blocks|key|133320|text|通常：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|133321|/([%5E/]*)$|code-block|syntax|javascript|133322|然后，您需要的数据将是第一组的匹配项。|133323|133324|PHP编辑：既然你使用的是PHP，你也可以使用strrchr，它返回从字符串中最后一个字符到最后一个字符的所有内容。或者您可以使用strrpos和substr的组合，首先找到最后一个出现的位置，然后获得从该位置到结尾的子字符串。或者explode和array_pop，在/处拆分字符串，只得到最后一部分。|offset|length|style|CODE|133325|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.php.net/strrchr|1|http://docs.php.net/strrpos|2|http://docs.php.net/substr|3|http://docs.php.net/explode|4|http://docs.php.net/array_pop^0|0|0|0|0|N|7|1T|7|21|6|38|7|3G|9|3R|1|N|7|0|1T|7|1|21|6|2|38|7|3|3G|9|4|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|17|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|18|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|19|8|@$L|1A|M|1B|N|O]|$L|1C|M|1D|N|O]|$L|1E|M|1F|N|O]|$L|1G|M|1H|N|O]|$L|1I|M|1J|N|O]|$L|1K|M|1L|N|O]]|9|@$L|1M|M|1N|1|1O]|$L|1P|M|1Q|1|1R]|$L|1S|M|1T|1|1U]|$L|1V|M|1W|1|1X]|$L|1Y|M|1Z|1|20]]|A|$]]|$1|P|3|-4|5|6|7|21|8|@]|9|@]|A|$]]]|Q|$R|$5|S|T|U|A|$V|W]]|X|$5|S|T|U|A|$V|Y]]|Z|$5|S|T|U|A|$V|10]]|11|$5|S|T|U|A|$V|12]]|13|$5|S|T|U|A|$V|14]]]]

Generally:

<pre><code>/([^/]*)$
</code></pre>

The data you want would then be the match of the first group.

<hr>

Edit   Since you’re using PHP, you could also use <a href="http://docs.php.net/strrchr" rel="noreferrer"><code>strrchr</code></a> that’s returning everything from the last occurence of a character in a string up to the end. Or you could use a combination of <a href="http://docs.php.net/strrpos" rel="noreferrer"><code>strrpos</code></a> and <a href="http://docs.php.net/substr" rel="noreferrer"><code>substr</code></a>, first find the position of the last occurence and then get the substring from that position up to the end. Or <a href="http://docs.php.net/explode" rel="noreferrer"><code>explode</code></a> and <a href="http://docs.php.net/array_pop" rel="noreferrer"><code>array_pop</code></a>, split the string at the <code>/</code> and get just the last part.

blocks|key|1142309|text|这个模式不会捕获$0中的最后一个斜杠，如果最后一个斜杠后面没有字符，它也不会匹配任何内容。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1142310|/(?<=\/)([%5E\/]%2B)$/|code-block|syntax|javascript|1142311|编辑:但它需要后视，不支持ECMAScript+(Javascript，Actionscript)，Ruby或a+few+other+flavors。如果您使用的是其中一种风格，则可以使用：|1142312|/\/([%5E\/]%2B)$/|1142313|但它将捕获$0中的最后一个斜杠。|1142314|entityMap|0|LINK|mutability|MUTABLE|url|http://www.regular-expressions.info/refflavors.html^0|8|2|0|0|1J|J|0|0|0|5|2|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|12|8|@]|D|@$9|13|A|14|1|15]]|E|$]]|$1|M|3|N|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|17|8|@$9|18|A|19|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|1A|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]]]

This pattern will not capture the last slash in <code>$0</code>, and it won't match anything if there's no characters after the last slash.

<pre><code>/(?&lt;=\/)([^\/]+)$/
</code></pre>

Edit: but it requires lookbehind, not supported by ECMAScript (Javascript, Actionscript), Ruby or <a href="http://www.regular-expressions.info/refflavors.html" rel="nofollow noreferrer">a few other flavors</a>. If you are using one of those flavors, you can use:

<pre><code>/\/([^\/]+)$/
</code></pre>

But it will capture the last slash in <code>$0</code>.

blocks|key|1142337|text|/%5E.*\/(.*)$/|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1142338|%5E+=行的开始|unstyled|offset|length|style|CODE|1142339|.*\/+=贪婪地匹配到最后一次出现的行/从行的开始|1142340|(.*)+=最后一次出现/之后的所有内容的组|1142341|entityMap^0|0|0|1|0|0|4|0|0|4|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@$G|S|H|T|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@$G|V|H|W|I|J]]|9|@]|A|$]]|$1|M|3|N|5|F|7|X|8|@$G|Y|H|Z|I|J]]|9|@]|A|$]]|$1|O|3|-4|5|F|7|10|8|@]|9|@]|A|$]]]|P|$]]

