每条记录的总百分比占总和的百分比。Presto/Athena/SQL
每条记录的总百分比占总和的百分比。Presto/Athena/SQL
提问于 2021-10-19 13:28:54
我正在尝试计算每行Presto/Athena的累积百分比。例句:如果我有这样的数据
AccountID | UserID | HolidaysTaken
ABC | A | 4
ABC | B | 6
ABC | B | 3
ABC | K | 2
ABC | K | 3
ABC | X | 1现在，在运行这个查询之后，我得到了以下结果。
SELECT AccountID, UserID, sum(HolidaysTaken) AS HolidaysTaken FROM table
WHERE AccountID = 'ABC'
GROUP BY AccountID, UserID
ORDER BY HolidaysTaken DESC
AccountID | UserID | HolidaysTaken
ABC | B | 9
ABC | K | 5
ABC | A | 4
ABC | X | 1
Total holiday taken by all users = 19 但是我想再添加两列。EachUserPercentage：每个用户的假期占总假期的百分比。CumulativePercentage：EachUserPercentage的累积和。我可以使用this post来完成这个任务
AccountID | UserID | HolidaysTaken | EachUserPercentage | CumulativePercentage
ABC | B | 9 | 47.36 | 47.36
ABC | K | 5 | 26.31 | 73.67
ABC | A | 4 | 21.05 | 94.72
ABC | X | 1 | 5.26 | 100我尝试了比较窗口函数percent_rank(), cume_dist() and ntile()，但是不能让EachUserPercentage正常工作。
回答 2
Stack Overflow用户
回答已采纳
发布于 2021-10-19 13:56:00
您可以使用窗口函数来查找AccountID的百分比，然后使用另一个窗口函数对前面未绑定的行求和，按每个UserID占用的总假期排序。如下所示：
WITH totalUser
AS (SELECT AccountID
,UserID
,SUM(HolidaysTaken) AS HolidaysTaken
,CAST(100.0 * SUM(HolidaysTaken) / SUM(SUM(HolidaysTaken)) OVER (PARTITION BY AccountID) AS NUMERIC(5, 2)) AS EachUserPercentage
FROM table
WHERE AccountID = 'ABC'
GROUP BY AccountID
,UserID)
SELECT totalUser.AccountID
,totalUser.UserID
,totalUser.HolidaysTaken
,totalUser.EachUserPercentage
,SUM(totalUser.EachUserPercentage) OVER (PARTITION BY totalUser.AccountID
ORDER BY totalUser.EachUserPercentage DESC
ROWS UNBOUNDED PRECEDING)
FROM totalUser
ORDER BY totalUser.HolidaysTaken DESC;Stack Overflow用户
发布于 2021-10-19 14:01:58
您好，您可以从下面的查询中获得简单的EachUserPercentage，如果您的组在AccountID上(考虑)。
SELECT table.AccountID, UserID, sum(table.HolidaysTaken) AS HolidaysTaken,
MAX(CAST(all_sum.HolidaysTaken AS NUMERIC(12,2))),
(SUM(CAST(table.HolidaysTaken AS NUMERIC(12,2)))/MAX(CAST(all_sum.HolidaysTaken AS NUMERIC(12,2))))*100 EachUserPercentage
FROM table
LEFT OUTER JOIN (SELECT SUM(HolidaysTaken) AS HolidaysTaken,AccountID FROM table GROUP BY AccountID)all_sum ON all_sum.AccountID= table.AccountID
WHERE table.AccountID = 'ABC'
GROUP BY table.AccountID, UserID
ORDER BY HolidaysTaken DESC它在我这一端起作用。
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原文链接：
https://stackoverflow.com/questions/69631750
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