blocks|key|377683|text|您可以创建匿名类型|type|unstyled|depth|inlineStyleRanges|entityRanges|data|377684|var+studentLst=dox.Descendants("Student").Select(d=>
new{
++++id=d.Element("Id").Value,
++++Name=d.Element("Name").Value,
++++Section=d.Element("Section").Value
+++}).ToList();|code-block|syntax|javascript|377685|这将创建一个匿名类型的列表。|377686|377687|如果您想创建一个学生类型列表|377688|class+Student{public+int+id;public+string+name,string+section}

List<Student>+studentLst=dox.Descendants("Student").Select(d=>
new+Student{
++++id=d.Element("Id").Value,
++++name=d.Element("Name").Value,
++++section=d.Element("Section").Value
+++}).ToList();|377689|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Q|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|R|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|S|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|T|8|@]|9|@]|A|$]]|$1|L|3|M|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|N|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|O|$]]

You can create an anonymous type

<pre><code>var studentLst=dox.Descendants("Student").Select(d=&gt;
new{
 id=d.Element("Id").Value,
 Name=d.Element("Name").Value,
 Section=d.Element("Section").Value
 }).ToList();
</code></pre>

This creates a list of anonymous type..

<hr>

If you want to create a list of Student type

<pre><code>class Student{public int id;public string name,string section}

List&lt;Student&gt; studentLst=dox.Descendants("Student").Select(d=&gt;
new Student{
 id=d.Element("Id").Value,
 name=d.Element("Name").Value,
 section=d.Element("Section").Value
 }).ToList();
</code></pre>

blocks|key|2638844|text|var+students+=+from+student+in+dox.Descendants("Student")
+++++++++++select+new
++++++++++++{
++++++++++++++++id=d.Element("Id").Value,
++++++++++++++++Name=d.Element("Name").Value,
++++++++++++++++Section=d.Element("Section").Value
++++++++++++}).ToList();|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2638845|或者，您可以创建一个名为Student的类，并将id、name和section作为属性，然后执行以下操作：|unstyled|2638846|var+students+=+from+student+in+dox.Descendants("Student")
+++++++++++select+new+Student
++++++++++++{
++++++++++++++++id=d.Element("Id").Value,
++++++++++++++++Name=d.Element("Name").Value,
++++++++++++++++Section=d.Element("Section").Value
++++++++++++}).ToList();|2638847|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>var students = from student in dox.Descendants("Student")
 select new
 {
 id=d.Element("Id").Value,
 Name=d.Element("Name").Value,
 Section=d.Element("Section").Value
 }).ToList();
</code></pre>

or you can create a class call Student with id, name and section as properties and do:

<pre><code>var students = from student in dox.Descendants("Student")
 select new Student
 {
 id=d.Element("Id").Value,
 Name=d.Element("Name").Value,
 Section=d.Element("Section").Value
 }).ToList();
</code></pre>

blocks|key|1920912|text|我知道你已经接受了答案。但我只想展示另一种我喜欢的方式。首先，您需要如下所示的类：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1920913|public+class+Student
{
++++[XmlElement("Id")]
++++public+int+StudentID+{+get;+set;+}

++++[XmlElement("Name")]
++++public+string+StudentName+{+get;+set;+}

++++[XmlElement("Section")]
++++public+int+Section+{+get;+set;+}
}

[XmlRoot("School")]
public+class+School
{
++++[XmlElement("Student",+typeof(Student))]
++++public+List<Student>+StudentList+{+get;+set;+}
}|code-block|syntax|javascript|1920914|然后，您可以反序列化此xml：|1920915|string+path+=+//path+to+xml+file

using+(StreamReader+reader+=+new+StreamReader(path))
{
++++XmlSerializer+serializer+=+new+XmlSerializer(typeof(School));
++++School+school+=+(School)serializer.Deserialize(reader);
}|1920916|希望对您有所帮助。|1920917|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I see that you have accepted an answer. But I just want to show another way which I like. First you will need classes as below:

<pre><code>public class Student
{
 [XmlElement("Id")]
 public int StudentID { get; set; }

 [XmlElement("Name")]
 public string StudentName { get; set; }

 [XmlElement("Section")]
 public int Section { get; set; }
}

[XmlRoot("School")]
public class School
{
 [XmlElement("Student", typeof(Student))]
 public List&lt;Student&gt; StudentList { get; set; }
}
</code></pre>

Then you can deserialize this xml:

<pre><code>string path = //path to xml file

using (StreamReader reader = new StreamReader(path))
{
 XmlSerializer serializer = new XmlSerializer(typeof(School));
 School school = (School)serializer.Deserialize(reader);
}
</code></pre>

Hope it will be helpful.

I am trying to convert XML to List

<pre><code>&lt;School&gt;
 &lt;Student&gt;
 &lt;Id&gt;2&lt;/Id&gt;
 &lt;Name&gt;dummy&lt;/Name&gt;
 &lt;Section&gt;12&lt;/Section&gt;
 &lt;/Student&gt;
 &lt;Student&gt;
 &lt;Id&gt;3&lt;/Id&gt;
 &lt;Name&gt;dummy&lt;/Name&gt;
 &lt;Section&gt;11&lt;/Section&gt;
 &lt;/Student&gt;
&lt;/School&gt;
</code></pre>

I tried few things using LINQ and am not so clear on proceeding.

<pre><code>dox.Descendants("Student").Select(d=&gt;d.Value).ToList();
</code></pre>

Am getting count 2 but values are like <code>2dummy12 3dummy11</code>

Is it possible to convert the above XML to a generic List of type Student which has Id,Name and Section Properties ?

What is the best way I can implement this ?

Converting a XML to Generic List

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在尝试将XML转换为列表<School> <Student> <Id>2</Id> <Name>dummy</Name> <Section>12</Section> </Student> <Student> <Id>3</Id> <Name>dummy</Name> <Se...

问将XML转换为泛型列表
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