blocks|key|4015299|text|单击submit按钮时设置一个标志，单击release按钮时清除该标志。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4015300|根据您的体系结构，标志可以是代码中的布尔变量、数据库中某处的特殊条目或临时文件中的任何内容。|4015301|单击submit按钮时，检查该标志是否已设置。如果是，则返回一条错误消息，指出该页正忙。|4015302|在伪代码中：|4015303|if+(flagIsSet())+{
++showPageIsBusy();
}+else+{
++setFlag();
++startBatchFile();
}|code-block|syntax|javascript|4015304|请记住，当批处理文件完成或单击release按钮并位于finally块中的某个位置时，要清除该标志。|offset|length|style|CODE|4015305|您还必须确保只有启动批处理文件的客户端才能释放它并清除该标志。|4015306|正如Avi在评论中指出的那样，您还应该记住同步对标志的访问。|4015307|entityMap^0|0|0|0|0|0|R|7|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|11|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@$O|14|P|15|Q|R]]|9|@]|A|$]]|$1|S|3|T|5|6|7|16|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|17|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

Set a flag when the submit button is clicked and clear it when the release button is clicked.

Depending on your architecture, the flag can be anything from a boolean variable in your code, a special entry somewhere in your database to a temporary file.

When the submit button is clicked, check whether the flag is already set. When it is, return an error message stating that the page is busy.

In pseudo code:

<pre><code>if (flagIsSet()) {
 showPageIsBusy();
} else {
 setFlag();
 startBatchFile();
}
</code></pre>

Remember to clear the flag when the batch file finishes or the release button is clicked and somewhere in a <code>finally</code> block.

You also have to make sure that only the client who started the batch file can release it and clear the flag.

As pointed out by Avi in the comments, you should also remember to synchronize access to the flag.

blocks|key|5484127|text|伪算法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5484128|修改批处理文件以在批处理操作之前和之后运行servlet。|5484129|在运行批处理文件之前，设置将注册正在执行的文件或数据库或会话变量的servlet或标志，并在批处理文件完成时设置将注册正在释放的文件或数据库或会话变量的servlet或标志|5484130|当用户单击release按钮时，运行将重新发布标志的同一个servlet。|5484131|当用户提交submit按钮时，检查该标志是已执行还是已释放，这取决于您向客户端发出的警报。|5484132|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|N|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|O|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|P|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|K|$]]

Pseudo algorithm:

Modify the batch file to run a servlet before and after batch operations.

Before running batch file, set a servlet or flag that will register a file or database or a session variable that I am being executed and at completion of batch file, set a servlet or flag that will register a file or database or a session variable that I am being released

When user clicks release button, run the same servlet which will relase the flag.

When User submits submit button, check for that flag whether it is executed or released, depending upon you alert your client.

blocks|key|1451287|text|您可以在servlet类中使用一个字段(否则是一个大的nono+)作为标志。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1451288|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

you could use a field in servlet class (a big nono otherwise) for a flag.

blocks|key|4015401|text|如果您的应用程序碰巧在多个负载平衡的服务器上运行，那么您将面临与我相同的问题:)我之前提交了一个关于它的问题，但不幸的是我没有得到任何响应。在任何情况下，您都可以将我对该问题的解决方案看作是对my+question+here的一个回答。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4015402|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/560710/simple-database-based-instance-synchronization^0|2O|G|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

If your application happens to run on multiple load-balanced servers, then you face the same problem I do :) I submitted a question earlier about it, but unfortunately I didn't get any response. In any case, you can see my solution for the problem as an answer to <a href="https://stackoverflow.com/questions/560710/simple-database-based-instance-synchronization">my question here</a>.

blocks|key|1699106|text|这是一个单例或更好的应用程序Bean。这个Bean应该启动你的长时间运行的后台任务，并提供有关它的信息，例如，它是否正在运行，以及它何时开始的，谁启动的，如果你可以，那么你可以显示一个进度条。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1699107|如果您能告诉我们，您使用的是什么web应用程序框架，我想我们可以给出更好的提示。|1699108|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

That is a Singleton or better an Application-Bean. This Bean should kick of your long running background task and provide information about it, e.g. if it is running and maybe stuff like when did it start, who started it and if you could the progress, so you could display a progress bar as well.

If you would tell us, what web application framework you use, we could give better tips, I think.

My requirements are as follows.

I have a web application developed in java.

I have a link in the html page. When the first client clicks submit button in the html page the batch file should run.

Meanwhile when the other client clicks the submit button he should get message that the page is busy.

If the first client clicks release button then the other clients must be able to run the batch file.

How can I do that?

Access by one client at a time

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我的要求如下。我有一个用java开发的web应用程序。我在html页面上有个链接。当第一个客户端单击html页面中的submit按钮时，批处理文件应该会运行。同时，当另一个客户端单击submit按钮时，他应该会得到页面正忙的消息。如果第一个客户端单击release按钮，则其他客户端必须能够运行批处理文件。我该怎么做呢？

问一次由一个客户端访问
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