blocks|key|2266642|text|通过指定folder/*.cpp，您将告诉g%2B%2B在folder中编译cpp文件。这是正确的。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2266643|您可能会遗漏的是告诉g%2B%2B在哪里可以找到那些cpp文件#include的附加文件。|2266644|要做到这一点，请告诉您的编译器也使用-I+include该目录，如下所示：|2266645|g%2B%2B+-o+out+-I+./folder+*.cpp+folder/*.cpp|code-block|syntax|javascript|2266646|在某些情况下，我让编译器忘记了根目录/+current目录中的内容，所以我用另一个指向当前目录.的-I手动指定了它|2266647|g%2B%2B+-o+out+-I+.+-I+./folder+*.cpp+folder/*.cpp|2266648|entityMap^0|4|C|P|6|0|R|8|0|I|2|L|7|0|0|1B|1|1D|2|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|12|8|@$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|17|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|18|8|@$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|L|7|1D|8|@]|D|@]|E|$M|N]]|$1|S|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]]|T|$]]

By specifying <code>folder/*.cpp</code> you are telling g++ to compile cpp files in <code>folder</code>. That is correct.

What you may be missing is telling the g++ where to locate additional files that those cpp files <code>#include</code>. 

To do this, tell your compiler to also <code>include</code> that directory with <code>-I</code> like this:

<pre><code>g++ -o out -I ./folder *.cpp folder/*.cpp
</code></pre>

In some circumstances I have had the compiler forget what was in the root/current directory, so I manually specified it with another <code>-I</code> to the current directory <code>.</code>

<pre><code>g++ -o out -I . -I ./folder *.cpp folder/*.cpp
</code></pre>

blocks|key|5794679|text|弄清楚了！:)我讨厌仅仅为了编译我的代码而不得不使用make或构建系统的想法，但我想将我的代码拆分到子文件夹中，以保持它的整洁和有序。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5794680|运行此命令(替换RootFolderName+(例如，用.替换)和OutputName)：|offset|length|style|CODE|5794681|g%2B%2B+-g+$(find+RootFolderName+-type+f+-iregex+".*\.cpp")+-o+OutputName|code-block|syntax|javascript|5794682|find命令将对文件(-type+f)执行递归的、不区分大小写的正则表达式搜索(-iregex)。将其放入$()中，然后将结果注入到g%2B%2B调用中。漂亮！:)|5794683|当然，请确保正确使用命令；您可以随时进行测试运行。|5794684|5794685|对于那些使用Visual+Studio+Code进行编译的人来说，我必须在"command":+"g%2B%2B"任务的tasks.json+args:+[]中进行编译|5794686|"-g",
"$(find",
"code",
"-type",
"f",
"-iregex",
"'.*\\.cpp')",
"-o",
"program"|5794687|(否则它将用单引号将所有$()括起来。)|5794688|5794689|(感谢:+user405725+@+https://stackoverflow.com/a/9764119/1599699评论)|5794690|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/9764119/1599699^0|0|S|1|0|0|B|7|14|7|1H|3|1U|3|0|0|0|11|G|1V|8|0|0|C|3|0|0|I|17|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|19|8|@$D|1A|E|1B|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|1C|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|1D|8|@$D|1E|E|1F|F|G]|$D|1G|E|1H|F|G]|$D|1I|E|1J|F|G]|$D|1K|E|1L|F|G]]|9|@]|A|$]]|$1|O|3|P|5|6|7|1M|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|1N|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|1O|8|@$D|1P|E|1Q|F|G]|$D|1R|E|1S|F|G]]|9|@]|A|$]]|$1|T|3|U|5|J|7|1T|8|@]|9|@]|A|$K|L]]|$1|V|3|W|5|6|7|1U|8|@$D|1V|E|1W|F|G]]|9|@]|A|$]]|$1|X|3|-4|5|6|7|1X|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|6|7|1Y|8|@]|9|@$D|1Z|E|20|1|21]]|A|$]]|$1|10|3|-4|5|6|7|22|8|@]|9|@]|A|$]]]|11|$12|$5|13|14|15|A|$16|17]]]]

Figured it out! :) I hate the idea of having to use make or a build system just to compile my code, but I wanted to split up my code into subfolders to keep it clean and organized.

