blocks|key|5254237|text|使用JavaScript的String.prototype.split函数：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5254238|var+input+=+'john+smith~123+Street~Apt+4~New+York~NY~12345';

var+fields+=+input.split('~');

var+name+=+fields[0];
var+street+=+fields[1];
//+etc.|code-block|syntax|javascript|5254239|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split^0|D|M|D|M|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

With JavaScript’s <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split" rel="noreferrer"><code>String.prototype.split</code></a> function:

<pre><code>var input = 'john smith~123 Street~Apt 4~New York~NY~12345';

var fields = input.split('~');

var name = fields[0];
var street = fields[1];
// etc.
</code></pre>

blocks|key|753050|text|根据ECMAScript6+ES6的说法，最干净的方法是解构数组：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|753051|​|753052|const+input+=+'john+smith~123+Street~Apt+4~New+York~NY~12345';

const+[name,+street,+unit,+city,+state,+zip]+=+input.split('~');

console.log(name);+//+john+smith
console.log(street);+//+123+Street
console.log(unit);+//+Apt+4
console.log(city);+//+New+York
console.log(state);+//+NY
console.log(zip);+//+12345|code-block|syntax|javascript|753053|753054|您可能在输入字符串中有额外的项目。在这种情况下，您可以使用rest运算符来获取剩余部分的数组，或者直接忽略它们：|753055|753056|const+input+=+'john+smith~123+Street~Apt+4~New+York~NY~12345';

const+[name,+street,+...others]+=+input.split('~');

console.log(name);+//+john+smith
console.log(street);+//+123+Street
console.log(others);+//+["Apt+4",+"New+York",+"NY",+"12345"]|753057|753058|我假设值是一个只读引用，并使用了const声明。|753059|享受ES6!|BOLD|753060|entityMap^0|E|3|0|0|0|0|0|0|0|0|G|5|0|0|6|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|14|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|15|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|16|8|@]|D|@]|E|$]]|$1|P|3|G|5|6|7|17|8|@]|D|@]|E|$]]|$1|Q|3|R|5|J|7|18|8|@]|D|@]|E|$K|L]]|$1|S|3|G|5|6|7|19|8|@]|D|@]|E|$]]|$1|T|3|U|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|V|3|W|5|6|7|1D|8|@$9|1E|A|1F|B|X]]|D|@]|E|$]]|$1|Y|3|-4|5|6|7|1G|8|@]|D|@]|E|$]]]|Z|$]]

According to ECMAScript6 <code>ES6</code>, the clean way is destructuring arrays:

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="true">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const input = 'john smith~123 Street~Apt 4~New York~NY~12345';

const [name, street, unit, city, state, zip] = input.split('~');

console.log(name); // john smith
console.log(street); // 123 Street
console.log(unit); // Apt 4
console.log(city); // New York
console.log(state); // NY
console.log(zip); // 12345</code></pre>
</div>
</div>


You may have extra items in the input string. In this case, you can use rest operator to get an array for the rest or just ignore them: 

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="true">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const input = 'john smith~123 Street~Apt 4~New York~NY~12345';

const [name, street, ...others] = input.split('~');

console.log(name); // john smith
console.log(street); // 123 Street
console.log(others); // ["Apt 4", "New York", "NY", "12345"]</code></pre>
</div>
</div>


I supposed a read-only reference for values and used the <code>const</code> declaration.

Enjoy ES6!

blocks|key|5254329|text|你不需要jQuery。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5254330|var+s+=+'john+smith~123+Street~Apt+4~New+York~NY~12345';
var+fields+=+s.split(/~/);
var+name+=+fields[0];
var+street+=+fields[1];|code-block|syntax|javascript|5254331|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You don't need jQuery.

