blocks|key|2954692|text|按计数聚合列，然后使用HAVING子句查找出现次数超过一次的值。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2954693|SELECT+column_name,+COUNT(column_name)
FROM+table_name
GROUP+BY+column_name
HAVING+COUNT(column_name)+>+1;|code-block|syntax|javascript|2954694|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Aggregate the column by COUNT, then use a HAVING clause to find values that appear greater than one time.
<pre><code>SELECT column_name, COUNT(column_name)
FROM table_name
GROUP BY column_name
HAVING COUNT(column_name) &gt; 1;
</code></pre>

blocks|key|5210236|text|我能想到的最简单的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5210237|select+job_number,+count(*)
from+jobs
group+by+job_number
having+count(*)+>+1;|code-block|syntax|javascript|5210238|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Simplest I can think of:

<pre><code>select job_number, count(*)
from jobs
group by job_number
having count(*) &gt; 1;
</code></pre>

blocks|key|730479|text|这样如何：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|730480|SELECT+<column>,+count(*)
FROM+<table>
GROUP+BY+<column>+HAVING+COUNT(*)+>+1;|code-block|syntax|javascript|730481|要回答上面的示例，它将如下所示：|730482|SELECT+job_number,+count(*)
FROM+jobs
GROUP+BY+job_number+HAVING+COUNT(*)+>+1;|730483|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

How about:

<pre><code>SELECT &lt;column&gt;, count(*)
FROM &lt;table&gt;
GROUP BY &lt;column&gt; HAVING COUNT(*) &gt; 1;
</code></pre>

To answer the example above, it would look like:

<pre><code>SELECT job_number, count(*)
FROM jobs
GROUP BY job_number HAVING COUNT(*) &gt; 1;
</code></pre>

blocks|key|5210279|text|正在做什么|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5210280|select+count(j1.job_number),+j1.job_number,+j1.id,+j2.id
from+++jobs+j1+join+jobs+j2+on+(j1.job_numer+=+j2.job_number)
where++j1.id+!=+j2.id
group+by+j1.job_number|code-block|syntax|javascript|5210281|将为您提供重复行的ids。|5210282|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Doing

<pre><code>select count(j1.job_number), j1.job_number, j1.id, j2.id
from jobs j1 join jobs j2 on (j1.job_numer = j2.job_number)
where j1.id != j2.id
group by j1.job_number
</code></pre>

will give you the duplicated rows' ids.

blocks|key|2954751|text|另一种方式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2954752|SELECT+*
FROM+TABLE+A
WHERE+EXISTS+(
++SELECT+1+FROM+TABLE
++WHERE+COLUMN_NAME+=+A.COLUMN_NAME
++AND+ROWID+<+A.ROWID
)|code-block|syntax|javascript|2954753|当在column_name上有索引时，工作正常(足够快)。这是删除或更新重复行的更好方法。|offset|length|style|CODE|2954754|entityMap^0|0|0|2|B|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Another way:

<pre><code>SELECT *
FROM TABLE A
WHERE EXISTS (
 SELECT 1 FROM TABLE
 WHERE COLUMN_NAME = A.COLUMN_NAME
 AND ROWID &lt; A.ROWID
)
</code></pre>

Works fine (quick enough) when there is index on <code>column_name</code>. And it's better way to delete or update duplicate rows.

blocks|key|5210997|text|如果您不需要知道实际的重复数，那么您甚至不需要在返回的列中包含计数。例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5210998|SELECT+column_name
FROM+table
GROUP+BY+column_name
HAVING+COUNT(*)+>+1|code-block|syntax|javascript|5210999|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You don't need to even have the count in the returned columns if you don't need to know the actual number of duplicates. e.g.

