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社区首页 >问答首页 >有没有内置的方法将IEnumerator转换为IEnumerable?

有没有内置的方法将IEnumerator转换为IEnumerable?
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Stack Overflow用户
提问于 2009-06-22 21:57:38
回答 9查看 43.1K关注 0票数 61

有没有内置的方法将IEnumerator<T>转换为IEnumerable<T>

EN

Stack Overflow用户

发布于 2015-03-20 16:43:28

这是我写的一个变种。具体情况略有不同。我想在IEnumerable<T>上执行一个MoveNext(),检查结果,然后将所有内容放入一个“完整”的新IEnumerator<T>中(这样甚至包括了我已经提取的IEnumerable<T>的元素)。

代码语言:javascript
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// Simple IEnumerable<T> that "uses" an IEnumerator<T> that has
// already received a MoveNext(). "eats" the first MoveNext() 
// received, then continues normally. For shortness, both IEnumerable<T>
// and IEnumerator<T> are implemented by the same class. Note that if a
// second call to GetEnumerator() is done, the "real" IEnumerator<T> will
// be returned, not this proxy implementation.
public class EnumerableFromStartedEnumerator<T> : IEnumerable<T>, IEnumerator<T>
{
    public readonly IEnumerator<T> Enumerator;

    public readonly IEnumerable<T> Enumerable;

    // Received by creator. Return value of MoveNext() done by caller
    protected bool FirstMoveNextSuccessful { get; set; }

    // The Enumerator can be "used" only once, then a new enumerator
    // can be requested by Enumerable.GetEnumerator() 
    // (default = false)
    protected bool Used { get; set; }

    // The first MoveNext() has been already done (default = false)
    protected bool DoneMoveNext { get; set; }

    public EnumerableFromStartedEnumerator(IEnumerator<T> enumerator, bool firstMoveNextSuccessful, IEnumerable<T> enumerable)
    {
        Enumerator = enumerator;
        FirstMoveNextSuccessful = firstMoveNextSuccessful;
        Enumerable = enumerable;
    }

    public IEnumerator<T> GetEnumerator()
    {
        if (Used)
        {
            return Enumerable.GetEnumerator();
        }

        Used = true;
        return this;
    }

    IEnumerator IEnumerable.GetEnumerator()
    {
        return GetEnumerator();
    }

    public T Current
    {
        get
        {
            // There are various school of though on what should
            // happens if called before the first MoveNext() or
            // after a MoveNext() returns false. We follow the 
            // "return default(TInner)" school of thought for the
            // before first MoveNext() and the "whatever the 
            // Enumerator wants" for the after a MoveNext() returns
            // false
            if (!DoneMoveNext)
            {
                return default(T);
            }

            return Enumerator.Current;
        }
    }

    public void Dispose()
    {
        Enumerator.Dispose();
    }

    object IEnumerator.Current
    {
        get
        {
            return Current;
        }
    }

    public bool MoveNext()
    {
        if (!DoneMoveNext)
        {
            DoneMoveNext = true;
            return FirstMoveNextSuccessful;
        }

        return Enumerator.MoveNext();
    }

    public void Reset()
    {
        // This will 99% throw :-) Not our problem.
        Enumerator.Reset();

        // So it is improbable we will arrive here
        DoneMoveNext = true;
    }
}

使用:

代码语言:javascript
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var enumerable = someCollection<T>;

var enumerator = enumerable.GetEnumerator();
bool res = enumerator.MoveNext();
// do whatever you want with res/enumerator.Current

var enumerable2 = new EnumerableFromStartedEnumerator<T>(enumerator, res, enumerable);

现在,将通过枚举器enumerator提供将请求给enumerable2的第一个GetEnumerator()。从第二个开始,将使用enumerable.GetEnumerator()

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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/1029612

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