如何从多维数组中计算数组中的总数
如何从多维数组中计算数组中的总数
提问于 2013-02-21 23:51:54
我有一个来自报告的数组。
此报告包含类似于以下内容的信息：
157479877294,OBSOLETE_ORDER,obelisk,19/01/2013 01:42pm
191532426695,WRONG_PERFORMANCE,g3t1,19/01/2013 01:56pm
159523681637,WRONG_PERFORMANCE,g3t1,19/01/2013 01:57pm
176481653889,WRONG_PERFORMANCE,g4t1,19/01/2013 01:57pm
167479810401,WRONG_PERFORMANCE,g4t1,19/01/2013 02:00pm
172485359309,WRONG_PERFORMANCE,g4t2,19/01/2013 02:02pm
125485358802,WRONG_PERFORMANCE,g4t2,19/01/2013 02:02pm
172485359309,DAY_LIMIT_EXCEEDED,obelisk,19/01/2013 02:03pm
125485358802,DAY_LIMIT_EXCEEDED,obelisk,19/01/2013 02:03pm我需要做的是得到每种类型错误的总数和位置，所以第一个错误是错误：'OBSOLETE_ORDER‘和位置：’方尖碑‘。我尝试过很多方法，但我能想到的最好的方法是多维数组：
$error_handle = fopen("$reportUrl", "r");
while (!feof($error_handle) )
{
$line_of_text = fgetcsv($error_handle, 1024);
$errorName = $line_of_text[1];
$scannerName = $line_of_text[2];
if($errorName != "SCAN_RESULT" && $errorName != "" && $scannerName != "SCAN_LOGIN" && $scannerName != "")
{
$errorsArray["$errorName"]["$scannerName"]++;
}
}
fclose($error_handle);
print_r($errorsArray);为我提供了以下内容：
Array ( [OBSOLETE_ORDER] => Array ( [obelisk] => 1 ) [WRONG_PERFORMANCE] => Array ( [g3t1] => 2 [g4t1] => 2 [g4t2] => 2 ) [DAY_LIMIT_EXCEEDED] => Array ( [obelisk] => 2 ) )哪一个是great...except然后我如何把它拆开添加到我的sql数据库中？！(我感兴趣的是在数组所在的key下获取key和该key的合计)
然后将其添加到表中
-错误-(索引)id_errors id_event id_access_scanner id_errors_type total_errors
-errors_type- (索引)id_errors_type name_errors_type
-access_scanner(索引)id_access_scanner id_portal name_access_scanner
请帮帮我！
谢谢!
回答 4
Stack Overflow用户
发布于 2013-02-22 00:48:34
多维数组超出了您的需要。要采用的方法是创建您自己的字符串(在我的示例中为$arrayKey)，将其用作组合扫描仪名称和错误的数组键，以便您可以获得计数。
//this is the array containing all the report lines, each as an array
$lines_of_text;
//this is going to be our output array
$errorScannerArray = array();
//this variable holds the array key that we're going to generate from each line
$arrayKey = null;
foreach($lines_of_text as $line_of_text)
{
//the array key is a combination of the scanner name and the error name
//the tilde is included to attempt to prevent possible (rare) collisions
$arrayKey = trim($line_of_text[1]).'~'.trim($line_of_text[2]);
//if the array key exists, increase the count by 1
//if it doesn't exist, set the count to 1
if(array_key_exists($arrayKey, $errorScannerArray))
{
$errorScannerArray[$arrayKey]++;
}
else
{
$errorScannerArray[$arrayKey] = 1;
}
}
//clean up
unset($line_of_text);
unset($arrayKey);
unset($lines_of_text);
//displaying the result
foreach($errorScannerArray as $errorScanner => $count)
{
//we can explode the string hash to get the separate error and scanner names
$names = explode('~', $errorScanner);
$errorName = $names[0];
$scannerName = $names[1];
echo 'Scanner '.$scannerName.' experienced error '.$errorName.' '.$count.' times'."\n";
}Stack Overflow用户
发布于 2013-02-22 01:03:35
对于你编辑过的问题，这个简单得多的循环将为你工作，然后你只需要将数据插入到循环中的数据库中，而不是回显出来：
$errorsArray = Array (
[OBSOLETE_ORDER] => Array (
[obelisk] => 1
)
[WRONG_PERFORMANCE] => Array (
[g3t1] => 2
[g4t1] => 2
[g4t2] => 2
)
[DAY_LIMIT_EXCEEDED] => Array (
[obelisk] => 2
)
)
foreach($errorsArray as $row => $errors) {
foreach($errors as $error => $count) {
echo $row; // 'OBSOLETE_ORDER'
echo $error; // 'obelisk'
echo $count; // 1
// insert into database here
}
}旧的答案你只需要一个新的数组来保存你需要的信息，最好是一个计数。我假设正确的数据格式是：
$report = [
['157479877294','OBSOLETE_ORDER','obelisk','19/01/2013 01:42pm'],
['191532426695','WRONG_PERFORMANCE','g3t1','19/01/2013 01:56pm'],
['159523681637','WRONG_PERFORMANCE','g3t1','19/01/2013 01:57pm'],
['176481653889','WRONG_PERFORMANCE','g4t1','19/01/2013 01:57pm'],
.....
];
foreach($report as $array) {
$errorName = $array[1];
$scannerName = $array[2];
if(exists($errorsArray[$errorName][$scannerName])) {
$errorsArray[$errorName][$scannerName] = $errorsArray[$errorName][$scannerName] + 1;
}
else {
$errorsArray[$errorName][$scannerName] = 1;
}
}Stack Overflow用户
发布于 2013-02-22 01:04:18
$list = array();
foreach ($lines as $line) {
$values = explode(',' $line);
$error = $values[1];
$scanner = $values[2];
if (!isset($list[$error])) {
$list[$error] = array();
}
if (!isset($list[$error][$scanner])) {
$list[$error][$scanner] = 1;
} else {
$list[$error][$scanner]++;
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/15006537
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