<pre><code>var s = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = s.split(/~/);
var name = fields[0];
var street = fields[1];
</code></pre>

blocks|key|2999750|text|尽管这不是最简单的方法，但您可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2999751|var+addressString+=+"~john+smith~123+Street~Apt+4~New+York~NY~12345~",
++++keys+=+"name+address1+address2+city+state+zipcode".split("+"),
++++address+=+{};

//+clean+up+the+string+with+the+first+replace
//+"abuse"+the+second+replace+to+map+the+keys+to+the+matches
addressString.replace(/%5E~%7C~$/g).replace(/[%5E~]%2B/g,+function(match){
++++address[+keys.unshift()+]+=+match;
});

//+address+will+contain+the+mapped+result
address+=+{
++++address1:+"123+Street"
++++address2:+"Apt+4"
++++city:+"New+York"
++++name:+"john+smith"
++++state:+"NY"
++++zipcode:+"12345"
}|code-block|syntax|javascript|2999752|2999753|ES2015的更新，使用解构|offset|length|style|BOLD|2999754|const+[address1,+address2,+city,+name,+state,+zipcode]+=+addressString.match(/[%5E~]%2B/g);

//+The+variables+defined+above+now+contain+the+appropriate+information:

console.log(address1,+address2,+city,+name,+state,+zipcode);
//+->+john+smith+123+Street+Apt+4+New+York+NY+12345|2999755|entityMap^0|0|0|0|7|7|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|T|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|U|8|@$J|V|K|W|L|M]]|9|@]|A|$]]|$1|N|3|O|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|P|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|Q|$]]

Even though this is not the simplest way, you could do this:

<pre><code>var addressString = "~john smith~123 Street~Apt 4~New York~NY~12345~",
 keys = "name address1 address2 city state zipcode".split(" "),
 address = {};

// clean up the string with the first replace
// "abuse" the second replace to map the keys to the matches
addressString.replace(/^~|~$/g).replace(/[^~]+/g, function(match){
 address[ keys.unshift() ] = match;
});

// address will contain the mapped result
address = {
 address1: "123 Street"
 address2: "Apt 4"
 city: "New York"
 name: "john smith"
 state: "NY"
 zipcode: "12345"
}
</code></pre>

<hr>

Update for ES2015, using destructuring

<pre><code>const [address1, address2, city, name, state, zipcode] = addressString.match(/[^~]+/g);

// The variables defined above now contain the appropriate information:

console.log(address1, address2, city, name, state, zipcode);
// -&gt; john smith 123 Street Apt 4 New York NY 12345
</code></pre>

blocks|key|5254318|text|您需要研究一下JavaScript的substr或split，因为这并不是一个真正适合jQuery的任务。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5254319|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/substr|1|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split^0|I|6|0|P|5|1|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]|$A|R|B|S|1|T]]|C|$]]|$1|D|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]|L|$5|G|H|I|C|$J|M]]]]

You'll want to look into JavaScript's <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/substr" rel="nofollow noreferrer">substr</a> or <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split" rel="nofollow noreferrer">split</a>, as this is not really a task suited for jQuery.

blocks|key|2999812|text|如果发现拆分器为，则仅|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2999813|它会拆分它|2999814|否则返回相同字符串的|2999815|2999816|函数名称(ResultStr+){+if+(ResultStr+!=+null)+{+var+SplitChars+=+'~'；if+(ResultStr.indexOf(SplitChars)+>=+0)+{+var+DtlStr+=+ResultStr.split(SplitChars)；var+name+=+DtlStr；var+street+=+DtlStr1；}|blockquote|2999817|2999818|entityMap^0|4|4|0|0|0|0|0|57|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|T|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|U|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|V|8|@]|D|@]|E|$]]|$1|K|3|L|5|M|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|N|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|P|$]]

If Spliter is found then only
it will Split it
else return the same string
<blockquote>
<pre><code>function SplitTheString(ResultStr) {
 if (ResultStr != null) {
 var SplitChars = '~';
 if (ResultStr.indexOf(SplitChars) &gt;= 0) {
 var DtlStr = ResultStr.split(SplitChars);
 var name = DtlStr[0];
 var street = DtlStr[1];
 }
 }
}
</code></pre>
</blockquote>

blocks|key|5254396|text|嗯，最简单的方法是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5254397|var+address+=+theEncodedString.split(/~/)
var+name+=+address[0],+street+=+address[1]|code-block|syntax|javascript|5254398|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

well, easiest way would be something like:

