blocks|key|1176306|text|你可以这样做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1176307|1176308|var+JSONObject+=+{"results":[{"Name":"Pini","ID":"111"},
++++++++++++++++++{"Name":"Yaniv","ID":"123"},
+++++++++++++++++++++++++++++{"Name":"Yoni","ID":"145"}]};


var+Users=+[];

$.each(JSONObject.results,+function(i,+obj)
+++++++{
++++alert(obj.Name);
++++alert(obj.ID);
++++Users.push([obj.Name,+obj.ID]);
});​|code-block|syntax|javascript|1176309|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|K|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|L|8|@]|9|@]|A|$F|G]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

You can do like this

<h2><a href="http://jsfiddle.net/zZsW6/" rel="nofollow">JsFiddler Demo of below code</a></h2>

<pre><code>var JSONObject = {"results":[{"Name":"Pini","ID":"111"},
 {"Name":"Yaniv","ID":"123"},
 {"Name":"Yoni","ID":"145"}]};


var Users= [];

$.each(JSONObject.results, function(i, obj)
 {
 alert(obj.Name);
 alert(obj.ID);
 Users.push([obj.Name, obj.ID]);
});​
</code></pre>

blocks|key|3465255|text|我认为应该是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3465256|var+ret+=+[];

for+(var+i+=+0;+i+<+js.length;+i%2B%2B)+{
++++ret.push([js[i].Name,+js[i].ID]);
}

//+ret+holds+your+array+of+arrays|code-block|syntax|javascript|3465257|或者类似这样的东西：|3465258|var+ret+=+$.map(js,+function+(el,+i)+{
++++return+[[el.Name,+el.ID]];
});|3465259|两者都有的一个例子：http://jsfiddle.net/RNY8M/|offset|length|3465260|entityMap|0|LINK|mutability|MUTABLE|url|http://jsfiddle.net/RNY8M/^0|0|0|0|0|A|Q|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

I think something like this:

<pre><code>var ret = [];

for (var i = 0; i &lt; js.length; i++) {
 ret.push([js[i].Name, js[i].ID]);
}

// ret holds your array of arrays
</code></pre>

Or something like:

<pre><code>var ret = $.map(js, function (el, i) {
 return [[el.Name, el.ID]];
});
</code></pre>

An example of both: <a href="http://jsfiddle.net/RNY8M/" rel="nofollow">http://jsfiddle.net/RNY8M/</a>

blocks|key|1148905|text|对于这种转换，我总是更喜欢使用，它是一个实用工具库(主要用于对象/数组转换)。我认为它提供了很好的功能，使生活更容易，允许javascript开发人员更有生产力的，并为结果代码实现更好的易读性。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1148906|下面是带下划线(扩展)的解决方案：|1148907|var+js=[{"Name":"Pini","ID":"111"},++
++++++++{"Name":"Yaniv","ID":"123"},++++
++++++++{"Name":"Yoni","ID":"145"}]

var+names+=+_.pluck(js,+'Name');
var+ids+=+_.pluck(js,+'ID');

var+result+=+_.zip(names,+ids)|code-block|syntax|javascript|1148908|你就会得到你想要的结果：|1148909|[['Pini',111],['Yaniv',123],['Yoni',145]]|1148910|带有下划线的单行解决方案：|1148911|var+result+=+_.zip(_.pluck(js,+'Name'),+_.pluck(js,+'ID'))|1148912|希望它能帮上忙！|1148913|entityMap^0|K|5|23|6|2L|3|0|0|0|0|0|8|4|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|15|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|16|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|17|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|18|8|@]|D|@]|E|$K|L]]|$1|Q|3|R|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|S|3|T|5|J|7|1C|8|@]|D|@]|E|$K|L]]|$1|U|3|V|5|6|7|1D|8|@]|D|@]|E|$]]|$1|W|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]]|X|$]]

For this kind of transformations I always prefer using <a href="http://underscorejs.org" rel="nofollow">UnderscoreJs</a> which is an utility-belt library (mainly for object/array transformations) for Javascript. I think that it provides great functions that make life easier, allowing javascript developers to be more productive and to achieve a better legibility for the resulting code.

Here is the solution with underscore (extended):

<pre><code>var js=[{"Name":"Pini","ID":"111"}, 
 {"Name":"Yaniv","ID":"123"}, 
 {"Name":"Yoni","ID":"145"}]

var names = _.pluck(js, 'Name');
var ids = _.pluck(js, 'ID');

var result = _.zip(names, ids)
</code></pre>

And you achive the desired result:

<pre><code>[['Pini',111],['Yaniv',123],['Yoni',145]]
</code></pre>

Solution in one line with underscorejs:

<pre><code>var result = _.zip(_.pluck(js, 'Name'), _.pluck(js, 'ID'))
</code></pre>

Hope it helps!

blocks|key|1170224|text|我更正了我的解决方案，我没有仔细阅读规范(我的错)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1170225|var+jsonArray+=+[{"Name":"Pini","ID":"111"},+{"Name":"Yaniv","ID":"123"},+{"Name":"Yoni","ID":"145"}];

var+jsonConverted+=+{};
$(jsonArray).each(+function()+{
++++jsonConverted.push([+this.Name,+this.ID+]);
});|code-block|syntax|javascript|1170226|此解决方案使用jQuery。|1170227|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I correct my solution, I hadn't read well the specs (my fault):