<pre><code>SELECT column_name
FROM table
GROUP BY column_name
HAVING COUNT(*) &gt; 1
</code></pre>

blocks|key|5211095|text|在多个列标识唯一行(例如关系表)的情况下，您可以使用以下命令|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5211096|使用行id，例如emp_dept(+empid，deptid，startdate，enddate)假设empid和deptid是唯一的，并在这种情况下标识行|5211097|select+oed.empid,+count(oed.empid)+
from+emp_dept+oed+
where+exists+(+select+*+
+++++++++++++++from++emp_dept+ied+
++++++++++++++++where+oed.rowid+<>+ied.rowid+and+
+++++++++++++++++++++++ied.empid+=+oed.empid+and+
++++++++++++++++++++++ied.deptid+=+oed.deptid+)++
++++++++group+by+oed.empid+having+count(oed.empid)+>+1+order+by+count(oed.empid);|code-block|syntax|javascript|5211098|如果这样的表有主键，那么使用主键而不是rowid，例如id是pk，那么|5211099|select+oed.empid,+count(oed.empid)+
from+emp_dept+oed+
where+exists+(+select+*+
+++++++++++++++from++emp_dept+ied+
++++++++++++++++where+oed.id+<>+ied.id+and+
+++++++++++++++++++++++ied.empid+=+oed.empid+and+
++++++++++++++++++++++ied.deptid+=+oed.deptid+)++
++++++++group+by+oed.empid+having+count(oed.empid)+>+1+order+by+count(oed.empid);|5211100|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

In case where multiple columns identify unique row (e.g relations table ) there you can use following 

Use row id 
 e.g. emp_dept(empid, deptid, startdate, enddate)
 suppose empid and deptid are unique and identify row in that case

<pre><code>select oed.empid, count(oed.empid) 
from emp_dept oed 
where exists ( select * 
 from emp_dept ied 
 where oed.rowid &lt;&gt; ied.rowid and 
 ied.empid = oed.empid and 
 ied.deptid = oed.deptid ) 
 group by oed.empid having count(oed.empid) &gt; 1 order by count(oed.empid);
</code></pre>

and if such table has primary key then use primary key instead of rowid, e.g id is pk then

<pre><code>select oed.empid, count(oed.empid) 
from emp_dept oed 
where exists ( select * 
 from emp_dept ied 
 where oed.id &lt;&gt; ied.id and 
 ied.empid = oed.empid and 
 ied.deptid = oed.deptid ) 
 group by oed.empid having count(oed.empid) &gt; 1 order by count(oed.empid);
</code></pre>

blocks|key|3800972|text|SELECT+++SocialSecurity_Number,+Count(*)+no_of_rows
FROM+++++SocialSecurity+
GROUP+BY+SocialSecurity_Number
HAVING+++Count(*)+>+1
Order+by+Count(*)+desc+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3800973|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>SELECT SocialSecurity_Number, Count(*) no_of_rows
FROM SocialSecurity 
GROUP BY SocialSecurity_Number
HAVING Count(*) &gt; 1
Order by Count(*) desc 
</code></pre>

blocks|key|5211164|text|你也可以尝试这样在一个表中列出所有重复的值，比如reqitem|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5211165|SELECT+count(poid)+
FROM+poitem+
WHERE+poid+=+50+
AND+rownum+<+any+(SELECT+count(*)++FROM+poitem+WHERE+poid+=+50)+
GROUP+BY+poid+
MINUS
SELECT+count(poid)+
FROM+poitem+
WHERE+poid+in+(50)
GROUP+BY+poid+
HAVING+count(poid)+>+1;|code-block|syntax|javascript|5211166|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Also u can try something like this to list all duplicate values in a table say reqitem

<pre><code>SELECT count(poid) 
FROM poitem 
WHERE poid = 50 
AND rownum &lt; any (SELECT count(*) FROM poitem WHERE poid = 50) 
GROUP BY poid 
MINUS
SELECT count(poid) 
FROM poitem 
WHERE poid in (50)
GROUP BY poid 
HAVING count(poid) &gt; 1;
</code></pre>

blocks|key|5211196|text|1.解决方案|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|5211197|select+*+from+emp
++++where+rowid+not+in
++++(select+max(rowid)+from+emp+group+by+empno);|code-block|syntax|javascript|5211198|entityMap^0|0|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