<pre><code>/^.*\/(.*)$/
</code></pre>

<code>^</code> = start of the row

<code>.*\/</code> = greedy match to last occurance to / from start of the row

<code>(.*)</code> = group of everything that comes after the last occurance of /

blocks|key|1433958|text|这至少匹配字符串末尾的一个(任何不是斜杠)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1433959|[%5E/]%2B$|code-block|syntax|javascript|1433960|备注：|1433961|1433962|无括号，因为它不需要任何组-结果进入组0(匹配本身)。|unordered-list-item|1433963|使用%2B+(而不是*)，因此如果最后一个字符是斜杠，它将无法匹配(而不是匹配空字符串)。|offset|length|style|CODE|1433964|1433965|但是，最可能更快、更简单的解决方案是使用你的语言内置的字符串列表处理功能-即ListLast(+Text+,+'/'+)或等效函数。|1433966|对于PHP，最接近的函数是strrchr，它的工作方式如下：|1433967|strrchr(+Text+,+'/'+)|1433968|这包括结果中的斜杠-根据Teddy下面的评论，您可以使用substr删除斜杠|1433969|substr(+strrchr(+Text,+'/'+),+1+);|1433970|entityMap|0|LINK|mutability|MUTABLE|url|http://www.php.net/manual/en/function.strrchr.php|1|http://www.php.net/manual/en/function.substr.php^0|0|0|0|0|0|2|1|8|1|0|0|12|M|0|D|7|0|0|0|S|6|1|0|0^^$0|@$1|2|3|4|5|6|7|1D|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1E|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1F|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|1G|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|1H|8|@]|9|@]|A|$]]|$1|M|3|N|5|L|7|1I|8|@$O|1J|P|1K|Q|R]|$O|1L|P|1M|Q|R]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1N|8|@]|9|@]|A|$]]|$1|T|3|U|5|6|7|1O|8|@$O|1P|P|1Q|Q|R]]|9|@]|A|$]]|$1|V|3|W|5|6|7|1R|8|@]|9|@$O|1S|P|1T|1|1U]]|A|$]]|$1|X|3|Y|5|D|7|1V|8|@]|9|@]|A|$E|F]]|$1|Z|3|10|5|6|7|1W|8|@]|9|@$O|1X|P|1Y|1|1Z]]|A|$]]|$1|11|3|12|5|D|7|20|8|@]|9|@]|A|$E|F]]|$1|13|3|-4|5|6|7|21|8|@]|9|@]|A|$]]]|14|$15|$5|16|17|18|A|$19|1A]]|1B|$5|16|17|18|A|$19|1C]]]]

This matches at least one of (anything not a slash) followed by end of the string:

<pre><code>[^/]+$
</code></pre>

 
Notes:

<ul>
<li>No parens because it doesn't need any groups - result goes into group 0 (the match itself).</li>
<li>Uses <code>+</code> (instead of <code>*</code>) so that if the last character is a slash it fails to match (rather than matching empty string).</li>
</ul>

 
But, most likely a faster and simpler solution is to use your language's built-in string list processing functionality - i.e. <code>ListLast( Text , '/' )</code> or equivalent function.

For PHP, the closest function is <a href="http://www.php.net/manual/en/function.strrchr.php" rel="noreferrer">strrchr</a> which works like this:

<pre><code>strrchr( Text , '/' )
</code></pre>

This includes the slash in the results - as per Teddy's comment below, you can remove the slash with <a href="http://www.php.net/manual/en/function.substr.php" rel="noreferrer">substr</a>:

<pre><code>substr( strrchr( Text, '/' ), 1 );
</code></pre>

blocks|key|1433983|text|虽然不是PHP程序员，但strrpos似乎是一个更有前途的起点。找到最右边的'/'，所有过去的都是你要找的。不使用正则表达式。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1433984|查找字符串中最后一次出现字符的位置|1433985|entityMap|0|LINK|mutability|MUTABLE|url|http://www.php.net/manual/en/function.strrpos.php^0|C|7|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]]|C|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|C|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]]]

Not a PHP programmer, but <a href="http://www.php.net/manual/en/function.strrpos.php" rel="nofollow noreferrer">strrpos</a> seems a more promising place to start. Find the rightmost '/', and everything past that is what you are looking for. No regex used.

Find position of last occurrence of a char in a string

blocks|key|1142441|text|您还可以使用basename函数获取"filename“或最后一部分。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1142442|<?php
$url+=+'http://spreadsheets.google.com/feeds/spreadsheets/p1f3JYcCu_cb0i0JYuCu123';

echo+basename($url);+//+"p1f3JYcCu_cb0i0JYuCu123"|code-block|syntax|javascript|1142443|在我的邮箱中，我可以只传递完整的URL。您可能需要从前面脱掉http:/。|style|CODE|1142444|Basename和dirname非常适合在任何看起来像unix文件路径的文件中移动。|1142445|entityMap|0|LINK|mutability|MUTABLE|url|http://us3.php.net/basename|1|http://us3.php.net/manual/en/function.dirname.php^0|6|8|0|0|0|U|6|0|9|7|1|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|13|8|@$A|14|B|15|K|L]]|9|@]|C|$]]|$1|M|3|N|5|6|7|16|8|@]|9|@$A|17|B|18|1|19]]|C|$]]|$1|O|3|-4|5|6|7|1A|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]]]

You can also get the "filename", or the last part, with the <a href="http://us3.php.net/basename" rel="noreferrer">basename</a> function.