<pre><code>var address = theEncodedString.split(/~/)
var name = address[0], street = address[1]
</code></pre>

blocks|key|3844108|text|您可以使用split拆分文本。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3844109|作为另一种选择，您也可以使用match，如下所示|3844110|​|3844111|var+str+=+'john+smith~123+Street~Apt+4~New+York~NY~12345';
matches+=+str.match(/[%5E~]%2B/g);

console.log(matches);
document.write(matches);|code-block|syntax|javascript|3844112|3844113|正则表达式[%5E~]%2B将匹配除~之外的所有字符，并以数组形式返回匹配项。然后，您可以从中提取匹配项。|3844114|entityMap^0|5|5|0|E|5|0|0|0|0|5|5|E|1|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|Z|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|10|8|@]|D|@]|E|$M|N]]|$1|O|3|I|5|6|7|11|8|@]|D|@]|E|$]]|$1|P|3|Q|5|6|7|12|8|@$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@]|E|$]]|$1|R|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|S|$]]

You can use <code>split</code> to split the text.

As an alternative, you can also use <code>match</code> as follow

<div class="snippet" data-lang="js" data-hide="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var str = 'john smith~123 Street~Apt 4~New York~NY~12345';
matches = str.match(/[^~]+/g);

console.log(matches);
document.write(matches);</code></pre>
</div>
</div>


The regex <code>[^~]+</code> will match all the characters except <code>~</code> and return the matches in an array. You can then extract the matches from it.

blocks|key|756104|text|类似于：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|756105|var+divided+=+str.split("/~/");
var+name=divided[0];
var+street+=+divided[1];|code-block|syntax|javascript|756106|可能是最简单的|756107|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Something like:

<pre><code>var divided = str.split("/~/");
var name=divided[0];
var street = divided[1];
</code></pre>

Is probably going to be easiest

blocks|key|3844068|text|扎克的这一点是对的..使用他的方法，您还可以创建一个看似“多维”的数组。我在JSFiddle+http://jsfiddle.net/LcnvJ/2/创建了一个快速示例|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3844069|//+array[0][0]+will+produce+brian
//+array[0][1]+will+produce+james

//+array[1][0]+will+produce+kevin
//+array[1][1]+will+produce+haley

var+array+=+[];
++++array[0]+=+"brian,james,doug".split(",");
++++array[1]+=+"kevin,haley,steph".split(",");|code-block|syntax|javascript|3844070|entityMap|0|LINK|mutability|MUTABLE|url|http://jsfiddle.net/LcnvJ/2/^0|1B|S|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Zach had this one right.. using his method you could also make a seemingly "multi-dimensional" array.. I created a quick example at JSFiddle <a href="http://jsfiddle.net/LcnvJ/2/" rel="nofollow">http://jsfiddle.net/LcnvJ/2/</a>

<pre><code>// array[0][0] will produce brian
// array[0][1] will produce james

// array[1][0] will produce kevin
// array[1][1] will produce haley

var array = [];
 array[0] = "brian,james,doug".split(",");
 array[1] = "kevin,haley,steph".split(",");
</code></pre>

blocks|key|3844264|text|这个string.split("~")[0];可以把事情做好。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3844265|来源：String.prototype.split()|3844266|3844267|使用curry和函数组合的另一种函数方法。|BOLD|3844268|所以第一件事就是拆分函数。我们希望将此"john+smith~123+Street~Apt+4~New+York~NY~12345"添加到此["john+smith",+"123+Street",+"Apt+4",+"New+York",+"NY",+"12345"]中|3844269|const+split+=+(separator)+=>+(text)+=>+text.split(separator);
const+splitByTilde+=+split('~');|code-block|syntax|javascript|3844270|所以现在我们可以使用专门的splitByTilde函数了。示例：|3844271|splitByTilde("john+smith~123+Street~Apt+4~New+York~NY~12345")+//+["john+smith",+"123+Street",+"Apt+4",+"New+York",+"NY",+"12345"]|3844272|要获得第一个元素，我们可以使用list[0]运算符。让我们构建一个first函数：|3844273|const+first+=+(list)+=>+list[0];|3844274|算法是:用冒号拆分，然后得到给定列表的第一个元素。因此，我们可以组合这些函数来构建最终的getName函数。使用reduce构建compose函数|3844275|const+compose+=+(...fns)+=>+(value)+=>+fns.reduceRight((acc,+fn)+=>+fn(acc),+value);|3844276|现在使用它来组合splitByTilde和first函数。|3844277|const+getName+=+compose(first,+splitByTilde);