1. solution

<pre><code>select * from emp
 where rowid not in
 (select max(rowid) from emp group by empno);
</code></pre>

blocks|key|734623|text|我通常使用Oracle+Analytic函数ROW_NUMBER()。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|734624|假设您想要检查在列(c1、c2、c3)上构建的唯一索引或主键的重复项。然后您就可以这样做了，调出由ROW_NUMBER()带来的行数为>1的行数ROWID。|style|CODE|BOLD|734625|Select+*+From+Table_With_Duplicates
++++++Where+Rowid+In
++++++++++++++++++++(Select+Rowid
+++++++++++++++++++++++From+(Select+Rowid,
++++++++++++++++++++++++++++++++++++ROW_NUMBER()+Over+(
++++++++++++++++++++++++++++++++++++++++++++Partition+By+c1+%7C%7C+c2+%7C%7C+c3
++++++++++++++++++++++++++++++++++++++++++++Order+By+c1+%7C%7C+c2+%7C%7C+c3
++++++++++++++++++++++++++++++++++++++++)+nbLines
+++++++++++++++++++++++++++++++From+Table_With_Duplicates)+t2
++++++++++++++++++++++Where+nbLines+>+1)|code-block|syntax|javascript|734626|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions001.htm#i81407|1|http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions137.htm#i86310^0|5|F|0|M|C|1|0|A|2|D|2|G|2|1D|C|1V|2|20|5|20|5|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@$A|Y|B|Z|1|10]|$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|6|7|14|8|@$A|15|B|16|F|G]|$A|17|B|18|F|G]|$A|19|B|1A|F|G]|$A|1B|B|1C|F|G]|$A|1D|B|1E|F|G]|$A|1F|B|1G|F|G]|$A|1H|B|1I|F|H]]|9|@]|C|$]]|$1|I|3|J|5|K|7|1J|8|@]|9|@]|C|$L|M]]|$1|N|3|-4|5|6|7|1K|8|@]|9|@]|C|$]]]|O|$P|$5|Q|R|S|C|$T|U]]|V|$5|Q|R|S|C|$T|W]]]]

I usually use <a href="https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions001.htm#i81407" rel="nofollow noreferrer">Oracle Analytic</a> function <a href="http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions137.htm#i86310" rel="nofollow noreferrer">ROW_NUMBER()</a>.

Say you want to check the duplicates you have regarding a unique index or primary key built on columns (<code>c1</code>, <code>c2</code>, <code>c3</code>). 
Then you will go this way, bringing up <code>ROWID</code> s of rows where the number of lines brought by <code>ROW_NUMBER()</code> is <code>&gt;1</code>:

<pre><code>Select * From Table_With_Duplicates
 Where Rowid In
 (Select Rowid
 From (Select Rowid,
 ROW_NUMBER() Over (
 Partition By c1 || c2 || c3
 Order By c1 || c2 || c3
 ) nbLines
 From Table_With_Duplicates) t2
 Where nbLines &gt; 1)
</code></pre>

blocks|key|3801185|text|下面是一个执行此操作的SQL请求：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3801186|select+column_name,+count(1)
from+table
group+by+column_name
having+count+(column_name)+>+1;|code-block|syntax|javascript|3801187|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is an SQL request to do that:

<pre><code>select column_name, count(1)
from table
group by column_name
having count (column_name) &gt; 1;
</code></pre>

blocks|key|730683|text|我知道这是一个古老的帖子，但这可能会对某些人有所帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|730684|如果在检查重复项时需要打印表的其他列，请使用以下内容：|730685|select+*+from+table+where+column_name+in
(select+ing.column_name+from+table+ing+group+by+ing.column_name+having+count(*)+>+1)
order+by+column_name+desc;|code-block|syntax|javascript|730686|如果需要，还可以在where子句中添加一些额外的过滤器。|730687|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I know its an old thread but this may help some one.

If you need to print other columns of the table while checking for duplicate use below:

<pre><code>select * from table where column_name in
(select ing.column_name from table ing group by ing.column_name having count(*) &gt; 1)
order by column_name desc;
</code></pre>

also can add some additional filters in the where clause if needed.

What's the simplest SQL statement that will return the duplicate values for a given column and the count of their occurrences in an Oracle database table?

For example: I have a <code>JOBS</code> table with the column <code>JOB_NUMBER</code>. How can I find out if I have any duplicate <code>JOB_NUMBER</code>s, and how many times they're duplicated?

How do I find duplicate values in a table in Oracle?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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哪条最简单的SQL语句将返回给定列的重复值以及它们在Oracle数据库表中出现的次数？例如:我有一个列为JOB_NUMBER的JOBS表。我怎样才能知道我是否有重复的JOB_NUMBER，以及它们被复制了多少次？

问如何在Oracle的表中查找重复的值？
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问如何在Oracle的表中查找重复的值？EN