我在动态属性的选择器中遇到了css counter-reset的问题,但只在Safari浏览器中。
<p numbered="1">para</p>
<p numbered="1">para</p>
<p numbered="1">para</p>
<p numbered="1">para</p>
<p numbered="1" id="test" restart-numbering="true">para</p>
<p numbered="1">para</p>
<br><br><br>
<button onclick='toggle()'>
Toggle
</button>js:
function toggle() {
let el = document.querySelector('#test');
let restarting = !!el.getAttribute('restart-numbering');
if (restarting) {
el.removeAttribute('restart-numbering');
} else {
el.setAttribute('restart-numbering', true);
}
}css:
p[numbered="1"] {
counter-increment: numbered1;
}
p[numbered="1"]:before {
content: counter(numbered1)'.';
}
p[numbered="1"][restart-numbering="true"] {
counter-reset: numbered1;
}第一次加载时,段落编号会正确重置:1、2、3、4、1、2
按toggle按钮两次,这将把html带到原始状态,并得到1,2,3,4,4,5
发布于 2019-02-27 00:36:17
找到相关的S.O.帖子:How can I force WebKit to redraw/repaint to propagate style changes?
似乎为了快速和高效,浏览器有时会在评估CSS时走捷径。使用这篇文章的答案,我们可以修改小提琴来切换容器div上的一些道具,让浏览器更深入地评估CSS:
html:
<div id="container">
<p numbered="1">para</p>
<p numbered="1">para</p>
<p numbered="1">para</p>
<p numbered="1">para</p>
<p numbered="1" id="test" restart-numbering="true">para</p>
<p numbered="1">para</p>
</div>js:
function toggle() {
let el = document.querySelector('#test');
let restarting = !!el.getAttribute('restart-numbering');
if (restarting) {
el.removeAttribute('restart-numbering');
} else {
el.setAttribute('restart-numbering', true);
}
let ctr = document.querySelector('#container');
ctr.style.display='none';
ctr.offsetHeight; // no need to store this anywhere, the reference is enough
ctr.style.display='';
}Here's the updated fiddle
https://stackoverflow.com/questions/54822993
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