blocks|key|3771495|text|您将通过YAML得到您想要的东西。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3771496|但是你的字符串有一个小问题。YAML期望逗号后面有一个空格。所以我们需要这个|3771497|str+=+"[[this,+is],+[a,+nested],+[array]]"|code-block|syntax|javascript|3771498|代码：|3771499|require+'yaml'
str+=+"[[this,+is],[a,+nested],[array]]"
###+transform+your+string+in+a+valid+YAML-String
str.gsub!(/(\,)(\S)/,+"\\1+\\2")
YAML::load(str)
#+=>+[["this",+"is"],+["a",+"nested"],+["array"]]|3771500|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You'll get what you want with YAML.

But there is a little problem with your string. YAML expects that there's a space behind the comma. So we need this

<pre><code>str = "[[this, is], [a, nested], [array]]"
</code></pre>

Code:

<pre><code>require 'yaml'
str = "[[this, is],[a, nested],[array]]"
### transform your string in a valid YAML-String
str.gsub!(/(\,)(\S)/, "\\1 \\2")
YAML::load(str)
# =&gt; [["this", "is"], ["a", "nested"], ["array"]]
</code></pre>

blocks|key|3771532|text|您也可以将其视为几乎JSON。如果字符串真的只是字母，就像您的示例中一样，那么这将是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3771533|JSON.parse(yourarray.gsub(/([a-z]%2B)/,'"\1"'))|code-block|syntax|javascript|3771534|如果它们可以包含任意字符(而不是，)，则需要更多的字符：|3771535|JSON.parse("[[this,+is],[a,+nested],[array]]".gsub(/,+/,",").gsub(/([%5E\[\]\,]%2B)/,'"\1"'))|3771536|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You could also treat it as almost-JSON. If the strings really are only letters, like in your example, then this will work:

<pre><code>JSON.parse(yourarray.gsub(/([a-z]+)/,'"\1"'))
</code></pre>

If they could have arbitrary characters (other than [ ] , ), you'd need a little more:

<pre><code>JSON.parse("[[this, is],[a, nested],[array]]".gsub(/, /,",").gsub(/([^\[\]\,]+)/,'"\1"'))
</code></pre>

blocks|key|721189|text|作为笑料：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|721190|+ary+=+eval("[[this,+is],[a,+nested],[array]]".gsub(/(\w%2B?)/,+"'\\1'")+)
+=>+[["this",+"is"],+["a",+"nested"],+["array"]]|code-block|syntax|javascript|721191|免责声明:你绝对不应该这样做，因为eval是一个糟糕的想法，但它很快，并且有一个有用的副作用，如果你的嵌套数组无效，就会抛出一个异常|offset|length|style|CODE|721192|entityMap^0|0|0|H|4|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

For a laugh:

<pre><code> ary = eval("[[this, is],[a, nested],[array]]".gsub(/(\w+?)/, "'\\1'") )
 =&gt; [["this", "is"], ["a", "nested"], ["array"]]
</code></pre>

Disclaimer: You definitely shouldn't do this as <code>eval</code> is a terrible idea, but it is fast and has the useful side effect of throwing an exception if your nested arrays aren't valid

blocks|key|2926191|text|看起来像是一个基本的解析任务。通常，您要采用的方法是使用以下通用算法创建一个递归函数|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2926192|base+case+(input+doesn't+begin+with+'[')+return+the+input
recursive+case:
++++split+the+input+on+','+(you+will+need+to+find+commas+only+at+this+level)
++++for+each+sub+string+call+this+method+again+with+the+sub+string
++++return+array+containing+the+results+from+this+recursive+method|code-block|syntax|javascript|2926193|这里唯一稍微棘手的部分是将输入拆分到一个'，‘上。您可以为此编写一个单独的函数，该函数将扫描整个字符串，并对到目前为止看到的左括号-闭括号进行计数。然后，仅当计数等于零时拆分逗号。|2926194|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Looks like a basic parsing task. Generally the approach you are going to want to take is to create a recursive function with the following general algorithm

<pre><code>base case (input doesn't begin with '[') return the input
recursive case:
 split the input on ',' (you will need to find commas only at this level)
 for each sub string call this method again with the sub string
 return array containing the results from this recursive method
</code></pre>

The only slighlty tricky part here is splitting the input on a single ','. You could write a separate function for this that would scan through the string and keep a count of the openbrackets - closedbrakets seen so far. Then only split on commas when the count is equal to zero.

blocks|key|2926318|text|创建一个以字符串和整数偏移量为参数的递归函数，并“读出”一个数组。也就是说，让它返回一个数组或字符串(它已读取)和指向该数组后面整数偏移量。例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2926319|s+=+"[[this,+is],[a,+nested],[array]]"

yourFunc(s,+1)+#+returns+['this',+'is']+and+11.
yourFunc(s,+2)+#+returns+'this'+and+6.|code-block|syntax|javascript|2926320|然后，您可以使用另一个函数调用它，该函数提供偏移量0，并确保结束偏移量是字符串的长度。|2926321|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Make a recursive function that takes the string and an integer offset, and "reads" out an array. That is, have it return an array or string (that it has read) and an integer offset pointing after the array. For example:

<pre><code>s = "[[this, is],[a, nested],[array]]"

yourFunc(s, 1) # returns ['this', 'is'] and 11.
yourFunc(s, 2) # returns 'this' and 6.
</code></pre>

Then you can call it with another function that provides an offset of 0, and makes sure that the finishing offset is the length of the string.

I would like to convert the following string into an array/nested array: 

<pre><code>str = "[[this, is],[a, nested],[array]]"

newarray = # this is what I need help with!

newarray.inspect # =&gt; [['this','is'],['a','nested'],['array']]
</code></pre>

How do I convert a Ruby string with brackets to an array?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想将以下字符串转换为数组/嵌套数组：str = "[[this, is],[a, nested],[array]]"newarray = # this is what I need help with!newarray.inspect  # => [['this','is'],['a','nested'],['array']]

问如何将带括号的Ruby字符串转换为数组？
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