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社区首页 >问答首页 >用于向特定客户端发送消息的socket.io和node.js

用于向特定客户端发送消息的socket.io和node.js
EN

Stack Overflow用户
提问于 2012-05-17 11:36:37
回答 2查看 13K关注 0票数 11

发送消息到所有客户端工作良好,但我想发送消息到特定的用户名。我的server.js文件看起来像这样。它所做的是,当http://localhost:8080运行时,客户端代码将用户添加到对象用户名以及套接字对象中。并立即将该单独的消息返回给每个连接的客户端。

代码语言:javascript
复制
//var io = require('socket.io').listen(8080);
var app = require('http').createServer(handler)
  , io = require('socket.io').listen(app)
  , fs = require('fs')
var usernames={};  
 app.listen(8080);

// on server started we can load our client.html page
function handler ( req, res ) {
  fs.readFile( __dirname + '/client.html' ,
  function ( err, data ) {
    if ( err ) {
      console.log( err );
      res.writeHead(500);
      return res.end( 'Error loading client.html' );
    }
    res.writeHead( 200 );
    res.end( data );
  });
};
io.set('log level', 1); // reduce logging
io.sockets.on('connection', function (socket) {

 socket.on('adduser', function(username){
        // store the username in the socket session for this client
        socket.username = username;
        // add the client's username to the global list
        usernames[username] = username;
        // send client to room 1
        console.log(username+' has connected to the server');
        // echo to client they've connected
  });

  socket.on('pmessage', function (data) {
        // we tell the client to execute 'updatechat' with 2 parameters
        io.sockets.emit("pvt",socket.username,data+socket.username); // This works
        io.sockets.socket(socket.username).emit("pvt",socket.username,data+socket.username); // THIS DOESNOT
   });

  socket.on('disconnect', function(){
        // remove the username from global usernames list
        delete usernames[socket.username];

        // echo globally that this client has left
       console.log(socket.username + ' has disconnected');
    });
});

发出消息的部分

代码语言:javascript
复制
socket.on('pmessage', function (data) {
        // we tell the client to execute 'updatechat' with 2 parameters
        io.sockets.emit("pvt",socket.username,data+socket.username); // This works and sends message to all clients
        io.sockets.socket(socket.username).emit("pvt",socket.username,data+socket.username); // THIS DOESNOT
   });
EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2012-06-07 03:41:35

试试这个:

代码语言:javascript
复制
socket.on('pmessage', function (data) {
    // we tell the client to execute 'updatechat' with 2 parameters
    io.sockets.emit("pvt",socket.username,data+socket.username);
    io.sockets.socket(socket.id).emit("pvt",socket.username,data+socket.username); 
});

socket.id由socket.io保存,它包含您的客户端的唯一id。您可以使用以下命令进行检查:

代码语言:javascript
复制
console.log(socket.id);
票数 10
EN

Stack Overflow用户

发布于 2014-10-31 17:32:49

您必须存储所有客户端id,并根据该id获取特定客户端的id,然后使用以下代码

代码语言:javascript
复制
var store={};//this will store all client id and username e.g. store={jay:"34jhjshdj343sasa"}
socket.on('pmessage', function (data) {
    var receiverUserName=data.username;
    var message=data.message;
    var id = store[receiverUserName];//get ID
    // we tell the client to execute 'updatechat' with 2 parameters
    io.sockets.emit("pvt",socket.username,data+socket.username);
    io.sockets.socket(id).emit("pvt",socket.username,data+socket.username); 
});

然后,这将在特定客户端上发出

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/10629497

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