blocks|key|2891288|text|我对您的问题的重复是，对于特定的AD组，您正在寻找基于OU或容器的成员计数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2891289|Get-ADGroupMember+-Identity+"insert_your_group"+-Recursive+%7C+
++++++++Where-Object{$_.objectClass+-eq+"User"}+%7C
++++++++Get-ADUser+-Properties+canonicalname+%7C+
++++++++Select-Object+@{Name='Container';Expression={$_.canonicalname+%7C+split-path+-parent}}+%7C
++++++++Group-Object+container+%7C
++++++++Select+Name,Count|code-block|syntax|javascript|2891290|逐行分解这段代码|2891291|2891292|还可以抓取特定组的所有成员，包括其他组的成员。|ordered-list-item|2891293|确保我们只处理用户，而不是组本身。我们已经有了来自-Recursive的所有用户，所以可以忽略他们。|offset|length|style|CODE|2891294|通过Get-ADUser调用获取所有用户对象。我们需要canonicalname，因为我们获得父container|2891295|Here的信息是最有趣的部分。使用canonicalname将其拆分(就像对目录一样)，并只获取对象的-parent，以便获得您正在查找的|2891296|Simplify输出的select语句。|2891297|2891298|输出|BOLD|2891299|Name++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++Count
----++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++-----
Domain.Local\OU\SubOU+++++++++++++++++++++++++++++++++++++++++++++++++++8
Domain.Local\OU\SubOU2++++++++++++++++++++++++++++++++++++++++++++++++++8
Domain.Local\OU\SubOU5++++++++++++++++++++++++++++++++++++++++++++++++++2|2891300|entityMap^0|0|0|0|0|0|P|A|0|R|D|0|H|D|1F|7|0|0|0|0|2|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|18|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|19|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|1A|8|@]|9|@]|A|$]]|$1|M|3|N|5|L|7|1B|8|@$O|1C|P|1D|Q|R]]|9|@]|A|$]]|$1|S|3|T|5|L|7|1E|8|@$O|1F|P|1G|Q|R]]|9|@]|A|$]]|$1|U|3|V|5|L|7|1H|8|@$O|1I|P|1J|Q|R]|$O|1K|P|1L|Q|R]]|9|@]|A|$]]|$1|W|3|X|5|L|7|1M|8|@]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1N|8|@]|9|@]|A|$]]|$1|Z|3|10|5|6|7|1O|8|@$O|1P|P|1Q|Q|11]]|9|@]|A|$]]|$1|12|3|13|5|D|7|1R|8|@]|9|@]|A|$E|F]]|$1|14|3|-4|5|6|7|1S|8|@]|9|@]|A|$]]]|15|$]]

My interpetation of your question is that for a paricular AD Group you are looking for a member count based on OU or container.

<pre><code>Get-ADGroupMember -Identity "insert_your_group" -Recursive | 
 Where-Object{$_.objectClass -eq "User"} |
 Get-ADUser -Properties canonicalname | 
 Select-Object @{Name='Container';Expression={$_.canonicalname | split-path -parent}} |
 Group-Object container |
 Select Name,Count
</code></pre>

Breaking this down line by line

<ol>
<li>Grab all member of a particular group as well including members of other groups. </li>
<li>Ensure we are only processing users and not the group themselves. We already have all the users from the <code>-Recursive</code> so they can be ignored. </li>
<li>Get all the user objects with a Get-ADUser call. We need the <code>canonicalname</code> as that is we get the information for the parent container</li>
<li>Here is the fun part. Using the <code>canonicalname</code> split it up (like you would a directory) and just take the <code>-parent</code> portion.</li>
<li>Group the objects in order to get the count you are looking for</li>
<li>Simplify output with a select statment.</li>
</ol>

Output

<pre><code>Name Count
---- -----
Domain.Local\OU\SubOU 8
Domain.Local\OU\SubOU2 8
Domain.Local\OU\SubOU5 2
</code></pre>

blocks|key|282589|text|(Get-ADGroupMember+'AD-groupname‘-Recursive).count|type|unstyled|depth|inlineStyleRanges|entityRanges|data|282590|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

(Get-ADGroupMember 'AD-groupname' -Recursive).count

Is it possible to get a count of members that belong to a specific group based on the OU? When I run the code below it is giving me the value of 3 for each OU when there is only 1 OU that has a value of 3, the rest should be 0. It is running the Get-ADGroupMember -Identity “Test_Group”).count against the whole active directory structure instead of just for each OU??

<pre><code>import-module activedirectory
foreach ($ou in Get-ADOrganizationalUnit -filter * -SearchScope 1){

 $computers = 0 + (get-adcomputer -filter * -searchbase $ou.distinguishedname).count 


 $ou | add-member -membertype noteproperty -name Computers -value $computers -force 


 Foreach ($Member in $ou){

 (Get-ADGroupMember -Identity “Test_Group”).count 

 }

 $ou | select name,computers 

}
</code></pre>

Get count of members of an active directory group?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

是否可以根据OU获取属于特定组的成员计数？当我运行下面的代码时，它为每个OU提供了值3，而只有1个OU的值为3，其余的应该为0。它正在针对整个active directory结构运行Get-ADGroupMember -Identity (“Test_Group”).count，而不仅仅是针对每个OU?？import-...

问是否获取active directory组的成员计数？
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问是否获取active directory组的成员计数？EN