blocks|key|214317|text|027447002是octal格式，因为它以零为前缀。把它转换成十进制，你就会得到6180354！|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|214318|有关详细信息，请参阅manual+page+on+integers。|214319|entityMap|0|LINK|mutability|MUTABLE|url|http://en.wikipedia.org/wiki/Octal|1|http://php.net/manual/en/language.types.integer.php^0|A|5|0|0|A|N|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]|N|$5|I|J|K|C|$L|O]]]]

027447002 is in <a href="http://en.wikipedia.org/wiki/Octal" rel="nofollow noreferrer">octal</a>, as it prefixed with a zero. Convert that to decimal and you get 6180354!

See the <a href="http://php.net/manual/en/language.types.integer.php" rel="nofollow noreferrer">manual page on integers</a> for details.

blocks|key|4517696|text|由于初始零，它被解释为八进制数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4517697|http://www.php.net/manual/en/language.types.integer.php|offset|length|4517698|如果数字在打印时应该用零填充(它们总是一个特定的长度)，那么可以使用sprintf()将存储的整数转换为填充零的字符串。|4517699|entityMap|0|LINK|mutability|MUTABLE|url|1|http://php.net/sprintf^0|0|0|1J|0|0|Y|9|1|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@$D|S|E|T|1|U]]|A|$]]|$1|F|3|G|5|6|7|V|8|@]|9|@$D|W|E|X|1|Y]]|A|$]]|$1|H|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|I|$J|$5|K|L|M|A|$N|C]]|O|$5|K|L|M|A|$N|P]]]]

Because of the initial zero, it is interpreted as an octal number.

<a href="http://www.php.net/manual/en/language.types.integer.php" rel="nofollow noreferrer">http://www.php.net/manual/en/language.types.integer.php</a>

If the number should be left padded with zeros when printed (they are always a specific length) then you can use <a href="http://php.net/sprintf" rel="nofollow noreferrer">sprintf()</a> to convert the stored integer to a zero padded string.

blocks|key|4517760|text|带有前导零的数字文字是以八进制(以8为基数)指定内容的方式。如果你写的是27447002而不是027447002，那就没问题了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4517761|entityMap^0|10|8|1B|9|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

Numeric literals with leading zeroes are how you specify something in octal (base 8). If you write <code>27447002</code> instead of <code>027447002</code> you'll be fine.

blocks|key|214375|text|自动基数转换。您甚至不需要所有的类代码就能看到它的实际效果|type|unstyled|depth|inlineStyleRanges|entityRanges|data|214376|echo+027447002;|code-block|syntax|javascript|214377|问题是，就数字而言，027447002是八进制(以8为基数)-而不是一个以零填充的十进制(以10为基数)整数。|214378|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Automatic base conversion. You don't even need all that class code to see this in action

<pre><code>echo 027447002;
</code></pre>

The thing is that 027447002, in terms of numbers, is octal (base-8) - not a zero-filled decimal (base-10) integer.

blocks|key|4517864|text|删除前导零，因为它使PHP将该数字视为八进制数。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4517865|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Remove the leading zero, because it makes PHP treat the number as an octal number.

blocks|key|4517889|text|正如每个人所说的那样-默认情况下，这被认为是一个八进制值。我认为类构造函数应该测试它是一个有效的整数，并且初始化类应该typecast这个值……|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4517890|function+bank($name,+$id,+$balance=0)
{
++++if+(is_int($id))
++++++$this->ID=$id;
++++else
++++++throw+new+Exception('ID+is+not+integer');

++++//+and+validate+these+too!
++++$this->balance=$balance;
++++$this->name=$name;
}

$b=+new+bank('yaniv',+(int)027447002,+15000);|code-block|syntax|javascript|4517891|希望这能有所帮助！|4517892|entityMap|0|LINK|mutability|MUTABLE|url|http://us3.php.net/manual/en/language.types.type-juggling.php^0|1N|8|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

As everyone rightly said - this is considered an octal value by default. I think the class constructor should be testing that it is a valid integer, and initiating the class should <a href="http://us3.php.net/manual/en/language.types.type-juggling.php" rel="nofollow noreferrer">typecast</a> the value...

<pre><code>function bank($name, $id, $balance=0)
{
 if (is_int($id))
 $this-&gt;ID=$id;
 else
 throw new Exception('ID is not integer');

 // and validate these too!
 $this-&gt;balance=$balance;
 $this-&gt;name=$name;
}

$b= new bank('yaniv', (int)027447002, 15000);
</code></pre>

Hope that helps!

blocks|key|1514325|text|除了每个人都在说的话之外，我还有一个评论。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1514326|看起来你想要一个0填充的数字，对吧？左边用零填充的九位数？|1514327|考虑使用str_pad函数。如下所示：|1514328|...
function+bank($name,+$id,+$bal=0)
{
+...
+$this->id+=+str_pad($id,+9,+'0',+STR_PAD_LEFT);
+...
}
...|code-block|syntax|javascript|1514329|然后在你的函数中，你可以调用：|1514330|$b+=+new+bank('John+Doe',+12345678,+1.25);|1514331|如果您输出id，它将被填充。|1514332|012345678|1514333|entityMap^0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|A|$I|J]]|$1|K|3|L|5|6|7|Y|8|@]|9|@]|A|$]]|$1|M|3|N|5|H|7|Z|8|@]|9|@]|A|$I|J]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|11|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

I have one comment besides what everyone else is saying. 

It appears you want a 0 padded number, right? A nine digit number that's padded with zeros on the left?

Think about using str_pad function. Like so:

<pre><code>...
function bank($name, $id, $bal=0)
{
 ...
 $this-&gt;id = str_pad($id, 9, '0', STR_PAD_LEFT);
 ...
}
...
</code></pre>

Then in your function you can call:

<pre><code>$b = new bank('John Doe', 12345678, 1.25);
</code></pre>

If you output id, it would be padded

012345678

Can some one please tell me why I get odd results rurning the following code?

<pre><code>&lt;?php
class Bank
{
 var $ID;
 var $balance;
 var $name;
 function bank($name,$id,$balance=0)
 {
 $this-&gt;ID=$id;
 $this-&gt;balance=$balance;
 $this-&gt;name=$name;
 }
 function getBalance()
 {
 return $this-&gt;balance;
 }
 function setBalance($bal)
 {
 $this-&gt;balance=$bal;
 }
 function getId()
 {
 return $this-&gt;ID;
 }
 function setId($i)
 {
 $this-&gt;ID=$i;
 }
)
$b= new bank(yaniv,027447002, 15000);
</code></pre>

Now when I try to echo:

<pre><code>$b-&gt;ID 
</code></pre>

Instead of the expected 027447002 I get an odd 6180354,
but if I initiate the object like this :

<pre><code>$b=new bank(yaniv,'027447002',15000);
</code></pre>

(notice I quoted the id property) it works OK.
Any suggestion why is this happening and what is the right way to fix it?

strange behaviour on php

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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有人能告诉我为什么运行下面的代码会得到奇怪的结果吗？<?phpclass Bank{ var $ID; var $balance; var $name; function bank($name,$id,$balance=0) { $this->ID=$id; $...

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