我应该如何使用RxJava的TestScheduler?我来自.NET背景,但RxJava中的TestScheduler似乎与.NET rx中的测试调度程序的工作方式不同。
下面是我想要测试的示例代码
Observable<Long> tick = Observable.interval(1, TimeUnit.SECONDS);
contactsRepository.find(index)
.buffer(MAX_CONTACTS_FETCH)
.zipWith(tick, new Func2<List<ContactDto>, Long, List<ContactDto>>() {
@Override
public List<ContactDto> call(List<ContactDto> contactList, Long aLong) {
return contactList;
}
}).subscribe()我试过了:
subscribeOn(testScheduler)
testScheduler.advanceTimeBy(2, TimeUnit.SECONDS);
testScheduler.triggerActions();不走运。
发布于 2014-11-02 21:42:29
我做了一个如何使用TestScheduler的小例子。我认为它非常类似于.NET实现
@Test
public void should_test_the_test_schedulers() {
TestScheduler scheduler = new TestScheduler();
final List<Long> result = new ArrayList<>();
Observable.interval(1, TimeUnit.SECONDS, scheduler)
.take(5)
.subscribe(result::add);
assertTrue(result.isEmpty());
scheduler.advanceTimeBy(2, TimeUnit.SECONDS);
assertEquals(2, result.size());
scheduler.advanceTimeBy(10, TimeUnit.SECONDS);
assertEquals(5, result.size());
}根据您的代码编辑:您应该将调度程序传递给Observable.interval操作,因为这是您想要控制的内容:
TestScheduler scheduler = new TestScheduler();
Observable<Long> tick = Observable.interval(1, TimeUnit.SECONDS, scheduler);
Subscription toBeTested = Observable.from(Arrays.asList(1, 2, 3, 4, 5))
.buffer(3)
.zipWith(tick, (i, t) -> i)
.subscribe(System.out::println);
scheduler.advanceTimeBy(2, TimeUnit.SECONDS);https://stackoverflow.com/questions/26699147
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