre>

PHP merge arrays by value for 2 different array value

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我曾尝试将两个不同的数组合并为一个数组。有谁能帮帮我吗？我有这样的数组[0] (Array)#2  [rank] "579"  [id] "1"[1] (Array)#4  [rank] "251"  [id] "2"[0] (Array)#2  [size] "S"  [rank] "251"[1] (Array)#...

问PHP按值合并2个不同数组值的数组
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问PHP按值合并2个不同数组值的数组EN