我有以下代码,但lon/lat似乎返回null;
package com.domain.www;
import android.app.Activity;
import android.content.Context;
import android.content.pm.ActivityInfo;
import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.location.Criteria;
import android.os.Bundle;
import android.webkit.WebView;
import android.webkit.WebViewClient;
public class WebMapActivity extends Activity implements LocationListener {
private static final String MAP_URL = "http://www.yahoo.com/";
private WebView webView;
private Location mostRecentLocation;
@Override
/** Called when the activity is first created. */
public void onCreate(Bundle savedInstanceState) {
try {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
getLocation();
setupWebView();
this.setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_PORTRAIT);
} catch (Exception e) {
e.printStackTrace();
}
}
/** Sets up the WebView object and loads the URL of the page **/
private void setupWebView() {
/*
final String centerURL = "javascript:centerAt("
+ mostRecentLocation.getLatitude() + ","
+ mostRecentLocation.getLongitude() + ")"; */
webView = (WebView) findViewById(R.id.webview);
webView.getSettings().setJavaScriptEnabled(true);
webView.setWebViewClient(new WebViewClient() {
@Override
public void onPageFinished(WebView view, String url)
{
String jsCode = "javascript:alert('" + getMostRecentLocation("lon") + "')";
webView.loadUrl(jsCode.toString());
}
});
webView.loadUrl(MAP_URL);
}
/**
* The Location Manager manages location providers. This code searches for
* the best provider of data (GPS, WiFi/cell phone tower lookup, some other
* mechanism) and finds the last known location.
**/
private void getLocation() {
LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
Criteria criteria = new Criteria();
criteria.setAccuracy(Criteria.ACCURACY_FINE);
String provider = locationManager.getBestProvider(criteria, true);
// In order to make sure the device is getting location, request
// updates. locationManager.requestLocationUpdates(provider, 1, 0,
// this);
//locationManager.requestLocationUpdates(provider, 1, 0, this);
setMostRecentLocation(locationManager.getLastKnownLocation(provider));
}
/** Sets the mostRecentLocation object to the current location of the device **/
@Override
public void onLocationChanged(Location location) {
setMostRecentLocation(location);
}
/**
* The following methods are only necessary because WebMapActivity
* implements LocationListener
**/
@Override
public void onProviderDisabled(String provider) {
}
@Override
public void onProviderEnabled(String provider) {
}
@Override
public void onStatusChanged(String provider, int status, Bundle extras) {
}
/**
* @param mostRecentLocation the mostRecentLocation to set
*/
public void setMostRecentLocation(Location mostRecentLocation) {
this.mostRecentLocation = mostRecentLocation;
}
/**
* @return the mostRecentLocation
*/
public double getMostRecentLocation(String lonLat) {
double gValue = 0.00;
try
{
Location xx = this.mostRecentLocation; //Used as a breakpoint
if(lonLat == "lat") gValue = this.mostRecentLocation.getLatitude();
if(lonLat == "lon") gValue = this.mostRecentLocation.getLongitude();
} catch (Exception e) {
e.printStackTrace();
}
return gValue;
}
}忽略URL位,因为它是一个上面有google地图的页面;但出于调试目的,我更喜欢它只显示一个带有值的警告。
你知道怎么回事吗?目标模拟器(Google API 1.5 API(3))
谢谢
发布于 2010-03-01 06:35:04
使用0,0纬度和经度的原因是您没有纬度或经度。您在代码中没有做任何获取位置的操作--只有当您的代码中有其他东西请求位置更新时,getLastKnownLocation()才会起作用。
通过拉动(类似于努里克先生的addJavascriptInterface()推荐)或推送(使用javascript:表示法),Here is a sample project可以执行您想要的操作。
https://stackoverflow.com/questions/2352679
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