let+string+=+'john+smith~123+Street~Apt+4~New+York~NY~12345';
getName(string);+//+"john+smith"|3844278|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split^0|2|L|0|3|O|0|0|0|0|L|0|J|1B|1Y|1S|0|0|D|C|0|0|F|7|X|5|0|0|18|7|1K|6|1S|7|0|0|8|C|L|5|0|0^^$0|@$1|2|3|4|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1J|8|@]|D|@$9|1K|A|1L|1|1M]]|E|$]]|$1|H|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]|$1|I|3|J|5|6|7|1O|8|@$9|1P|A|1Q|B|K]]|D|@]|E|$]]|$1|L|3|M|5|6|7|1R|8|@$9|1S|A|1T|B|C]|$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|N|3|O|5|P|7|1W|8|@]|D|@]|E|$Q|R]]|$1|S|3|T|5|6|7|1X|8|@$9|1Y|A|1Z|B|C]]|D|@]|E|$]]|$1|U|3|V|5|P|7|20|8|@]|D|@]|E|$Q|R]]|$1|W|3|X|5|6|7|21|8|@$9|22|A|23|B|C]|$9|24|A|25|B|C]]|D|@]|E|$]]|$1|Y|3|Z|5|P|7|26|8|@]|D|@]|E|$Q|R]]|$1|10|3|11|5|6|7|27|8|@$9|28|A|29|B|C]|$9|2A|A|2B|B|C]|$9|2C|A|2D|B|C]]|D|@]|E|$]]|$1|12|3|13|5|P|7|2E|8|@]|D|@]|E|$Q|R]]|$1|14|3|15|5|6|7|2F|8|@$9|2G|A|2H|B|C]|$9|2I|A|2J|B|C]]|D|@]|E|$]]|$1|16|3|17|5|P|7|2K|8|@]|D|@]|E|$Q|R]]|$1|18|3|-4|5|6|7|2L|8|@]|D|@]|E|$]]]|19|$1A|$5|1B|1C|1D|E|$1E|1F]]]]

This <code>string.split("~")[0];</code> gets things done.

source: <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split" rel="nofollow noreferrer">String.prototype.split()</a>

<hr>

Another functional approach using curry and function composition.

So the first thing would be the split function. We want to make this <code>"john smith~123 Street~Apt 4~New York~NY~12345"</code> into this <code>["john smith", "123 Street", "Apt 4", "New York", "NY", "12345"]</code>

<pre><code>const split = (separator) =&gt; (text) =&gt; text.split(separator);
const splitByTilde = split('~');
</code></pre>

So now we can use our specialized <code>splitByTilde</code> function. Example:

<pre><code>splitByTilde("john smith~123 Street~Apt 4~New York~NY~12345") // ["john smith", "123 Street", "Apt 4", "New York", "NY", "12345"]
</code></pre>

To get the first element we can use the <code>list[0]</code> operator. Let's build a <code>first</code> function:

<pre><code>const first = (list) =&gt; list[0];
</code></pre>

The algorithm is: split by the colon and then get the first element of the given list. So we can compose those functions to build our final <code>getName</code> function. Building a <code>compose</code> function with <code>reduce</code>:

<pre><code>const compose = (...fns) =&gt; (value) =&gt; fns.reduceRight((acc, fn) =&gt; fn(acc), value);
</code></pre>

And now using it to compose <code>splitByTilde</code> and <code>first</code> functions.