<pre><code>var jsonArray = [{"Name":"Pini","ID":"111"}, {"Name":"Yaniv","ID":"123"}, {"Name":"Yoni","ID":"145"}];

var jsonConverted = {};
$(jsonArray).each( function() {
 jsonConverted.push([ this.Name, this.ID ]);
});
</code></pre>

This solution uses jQuery.

blocks|key|1148951|text|这是一个适用于简单对象的解决方案(但不适用于深层对象……但我将把它留给您来实现)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1148952|http://jsfiddle.net/eUtkC/|offset|length|1148953|var+js+=+[{
++++"Name":+"Pini",
++++"ID":+"111"},
{
++++"Name":+"Yaniv",
++++"ID":+"123"},
{
++++"Name":+"Yoni",
++++"ID":+"145"}]

function+obj2arr(obj)+{
++++var+i,+key,+length+=+obj.length,
++++++++aOutput+=+[],
++++++++aObjValues;
++++for+(i+=+length+-+1;+i+>=+0;+i--)+{
++++++++aObjValues+=+[];
++++++++for+(key+in+obj[i])+{
++++++++++++if+(obj[i].hasOwnProperty(key))+{
++++++++++++++++aObjValues.push(obj[i][key]);
++++++++++++}
++++++++}
++++++++aOutput.push(aObjValues);
++++}
++++return+aOutput;
}

document.write(JSON.stringify(obj2arr(js)))​|code-block|syntax|javascript|1148954|编辑|style|BOLD|1148955|这是一个使用Array.prototype.map的版本|CODE|1148956|http://jsfiddle.net/eUtkC/1/|1148957|function+obj2arr(obj)+{
++++var+key,+aOutput+=+[];
++++for+(key+in+obj)+{
++++++++if+(obj.hasOwnProperty(key))+{
++++++++++++aOutput.push(obj[key]);
++++++++}
++++}
++++return+aOutput;
}

document.write(JSON.stringify(js.map(obj2arr)))​|1148958|entityMap|0|LINK|mutability|MUTABLE|url|1^0|0|0|Q|0|0|0|0|2|0|6|J|0|0|S|1|0|0^^$0|@$1|2|3|4|5|6|7|13|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|14|8|@]|9|@$D|15|E|16|1|17]]|A|$]]|$1|F|3|G|5|H|7|18|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|19|8|@$D|1A|E|1B|M|N]]|9|@]|A|$]]|$1|O|3|P|5|6|7|1C|8|@$D|1D|E|1E|M|Q]]|9|@]|A|$]]|$1|R|3|S|5|6|7|1F|8|@]|9|@$D|1G|E|1H|1|1I]]|A|$]]|$1|T|3|U|5|H|7|1J|8|@]|9|@]|A|$I|J]]|$1|V|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]]|W|$X|$5|Y|Z|10|A|$11|C]]|12|$5|Y|Z|10|A|$11|S]]]]

Here's a solution that will work for a simple object (not deep objects, though.... but I'll leave that for you to implement).

<a href="http://jsfiddle.net/eUtkC/" rel="nofollow">http://jsfiddle.net/eUtkC/</a>

<pre><code>var js = [{
 "Name": "Pini",
 "ID": "111"},
{
 "Name": "Yaniv",
 "ID": "123"},
{
 "Name": "Yoni",
 "ID": "145"}]

function obj2arr(obj) {
 var i, key, length = obj.length,
 aOutput = [],
 aObjValues;
 for (i = length - 1; i &gt;= 0; i--) {
 aObjValues = [];
 for (key in obj[i]) {
 if (obj[i].hasOwnProperty(key)) {
 aObjValues.push(obj[i][key]);
 }
 }
 aOutput.push(aObjValues);
 }
 return aOutput;
}

document.write(JSON.stringify(obj2arr(js)))​
</code></pre>

EDIT

Here's a version using <code>Array.prototype.map</code>:

<a href="http://jsfiddle.net/eUtkC/1/" rel="nofollow">http://jsfiddle.net/eUtkC/1/</a>

<pre><code>function obj2arr(obj) {
 var key, aOutput = [];
 for (key in obj) {
 if (obj.hasOwnProperty(key)) {
 aOutput.push(obj[key]);
 }
 }
 return aOutput;
}

document.write(JSON.stringify(js.map(obj2arr)))​
</code></pre>

I have the json string like,

<pre><code>string js=[{"Name":"Pini","ID":"111"},

{"Name":"Yaniv","ID":"123"},

{"Name":"Yoni","ID":"145"}]
</code></pre>

And I need to convert this into like the following format using java script.

<pre><code>[['Pini',111],['Yaniv',123],['Yoni',145]]
</code></pre>

How to convert the json string into javascript array using javascript function?

How to convert json to java script array?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有这样的json字符串，string js=[{"Name":"Pini","ID":"111"},{"Name":"Yaniv","ID":"123"},{"Name":"Yoni","ID":"145"}]我需要使用java脚本将其转换为如下格式。[['Pini',111],['Yaniv',123],['Yon...

问如何将json转换为java script数组？
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问如何将json转换为java script数组？EN