<pre><code>&lt;?php
$url = 'http://spreadsheets.google.com/feeds/spreadsheets/p1f3JYcCu_cb0i0JYuCu123';

echo basename($url); // "p1f3JYcCu_cb0i0JYuCu123"
</code></pre>

On my box I could just pass the full URL. It's possible you might need to strip off <code>http:/</code> from the front.

Basename and <a href="http://us3.php.net/manual/en/function.dirname.php" rel="noreferrer">dirname</a> are great for moving through anything that looks like a unix filepath.

blocks|key|133449|text|你也可以正常拆分字符串|type|unstyled|depth|inlineStyleRanges|entityRanges|data|133450|$str+=+"http://spreadsheets.google.com/feeds/spreadsheets/p1f3JYcCu_cb0i0JYuCu123";
$s+=+explode("/",$str);
print+end($s);|code-block|syntax|javascript|133451|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can also normal string split

<pre><code>$str = "http://spreadsheets.google.com/feeds/spreadsheets/p1f3JYcCu_cb0i0JYuCu123";
$s = explode("/",$str);
print end($s);
</code></pre>

blocks|key|1435780|text|根据@Mark+Rushakoff的回答，不同情况下的最佳解决方案：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1435781|<?php
$path+=+"http://spreadsheets.google.com/feeds/spreadsheets/p1f3JYcCu_cb0i0JYuCu123?var1&var2#hash";
$vars+=strrchr($path,+"?");+//+?asd=qwe&stuff#hash
var_dump(preg_replace('/'.+preg_quote($vars,+'/')+.+'$/',+'',+basename($path)));+//+test.png
?>|code-block|syntax|javascript|1435782|1435783|Regular+Expression+to+collect+everything+after+the+last+/|ordered-list-item|1435784|How+to+get+file+name+from+full+path+with+PHP?|1435785|1435786|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/users/126042/mark-rushakoff|1|https://stackoverflow.com/questions/1150559/regular-expression-to-collect-everything-after-the-last|2|https://stackoverflow.com/questions/1418193/how-to-get-file-name-from-full-path-with-php^0|3|E|0|0|0|0|0|1L|1|0|0|19|2|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|D|3|E|5|F|7|15|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|16|8|@]|9|@]|C|$]]|$1|J|3|K|5|L|7|17|8|@]|9|@$A|18|B|19|1|1A]]|C|$]]|$1|M|3|N|5|L|7|1B|8|@]|9|@$A|1C|B|1D|1|1E]]|C|$]]|$1|O|3|-4|5|6|7|1F|8|@]|9|@]|C|$]]|$1|P|3|-4|5|6|7|1G|8|@]|9|@]|C|$]]]|Q|$R|$5|S|T|U|C|$V|W]]|X|$5|S|T|U|C|$V|Y]]|Z|$5|S|T|U|C|$V|10]]]]

based on @<a href="https://stackoverflow.com/users/126042/mark-rushakoff">Mark Rushakoff</a>'s answer the best solution for different cases:

<pre><code>&lt;?php
$path = "http://spreadsheets.google.com/feeds/spreadsheets/p1f3JYcCu_cb0i0JYuCu123?var1&amp;var2#hash";
$vars =strrchr($path, "?"); // ?asd=qwe&amp;stuff#hash
var_dump(preg_replace('/'. preg_quote($vars, '/') . '$/', '', basename($path))); // test.png
?&gt;
</code></pre>

<ol>
<li><a href="https://stackoverflow.com/questions/1150559/regular-expression-to-collect-everything-after-the-last">Regular Expression to collect everything after the last /</a></li>
<li><a href="https://stackoverflow.com/questions/1418193/how-to-get-file-name-from-full-path-with-php">How to get file name from full path with PHP?</a></li>
</ol>

I'm new at regular expressions and wonder how to phrase one that collects everything after the last <code>/</code>.

I'm extracting an ID used by Google's GData.

my example string is 



<pre class="lang-none prettyprint-override"><code>http://spreadsheets.google.com/feeds/spreadsheets/p1f3JYcCu_cb0i0JYuCu123
</code></pre>

Where the ID is: <code>p1f3JYcCu_cb0i0JYuCu123</code>

Oh and I'm using PHP.

Regular Expression to collect everything after the last /

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我是正则表达式的新手，不知道如何表达一个收集最后一个/之后的所有内容的正则表达式。我正在提取谷歌GData使用的ID。我的示例字符串是http://spreadsheets.google.com/feeds/spreadsheets/p1f3JYcCu_cb0i0JYuCu123其中ID为：p1f3JYcCu_cb0i...

问正则表达式来收集最后一个/之后的所有内容
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问正则表达式来收集最后一个/之后的所有内容EN