<pre><code>const getName = compose(first, splitByTilde);

let string = 'john smith~123 Street~Apt 4~New York~NY~12345';
getName(string); // "john smith"
</code></pre>

blocks|key|753143|text|在纯Javascript中尝试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|753144|+//basic+url=http://localhost:58227/ExternalApproval.html?Status=1

+var+ar=+[url,statu]+=+window.location.href.split("=");|code-block|syntax|javascript|753145|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<h1>Try in Plain Javascript</h1>
<pre><code> //basic url=http://localhost:58227/ExternalApproval.html?Status=1

 var ar= [url,statu] = window.location.href.split(&quot;=&quot;);
</code></pre>

blocks|key|3844435|text|JavaScript:将字符串转换为数组JavaScript拆分|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3844436|​|3844437|++++var+str+=+"This-javascript-tutorial-string-split-method-examples-tutsmake."
+
++++var+result+=+str.split('-');+
+++++
++++console.log(result);
+++++
++++document.getElementById("show").innerHTML+=+result;+|code-block|syntax|javascript|3844438|<html>
<head>
<title>How+do+you+split+a+string,+breaking+at+a+particular+character+in+javascript?</title>
</head>
<body>
+
<p+id="show">+
+
</body>
</html>|3844439|3844440|https://www.tutsmake.com/javascript-convert-string-to-array-javascript/|offset|length|3844441|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|0|0|0|0|1Z|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|F|7|Z|8|@]|9|@]|A|$G|H]]|$1|K|3|C|5|6|7|10|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|11|8|@]|9|@$N|12|O|13|1|14]]|A|$]]|$1|P|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|Q|$R|$5|S|T|U|A|$V|M]]]]

JavaScript: Convert String to Array JavaScript Split

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code> var str = "This-javascript-tutorial-string-split-method-examples-tutsmake."
 
 var result = str.split('-'); 
 
 console.log(result);
 
 document.getElementById("show").innerHTML = result; </code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;html&gt;
&lt;head&gt;
&lt;title&gt;How do you split a string, breaking at a particular character in javascript?&lt;/title&gt;
&lt;/head&gt;
&lt;body&gt;
 
&lt;p id="show"&gt;&lt;/p&gt; 
 
&lt;/body&gt;
&lt;/html&gt;</code></pre>
</div>
</div>


<a href="https://www.tutsmake.com/javascript-convert-string-to-array-javascript/" rel="nofollow noreferrer">https://www.tutsmake.com/javascript-convert-string-to-array-javascript/</a>

blocks|key|3844331|text|由于逗号问题上的拆分与此问题重复，因此在此处添加此内容。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3844332|如果您想拆分一个字符，并处理该字符后面可能出现的额外空格，那么可以使用replace，然后使用split，如下所示：|offset|length|style|CODE|3844333|var+items+=+string.replace(/,\s%2B/,+",").split(',')|code-block|syntax|javascript|3844334|entityMap^0|0|Z|7|1B|5|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]|$D|S|E|T|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|U|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

Since the splitting on commas question is duplicated to this question, adding this here.

If you want to split on a character and also handle extra whitespace that might follow that character, which often happens with commas, you can use <code>replace</code> then <code>split</code>, like this:

