blocks|key|3490201|text|您可以单独检查单词。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3490202|regexp_checks+=+[/Filton/i,+/Grove/i,+/Bristol/i]
array.all?+{+%7Ca%7C+regexp_checks.all?{%7Crgx%7C+a+=~+rgx}+}|code-block|syntax|javascript|3490203|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could check for words separately.

<pre><code>regexp_checks = [/Filton/i, /Grove/i, /Bristol/i]
array.all? { |a| regexp_checks.all?{|rgx| a =~ rgx} }
</code></pre>

blocks|key|4959305|text|你也可以通过这种方式签到..|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4959306|regexp_checks+=+[/Filton.*?Grove.*?Bristol/i]
array.all?+{+%7Ca%7C+regexp_checks.all?{%7Crgx%7C+a+=~+rgx}+}|code-block|syntax|javascript|4959307|注意：仅当您想要保持单词的显示顺序时才使用此选项。如果顺序很重要，并且中间不允许有其他单词..您可以使用|offset|length|style|BOLD|4959308|regexp_checks+=+[/Filton\W%2BGrove\W%2BBristol/i]|CODE|4959309|entityMap^0|0|0|0|3|0|0|19|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|T|8|@$I|U|J|V|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|W|8|@$I|X|J|Y|K|O]]|9|@]|A|$]]|$1|P|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|Q|$]]

You could also check in this way.. 

<pre><code>regexp_checks = [/Filton.*?Grove.*?Bristol/i]
array.all? { |a| regexp_checks.all?{|rgx| a =~ rgx} }
</code></pre>

Note: Use this only if you want to maintain the order of words appearing.
And if order is important and no other words should be allowed in between.. you can use 
 <code>regexp_checks = [/Filton\W+Grove\W+Bristol/i]</code>

blocks|key|4959325|text|尝试执行以下正则表达式|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4959326|regexp+=+/Filton+Grove,?\s*Bristol/i|offset|length|style|CODE|4959327|您不需要在您的正则表达式中使用%5E。|4959328|entityMap^0|0|0|10|0|F|1|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@$D|N|E|O|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|J|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|K|$]]

Try the following regex 

<code>regexp = /Filton Grove,?\s*Bristol/i</code>

You do not need the <code>^</code> in your regex.

blocks|key|3490280|text|如果这三个词必须按特定顺序出现，请尝试这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3490281|regexp+=+/Filton[,\s]%2BGrove[,\s]%2BBristol/i|code-block|syntax|javascript|3490282|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If the three words must be in the specific sequence, try this:

<pre><code>regexp = /Filton[,\s]+Grove[,\s]+Bristol/i
</code></pre>

blocks|key|4959351|text|适用于所有可能的用例|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4959352|regexp+=+/Filton[\s,\s]*Grove[\s,\s]*Bristol/i|code-block|syntax|javascript|4959353|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For all possible use cases

<pre><code>regexp = /Filton[\s,\s]*Grove[\s,\s]*Bristol/i
</code></pre>

Say I have the following array of addresses

<pre><code>array = ["1 New Street, Filton Grove, Bristol BD7 0AA", "2 New Street, Filton Grove, Bristol BD7 0AA", "3 New Street, Filton Grove, Bristol BD7 0AA"]
</code></pre>

I would like to check that each item in the array contains the words <code>Filton Grove Bristol</code>, but as there are commas within the address is is throwing me slightly.

How do I ignore the commas and check that each word exists in each iteration of the array

So far I have this

<pre><code>regexp = /^Filton Grove Bristol/i
array.all? { |a| regex =~ a }
</code></pre>

But this fails.

Regexp to match multiple Strings - Ruby

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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假设我有以下地址数组array = ["1 New Street, Filton Grove, Bristol BD7 0AA", "2 New Street, Filton Grove, Bristol BD7 0AA", "3 New Street, Filton Grove, Bristol BD7 0AA"]我...

问匹配多个字符串的Regexp - Ruby
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