Run this (replace RootFolderName (e.g. with <code>.</code>) and OutputName):

<pre><code>g++ -g $(find RootFolderName -type f -iregex ".*\.cpp") -o OutputName
</code></pre>

The find command will do a recursive case-insensitive regex search (<code>-iregex</code>) for files (<code>-type f</code>). Placing this within <code>$()</code> will then inject the results into your <code>g++</code> call. Beautiful! :)

Of course, make sure you're using the command right; you can always do a test run.

<hr>

For those using Visual Studio Code to compile, I had to do this in the tasks.json <code>args: []</code> of a task with <code>"command": "g++"</code>:

<pre><code>"-g",
"$(find",
"code",
"-type",
"f",
"-iregex",
"'.*\\.cpp')",
"-o",
"program"
</code></pre>

(Otherwise it would wrap the <code>$()</code> all in single quotes.)

<hr>

(Thanks to: user405725 @ <a href="https://stackoverflow.com/a/9764119/1599699">https://stackoverflow.com/a/9764119/1599699</a> comments)

blocks|key|1751205|text|所以我遇到了这个问题，看到了上面的vscode任务，并管理了一个不同的解决方案。这将从同一目录中获取所有的头文件和c文件。然后将使用F5密钥。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1751206|tasks.json|1751207|{
++"tasks":+[
++++{
++++++"type":+"shell",
++++++"label":+"C/C%2B%2B:+gcc-7+build+active+file",
++++++"command":+"/usr/bin/gcc-7",
++++++"args":+[
++++++++"-I",
++++++++"${fileDirname}",
++++++++"-g",
++++++++"${fileDirname}/*.c",
++++++++"-o",
++++++++"${fileDirname}/${fileBasenameNoExtension}"
++++++],
++++++"options":+{
++++++++"cwd":+"${workspaceFolder}"
++++++},
++++++"problemMatcher":+[
++++++++"$gcc"
++++++],
++++++"group":+{
++++++++"kind":+"build",
++++++++"isDefault":+true
++++++}
++++}
++],
++"version":+"2.0.0"
}|code-block|syntax|javascript|1751208|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

So I ran across this and saw the vscode task above, and managed a different solution. This will get all the headers and c files from the same directory. Then will work with the F5 key.
tasks.json
<pre><code>{
 &quot;tasks&quot;: [
 {
 &quot;type&quot;: &quot;shell&quot;,
 &quot;label&quot;: &quot;C/C++: gcc-7 build active file&quot;,
 &quot;command&quot;: &quot;/usr/bin/gcc-7&quot;,
 &quot;args&quot;: [
 &quot;-I&quot;,
 &quot;${fileDirname}&quot;,
 &quot;-g&quot;,
 &quot;${fileDirname}/*.c&quot;,
 &quot;-o&quot;,
 &quot;${fileDirname}/${fileBasenameNoExtension}&quot;
 ],
 &quot;options&quot;: {
 &quot;cwd&quot;: &quot;${workspaceFolder}&quot;
 },
 &quot;problemMatcher&quot;: [
 &quot;$gcc&quot;
 ],
 &quot;group&quot;: {
 &quot;kind&quot;: &quot;build&quot;,
 &quot;isDefault&quot;: true
 }
 }
 ],
 &quot;version&quot;: &quot;2.0.0&quot;
}
</code></pre>