<pre><code>var items = string.replace(/,\s+/, ",").split(',')
</code></pre>

blocks|key|3000397|text|JavaScript中的split()方法用于将字符串转换为数组。它需要一个可选参数，作为要拆分的字符。在您的情况下(~)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3000398|如果跳过splitOn，它将简单地将字符串放在数组的第0位。|3000399|如果splitOn只是一个“”，那么它将转换单个字符的数组。|3000400|所以在你的例子中：|3000401|var+arr+=+input.split('~');|code-block|syntax|javascript|3000402|将在arr[0]得到名字，在arr[1]得到街道。|3000403|你可以在Split+on+in+JavaScript上阅读更详细的解释|3000404|entityMap|0|LINK|mutability|MUTABLE|url|https://codetopology.com/scripts/javascript-tutorials/javascript-string-methods/#splitsplitOn^0|C|7|0|0|0|0|0|2|6|E|6|0|4|M|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|15|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|16|8|@]|D|@]|E|$]]|$1|J|3|K|5|6|7|17|8|@]|D|@]|E|$]]|$1|L|3|M|5|N|7|18|8|@]|D|@]|E|$O|P]]|$1|Q|3|R|5|6|7|19|8|@$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|S|3|T|5|6|7|1E|8|@]|D|@$9|1F|A|1G|1|1H]]|E|$]]|$1|U|3|-4|5|6|7|1I|8|@]|D|@]|E|$]]]|V|$W|$5|X|Y|Z|E|$10|11]]]]

<code>split()</code> method in JavaScript is used to convert a string to an array.
It takes one optional argument, as a character, on which to split. In your case (~).
If splitOn is skipped, it will simply put string as it is on 0th position of an array.
If splitOn is just a “”, then it will convert array of single characters.
So in your case:
<pre><code>var arr = input.split('~');
</code></pre>
will get the name at <code>arr[0]</code> and the street at <code>arr[1]</code>.
You can read for a more detailed explanation at
<a href="https://codetopology.com/scripts/javascript-tutorials/javascript-string-methods/#splitsplitOn" rel="nofollow noreferrer">Split on in JavaScript</a>

blocks|key|3000463|text|这不像解构的答案那么好，但鉴于这个问题是12年前提出的，我决定给它一个12年前也会起作用的答案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3000464|function+Record(s)+{
++++var+keys+=+["name",+"address",+"address2",+"city",+"state",+"zip"],+values+=+s.split("~"),+i
++++for+(i+=+0;+i<keys.length;+i%2B%2B)+{
++++++++this[keys[i]]+=+values[i]
++++}
}

var+record+=+new+Record('john+smith~123+Street~Apt+4~New+York~NY~12345')

record.name+//+contains+john+smith
record.address+//+contains+123+Street
record.address2+//+contains+Apt+4
record.city+//+contains+New+York
record.state+//+contains+NY
record.zip+//+contains+zip|code-block|syntax|javascript|3000465|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This isn't as good as the destructuring answer, but seeing as this question was asked 12 years ago, I decided to give it an answer that also would have worked 12 years ago.
<pre><code>function Record(s) {
 var keys = [&quot;name&quot;, &quot;address&quot;, &quot;address2&quot;, &quot;city&quot;, &quot;state&quot;, &quot;zip&quot;], values = s.split(&quot;~&quot;), i
 for (i = 0; i&lt;keys.length; i++) {
 this[keys[i]] = values[i]
 }
}

var record = new Record('john smith~123 Street~Apt 4~New York~NY~12345')

record.name // contains john smith
record.address // contains 123 Street
record.address2 // contains Apt 4
record.city // contains New York
record.state // contains NY
record.zip // contains zip
</code></pre>

blocks|key|753071|text|使用这个代码--|type|unstyled|depth|inlineStyleRanges|entityRanges|data|753072|function+myFunction()+{
var+str+=+"How+are+you+doing+today?";
var+res+=+str.split("/");

}|code-block|syntax|javascript|753073|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use this code --

<pre><code>function myFunction() {
var str = "How are you doing today?";
var res = str.split("/");

}
</code></pre>

I have this string

<pre><code>'john smith~123 Street~Apt 4~New York~NY~12345'
</code></pre>

Using JavaScript, what is the fastest way to parse this into

<pre><code>var name = "john smith";
var street= "123 Street";
//etc...
</code></pre>

How do I split a string, breaking at a particular character?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有这个字符串'john smith~123 Street~Apt 4~New York~NY~12345'使用JavaScript，最快的解析方法是什么？var name = "john smith";var street= "123 Street";//etc...

问如何拆分字符串，在特定字符处断开？
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问如何拆分字符串，在特定字符处断开？
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