Django：'User‘对象没有'user’属性
Django：'User‘对象没有'user’属性
提问于 2012-08-10 03:53:57
我的网站有一个警报系统。当发生特定操作时，系统会记录以下模型的警报：
class Alert(models.Model):
title = models.CharField(max_length=60)
read = models.BooleanField #if this is a new alert of not
for_user = models.ForeignKey(User) #which user will see it
link = models.CharField(max_length=100)许多功能需要检查用户的警报数量(主要是为了在站点的alerts选项卡旁边显示新警报的数量)。正因为如此，我创建了这个函数：
@login_required()
def get_alertnum(user):
alert_objects = Alert.objects.filter(read = False, for_user=user)
num = 0
for n in alert_objects:
num += 1
return num它可以通过这个函数访问：
@login_required()
def posting_draft(request):
user = request.user
user_drafts = Draft.objects.filter(user = user)
drafts = dict()
for d in user_drafts:
drafts[d.title] = d.id
alertnum = get_alertnum(user)
return render_to_response('posting_draft.html', {'STATIC_URL':STATIC_URL, 'draft_l' : drafts, 'selected':"dr", alertnum: alertnum})但我得到以下错误：
Environment:
Request Method: GET
Request URL: http://127.0.0.1:8000/posting/drafts
Django Version: 1.4
Python Version: 2.7.3
Installed Applications:
('django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
'Knights',
'django.contrib.admin')
Installed Middleware:
('django.middleware.common.CommonMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware')
Traceback:
File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/core/handlers/base.py" in get_response
111. response = callback(request, *callback_args, **callback_kwargs)
File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/contrib/auth/decorators.py" in _wrapped_view
20. return view_func(request, *args, **kwargs)
File "/Users/Mike/Desktop/Main/Django-Development/BBN/Knights/views.py" in posting_draft
245. alertnum = get_alertnum(user)
File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/contrib/auth/decorators.py" in _wrapped_view
19. if test_func(request.user):
File "/Library/Python/2.7/site-packages/Django-1.4-py2.7.egg/django/utils/functional.py" in inner
185. return func(self._wrapped, *args)
Exception Type: AttributeError at /posting/drafts
Exception Value: 'User' object has no attribute 'user'回答 3
Stack Overflow用户
回答已采纳
发布于 2012-08-10 03:59:58
您需要从get_alertnum()函数中删除@login_required()装饰器。装饰器假设第一个参数是一个请求对象，并试图访问user属性。
此外，您还可以通过以下方式简化和加快函数的执行速度：
def get_alertnum(user):
return Alert.objects.filter(read=False, for_user=user).count()下面是对count方法的解释。
https://docs.djangoproject.com/en/dev/ref/models/querysets/#count
Stack Overflow用户
发布于 2016-02-18 20:01:14
当你在类上使用@login_required装饰器时，也会出现这个错误。对于类装饰，使用@method_decorator(login_required)。在Class based views docs.中查看更多信息
Stack Overflow用户
发布于 2012-08-10 04:04:42
@login_required装饰器只适用于第一个参数是请求的函数。您的堆栈跟踪是因为它试图像使用request对象一样使用user对象，但它不起作用。(正如另一个答案指出的那样，user对象没有.user属性)
也许相反，get_alertnum()可以先检查user.is_authenticated()，如果用户未通过身份验证，则返回0。
例如：
def get_alertnum(user):
if not user.is_authenticated():
return 0
else:
return Alerts.objects.filter(read=False, for_user=user).count()页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/11890970
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