blocks|key|5794753|text|如果所有文件都包含自己的主文件，并且不是同一项目/程序的一部分，则您可能希望保留其原始名称，并为每个文件创建一个可执行文件。如果是这种情况，您可以使用awk|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5794754|awk+'{n=split(FILENAME,+a,+".");+outfile=sprintf("%25s.out",a[n-1]);+command=sprintf("g%2B%2B+-I+.+%25s+-o+%25s",+FILENAME,+outfile);+system(command);+nextfile+}+'+*.cpp|code-block|syntax|javascript|5794755|开始时，使用split分隔文件名和扩展名，并将结果存储到数组a中。基本名称位于索引n-1，扩展名位于索引n。因此，我们将扩展名更改为.out，并使用sprintf将其存储到outfile变量中。同样，我们在shell中创建要由system函数执行的命令。|5794756|以上命令的最短版本为：|5794757|awk+'{n=split(FILENAME,+a,+".");+command=sprintf("g%2B%2B+-I+.+%25s+-o+%25s.out",+FILENAME,+a[n-1]);+system(command);+nextfile+}+'+*.cpp|5794758|您还可以按照@+#include+-I的建议修改该命令以使用-I断开其他文件。|5794759|注意:如果任何文件名包含空格或多个点，则此解决方案不能很好地工作。在执行该命令之前，需要将这些字符替换为下划线，如here所述|5794760|find+.+-type+f+-name+"*+*.cpp"+-exec+bash+-c+'mv+"$0"+"${0//+/_}"'+{}+\;|5794761|entityMap|0|LINK|mutability|MUTABLE|url|https://unix.stackexchange.com/questions/223182/how-to-replace-spaces-in-all-file-names-with-underscore-in-linux-using-shell-scr^0|23|3|0|0|6|5|U|1|15|3|1G|1|1U|4|22|7|2E|7|35|6|0|0|0|8|8|H|2|U|2|0|1L|4|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|18|8|@$9|19|A|1A|B|C]|$9|1B|A|1C|B|C]|$9|1D|A|1E|B|C]|$9|1F|A|1G|B|C]|$9|1H|A|1I|B|C]|$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]|$9|1N|A|1O|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|1P|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|1Q|8|@]|D|@]|E|$I|J]]|$1|Q|3|R|5|6|7|1R|8|@$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]|$9|1W|A|1X|B|C]]|D|@]|E|$]]|$1|S|3|T|5|6|7|1Y|8|@]|D|@$9|1Z|A|20|1|21]]|E|$]]|$1|U|3|V|5|H|7|22|8|@]|D|@]|E|$I|J]]|$1|W|3|-4|5|6|7|23|8|@]|D|@]|E|$]]]|X|$Y|$5|Z|10|11|E|$12|13]]]]

In case that all files contain their own main and there are not part of the same project/program, you might want to keep their original name and create one executable for each file. If this is the case, you could use <code>awk</code>:
<pre><code>awk '{n=split(FILENAME, a, &quot;.&quot;); outfile=sprintf(&quot;%s.out&quot;,a[n-1]); command=sprintf(&quot;g++ -I . %s -o %s&quot;, FILENAME, outfile); system(command); nextfile } ' *.cpp
</code></pre>
For start, you use <code>split</code> to separate filename and extension and store the result into an array <code>a</code>. The basename is located at index <code>n-1</code> and the extension is at index <code>n</code>. So, we change the extension into <code>.out</code> and by using <code>sprintf</code> store into the <code>outfile</code> variable. In the same way, we create the command to be executed by <code>system</code> function in a shell.
A shortest version of the above command is:
<pre><code>awk '{n=split(FILENAME, a, &quot;.&quot;); command=sprintf(&quot;g++ -I . %s -o %s.out&quot;, FILENAME, a[n-1]); system(command); nextfile } ' *.cpp
</code></pre>
You could also modify the command to <code>#include</code> additional files with <code>-I</code> as suggested by @Bit Fracture.
NOTE: This solution doesn't work well if any filename contains a space or multiple dots. Before executing the command, those characters need to be replaced with an underscore for example, as described <a href="https://unix.stackexchange.com/questions/223182/how-to-replace-spaces-in-all-file-names-with-underscore-in-linux-using-shell-scr">here</a>:
<pre><code>find . -type f -name &quot;* *.cpp&quot; -exec bash -c 'mv &quot;$0&quot; &quot;${0// /_}&quot;' {} \;
</code></pre>

I have a number of source files in a number of folders.. Is there a way to just compile all of them in one go without having to name them?

I know that I can say 

<pre><code>g++ -o out *.cpp 
</code></pre>

But when I try

<pre><code>g++ -o out *.cpp folder/*.cpp
</code></pre>

I get an error.

What's the correct way to do this? I know it's possible with makefiles, but can it be done with just straight g++?

How can you compile all cpp files in a directory?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我在许多文件夹中有许多源文件。有没有一种方法可以一次性编译所有它们，而不需要命名它们？我知道我可以说g++ -o out *.cpp 但当我尝试的时候g++ -o out *.cpp folder/*.cpp我得到一个错误。这样做的正确方法是什么？我知道使用makefile是可能的，但是仅仅使用g++就可以做到吗？

问如何编译一个目录中的所有cpp文件？
EN

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问如何编译一个目录中的所有cpp文件？EN