blocks|key|1431892|text|您可以做的是在空格上拆分它，然后遍历每个子字符串，并检查它是否以某个特殊分隔符开头。如果是，则开始一个新字符串，并追加后续字符串，直到到达末尾分隔符。然后删除这些子字符串并将其替换为新的子字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1431893|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

What you could do is split it on the spaces, then go through each substring and check if it starts with one of the special delimiters. If it does, start a new string and append subsequent strings until you get to the end delimiter. Then remove those substrings and replace them with the new one.

blocks|key|1659464|text|我想你想要的是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1659465|import+re
re.split(r"(?<=\])+%7C+(?=\$%7C\[)",+"auth-server+$na+me$+$1n+ame$+[position+[$pr+io$]]+xxxx+[match-fqdn+[[$fq+dn$]+[all]]]")|code-block|syntax|javascript|1659466|这就产生了|1659467|['auth-server',+'$na+me$',+'$1n+ame$',+'[position',+'[$pr+io$]]',+'xxxx',+'[match-fqdn',+'[[$fq+dn$]',+'[all]]]']|1659468|但是请注意，这并不完全是您所描述的，而是与您的示例相匹配的。当空格前面是]或后面是$或[时，您似乎想要在空格上拆分。|offset|length|style|CODE|1659469|entityMap^0|0|0|0|0|10|1|15|1|17|1|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]|$M|Z|N|10|O|P]|$M|11|N|12|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|R|$]]

I think what you want is

<pre><code>import re
re.split(r"(?&lt;=\]) | (?=\$|\[)", "auth-server $na me$ $1n ame$ [position [$pr io$]] xxxx [match-fqdn [[$fq dn$] [all]]]")
</code></pre>

This yields

<pre><code>['auth-server', '$na me$', '$1n ame$', '[position', '[$pr io$]]', 'xxxx', '[match-fqdn', '[[$fq dn$]', '[all]]]']
</code></pre>

Note however that this is not exactly what you described, but what matches your example. It seems that you want to split on spaces when they are preceded by <code>]</code> or followed by <code>$</code> or <code>[</code>.

blocks|key|1659480|text|不是一个完整的答案，但我使用了regexp搜索...|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1659481|a+=+"auth-server+$na+me$+$1n+ame$+[position+[$pr+io$]]+xxxx+[match-fqdn+[[$fq+dn$]+[all]]]"
m+=+re.search('\$.*\$',+a)|code-block|syntax|javascript|1659482|把它和a.split()结合起来，我们就可以做数学运算了。|1659483|entityMap^0|F|6|0|0|3|9|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

Not quite a full answer, but I used <code>regexp</code> search...

<pre><code>a = "auth-server $na me$ $1n ame$ [position [$pr io$]] xxxx [match-fqdn [[$fq dn$] [all]]]"
m = re.search('\$.*\$', a)
</code></pre>

combine this with <code>a.split()</code> and we can do the math...

blocks|key|3975594|text|试试re.split和一个能让人痛哭的正则表达式|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3975595|import+re
print+re.split(r'(\$[%5E\$]%2B\$%7C\[\S%2B([%5E\]]%2B\]\])?%7C[-0-9a-zA-Z]%2B)',"auth-server+$na+me$+$1n+ame$+[position+[$pr+io$]]+xxxx+[match-fqdn+[[$fq+dn$]+[all]]]")|code-block|syntax|javascript|3975596|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

try re.split and a regex who make someone cry blood

<pre><code>import re
print re.split(r'(\$[^\$]+\$|\[\S+([^\]]+\]\])?|[-0-9a-zA-Z]+)',"auth-server $na me$ $1n ame$ [position [$pr io$]] xxxx [match-fqdn [[$fq dn$] [all]]]")
</code></pre>

blocks|key|1659512|text|考虑使用pyparsing|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1659513|from+pyparsing+import+*
enclosed+=+Forward()
nestedBrackets+=+nestedExpr('[',+']')+
enclosed+<<+(+Combine(Group(Optional('$')+%2B+Word(alphas)+%2B+Optional('$')))+%7C+nestedBrackets+)
print+enclosed.parseString(data).asList()|code-block|syntax|javascript|1659514|输出：|1659515|[['auth-server',+'$na',+'me$',+'$1n',+'ame$',+['position',+['$pr',+'io$']],+'xxxx',+
+['match-fqdn',+[['$fq',+'dn$'],+['all']]]]]|1659516|entityMap|0|LINK|mutability|MUTABLE|url|http://pyparsing.wikispaces.com/HowToUsePyparsing^0|4|9|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

consider using <a href="http://pyparsing.wikispaces.com/HowToUsePyparsing" rel="nofollow">pyparsing</a>:

<pre><code>from pyparsing import *
enclosed = Forward()
nestedBrackets = nestedExpr('[', ']') 
enclosed &lt;&lt; ( Combine(Group(Optional('$') + Word(alphas) + Optional('$'))) | nestedBrackets )
print enclosed.parseString(data).asList()
</code></pre>

output:

<pre><code>[['auth-server', '$na', 'me$', '$1n', 'ame$', ['position', ['$pr', 'io$']], 'xxxx', 
 ['match-fqdn', [['$fq', 'dn$'], ['all']]]]]
</code></pre>

I have a following input : 

<pre><code>"auth-server $na me$ $1n ame$ [position [$pr io$]] xxxx [match-fqdn [[$fq dn$] [all]]]"
</code></pre>

I need to store them in a list with <code>$</code>, <code>&lt;</code>, and <code>&gt;</code> serving as delimiters.

Expected output:

<pre><code>['auth-server', '$na me$', '$1n ame$', '[position', '[$pr io$]]', 'xxxx', '[match-fqdn', '[[$fq dn$]', '[all]]]']
</code></pre>

How can I do this?

Python : splitting string with multiple characters

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有以下输入："auth-server $na me$ $1n ame$ [position [$pr io$]] xxxx [match-fqdn [[$fq dn$] [all]]]"我需要将它们存储在一个列表中，并使用$、<和>作为分隔符。预期输出：['auth-server', '$na me$', '$1n ...

问Python :使用多个字符拆分字符串
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