blocks|key|1190115|text|由于您只是删除了application/application/src目录，因此没有理由使用find等。你所需要做的就是：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1190116|rm+-rf+application/application/src|code-block|syntax|javascript|1190117|剩余：|BOLD|1190118|application/application/logs/l2.txt
application/application/logs/l1.txt
application/application/config/c1.conf
application/application/config/c2.conf|1190119|entityMap^0|8|R|0|0|2|1|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|U|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|V|8|@$9|W|A|X|B|M]]|D|@]|E|$]]|$1|N|3|O|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|P|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|Q|$]]

Since you are just deleting the <code>application/application/src</code> dir, there is no reason to use find, etc.. All you need to do is:

<pre><code>rm -rf application/application/src
</code></pre>

remaining:

<pre><code>application/application/logs/l2.txt
application/application/logs/l1.txt
application/application/config/c1.conf
application/application/config/c2.conf
</code></pre>

blocks|key|1197549|text|据我所知，除了src，还有很多其他的文件夹，因为如果不这样的话，你只会使用rm+-rf+src。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1197550|如果您的PWD是application，即您在config+logs和src的父目录中，那么您只需要一种方法来对除config和log之外的所有文件/文件夹使用rm+-rf，那么为什么不创建一个for循环呢？|1197551|++++#!/bin/bash

++++cd+"/path/to/application"

++++for+file+in+*+;+do
++++++++++++case+"$file"+in
++++++++++++++++++++config+)
++++++++++++++++++++++++++++echo+"file+is+$file:+doing+nothing"
++++++++++++++++++++;;
++++++++++++++++++++logs+)
++++++++++++++++++++++++++++echo+"file+is+$file:+doing+nothing"
++++++++++++++++++++;;
++++++++++++++++++++*+)
++++++++++++++++++++++++++++echo+"file+is+$file:+removing"
++++++++++++++++++++++++++++rm+-rf+"$file"
++++++++++++++++++++;;
++++++++++++++++++++esac
++++++++++++done
++++exit+0|code-block|syntax|javascript|1197552|entityMap^0|7|3|11|A|0|4|3|8|B|N|6|U|4|Z|3|1L|6|1S|3|28|6|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|1A|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|N|$]]

From what I gather, there's a bunch of other folders other than <code>src</code> because otherwise you would just use <code>rm -rf src</code>.

If your <code>PWD</code> is <code>application</code>, i.e. you're in the parent directory of <code>config</code> <code>logs</code> and <code>src</code>, you just need a way to use <code>rm -rf</code> on all files/folders except <code>config</code> and <code>log</code>, so why not make a for loop?

<pre><code> #!/bin/bash

 cd "/path/to/application"

 for file in * ; do
 case "$file" in
 config )
 echo "file is $file: doing nothing"
 ;;
 logs )
 echo "file is $file: doing nothing"
 ;;
 * )
 echo "file is $file: removing"
 rm -rf "$file"
 ;;
 esac
 done
 exit 0
</code></pre>

blocks|key|4975365|text|这必须行得通：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4975366|find+./application+-depth+-mindepth+1+-type+d+\
++-regextype+posix-extended+!+-regex+".*\/(config%7Clogs).*"+%7C+\
++-exec+rm+-fr+{}++\;|code-block|syntax|javascript|4975367|或者在xargs中，如果您没有包含换行符的文件夹名称，您可以这样写：|offset|length|style|CODE|4975368|find+./application+-depth+-mindepth+1+-type+d+\
++-regextype+posix-extended+!+-regex+".*\/(config%7Clogs).*"+%7C+\
++xargs+-t+-I+{}+rm+-fr+{}|4975369|或者，对于xargs，如果您的文件夹名称中包含换行符，则可以使用：|4975370|find+./application+-depth+-mindepth+1+-type+d+\
++-regextype+posix-extended+!+-regex+".*\/(config%7Clogs).*"+-print0+%7C+\
++xargs+-0+-t+-I+{}+rm+-fr+{}|4975371|4975372|find将查找./application下的所有目录(包含/config和/logs的目录除外)，并从运行lowest|unordered-list-item|4975373|xargs开始打印这些目录，删除目录|4975374|4975375|entityMap^0|0|0|3|5|0|0|5|5|0|0|0|0|4|7|D|T|7|11|5|0|0|5|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|13|8|@$I|14|J|15|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|17|8|@$I|18|J|19|K|L]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1A|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]|$1|T|3|U|5|V|7|1C|8|@$I|1D|J|1E|K|L]|$I|1F|J|1G|K|L]|$I|1H|J|1I|K|L]|$I|1J|J|1K|K|L]]|9|@]|A|$]]|$1|W|3|X|5|V|7|1L|8|@$I|1M|J|1N|K|L]]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1O|8|@]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|1P|8|@]|9|@]|A|$]]]|10|$]]

This must work:

<pre><code>find ./application -depth -mindepth 1 -type d \
 -regextype posix-extended ! -regex ".*\/(config|logs).*" | \
 -exec rm -fr {} \;
</code></pre>

Or with <code>xargs</code> if you don't have folder names with newlines in them you can write:

