这对我来说真的很新鲜,我只知道最基本的东西。我正在为一个网页创建一个前端登录(显然安全并不是什么大问题,否则我不会这么做)。我一直在争论我的"where“子句,声明"user”不存在。数据库的设置如下: dbname=connectivity table=users用户有id、用户和通行证。有人想给我点建议吗?提前谢谢。
<?php
define('DB_HOST', 'localhost');
define('DB_NAME', 'connectivity');
define('DB_USER','root');
define('DB_PASSWORD','');
$con=mysql_connect(DB_HOST,DB_USER,DB_PASSWORD) or die("Ya done goofed: " . mysql_error());
$db=mysql_select_db(DB_NAME,$con) or die("Ya done goofed: " . mysql_error());
function SignIn()
{
session_start();
if(!empty($_POST['user']))
{
$query = mysql_query("SELECT * FROM users where user = `$_POST[user]` AND pass = '$_POST[pass]'") or die(mysql_error());
$row = mysql_fetch_array($query) or die(mysql_error());
if(!empty($row['user']) AND !empty($row['pass']))
{
$_SESSION['user'] = $row['pass'];
echo "SUCCESSFULLY LOGIN TO USER PROFILE PAGE...";
}
else
{
echo "SORRY... YOU ENTERD WRONG ID AND PASSWORD... PLEASE RETRY...";
}
}
}
if(isset($_POST['submit']))
{
SignIn();
}
?>发布于 2015-07-02 00:47:50
您缺少引号
已更正代码:
$query = mysql_query("SELECT * FROM `users` WHERE `user` = `'".$_POST["user"]."'` AND pass = '".$_POST["pass"]."'") or die(mysql_error())https://stackoverflow.com/questions/31167150
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