<pre><code>find ./application -depth -mindepth 1 -type d \
 -regextype posix-extended ! -regex ".*\/(config|logs).*" | \
 xargs -t -I {} rm -fr {}
</code></pre>

Or with <code>xargs</code> if you have folder names with newlines in them you can use:

<pre><code>find ./application -depth -mindepth 1 -type d \
 -regextype posix-extended ! -regex ".*\/(config|logs).*" -print0 | \
 xargs -0 -t -I {} rm -fr {}
</code></pre>

<ul>
<li><code>find</code> finds all directories below <code>./application</code> excluding those that have <code>/config</code> and <code>/logs</code> and prints them starting with the lowest</li>
<li><code>xargs</code> runs removing the directory</li>
</ul>

blocks|key|1190217|text|cd+application
find+.+-type+d+%7C+egrep+-v+'(%5E\./$%7C%5E\./log%7C%5E\./config)'+%7C+while+read+DIR
do
+++echo+rm+-rf+$DIR
done|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1190218|这使用find列出所有目录，通过grep管道排除我们想要保留的目录(也排除"./“，这将是PWD)，并将过滤后的列表管道到执行删除的while循环。我把"echo“放在里面，这样你就可以测试它是否能达到你真正想要的效果。如果你很高兴，那就去掉回声。如果返回的列表(DIR)按树顺序排列，例如d1、d1/d1a、d1/d1b，并且rm+-rf+d1会删除较低的文件夹，则您可能希望在rm+-rf周围添加"if+-d+$DIR“。|unstyled|1190219|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>cd application
find . -type d | egrep -v '(^\./$|^\./log|^\./config)' | while read DIR
do
 echo rm -rf $DIR
done
</code></pre>

This uses find to list all the directories, pipes through grep to exclude the ones we want to keep (also to exclude "./" which would be the PWD), and pipes that filtered list to the while loop which does the delete. I've put the "echo" in there so you can test if this does what you actually want. If you're happy then remove the echo. SInce the the returned list (DIR) would be in tree order, e.g. d1, d1/d1a, d1/d1b, and rm -rf d1 would remove the lower folders, you might want to add a "if [ -d $DIR ]" around the rm -rf.

blocks|key|1191509|text|使用Bash：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1191510|for+file+in+applications/*;+do
++++target="${file#*/}"
++++if+[[+$target+!=+config+&&+$target+!=+logs+]];+then
++++++++rm+-rf+"$file"
++++fi
done|code-block|syntax|javascript|1191511|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Using Bash:

<pre><code>for file in applications/*; do
 target="${file#*/}"
 if [[ $target != config &amp;&amp; $target != logs ]]; then
 rm -rf "$file"
 fi
done
</code></pre>

blocks|key|4975473|text|不需要复杂的find命令，只需使用外壳(假设您在应用程序文件夹中)：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4975474|rm+-r+!(logs%7Cconfig)|code-block|syntax|javascript|4975475|这在man+bash中称为“路径名扩展”|4975476|4975477|++++++!(pattern-list)+++++++++++++++++Matches+anything+except+one+of+the+given+patterns|blockquote|4975478|4975479|entityMap^0|6|4|0|0|2|8|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|W|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|X|8|@$9|Y|A|Z|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|10|8|@]|D|@]|E|$]]|$1|N|3|O|5|P|7|11|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|12|8|@]|D|@]|E|$]]|$1|R|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|S|$]]

There is no need for complicated <code>find</code> commands, just use the shell (assuming you are in the application folder):

<pre><code>rm -r !(logs|config)
</code></pre>

This is referred to as "Pathname Expansion", from <code>man bash</code>

<blockquote>
<pre><code> !(pattern-list)
 Matches anything except one of the given patterns
</code></pre>
</blockquote>

I am trying to write maintainer scripts for <code>debian</code> package.
Assume that I have a directory structure as follows:

<pre><code>application/
----application/file1.txt
----application/file2.txt
----application/config
--------application/config/c1.conf
--------application/config/c2.conf
----application/logs
--------application/logs/l1.txt
--------application/logs/l2.txt
----application/src
--------application/src/static/
------------application/src/static/js
------------application/src/static/css
--------application/src/s1.py
--------application/src/s2.py
----application/lib
--------application/src/js/
--------application/src/css/
</code></pre>

Now I want to delete all the files/folders except <code>config</code> and <code>logs</code> (in this case, <code>src</code> and <code>lib</code> folders, and <code>file1.txt</code> and <code>file2.txt</code> files). My <code>PWD</code> is currently a parent of <code>appliaction/</code> dir (i.e., I can see <code>application</code> in my <code>PWD</code>).

What command should I use (a small <code>bash script</code> would be great)? (I tried with <code>rm -rf</code> with some options but mistakenly deleted other files, so I would like to know the correct answer before trying anything else!)

How to delete all the files/folders from the folder except few folders?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在尝试为debian包编写维护脚本。假设我有一个如下的目录结构：application/----application/file1.txt----application/file2.txt----application/config--------application/config/c1.conf--------...

问如何删除文件夹中除少数文件夹以外的所有文件/文件夹？
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问如何删除文件夹中除少数文件夹以外的所有文件/文件夹？EN